How do i include and overloading function inside an overload function [closed] - c++

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Here is mine Full code. Am trying to Include inpatient if the case is one(1) but some highlight show that is wrong. is there anyhow to fix this if not can you please tell me another way to do it as long as it include inpatient if one(1) is Entered
void selection(int &);
void processor(int &);
void inPatient(double &, double &, double &, double &);
int main()
{
int selected, include;
double numberOfDays, dailyRate, chargesForHospital, hospitalMedicationCharge;
selection(selected);
validate(selected, selected);
processor(selected);
system("pause");
return(0);
}
void selection(int & selectedOption)
{
cout << "\nEnter Selection: ";
cin >> selectedOption;
}
void processor(int & selectedOption)
{
switch(selectedOption)
{
case 1:
inPatient(umberOfDays, dailyRate, chargesForHospital, hospitalMedicationCharge);
break;
case 2:
cout << "out-Pat" << endl;
break;
default :
cout << "Nothing Selected" << endl;
break;
}
}
void inPatient(double & numberOfDays, double & dailyRate, double & chargesForHospital, double & hospitalMedicationCharge)
{
cout << "The number of days spent in the hospital: ";
cin >> numberOfDays;
cout << "The daily rate: ";
cin >> dailyRate;
cout << "Charges for hospital services (lab tests, etc.): ";
cin >> chargesForHospital;
cout << "Hospital medication charges: ";
cin >> hospitalMedicationCharge;
}

Answer 1

There are a number of errors in the code that you posted, but I'll try to address your immediate problem. You're trying to call a function like this:
patric(int & gender, int & age)
but that's more like a function declaration. To actually call the function, you pass in arguments but omit the type, like this:
patric(someGender, someAge);
The int & in the declaration says that the parameters are references to values of type int, so the values you pass when you call patric should be of type int.
Also, you say that patric is overloaded. That means that there are several versions of the function, each with different parameter lists. So, maybe there's the one above as well as one that doesn't take any values -- maybe their declarations look like this, respectively:
void patric(int &gender, int &age);
void patric(void);
Given that, if you wanted to call the second version, you'd just call it:
patric();
(The void in the parameter list in the second version means that the function doesn't take any parameters. The void before the function name means that it doesn't return anything.)
Note also that you need a semicolon (;) following the function call.