C++ compile time counter in macros - c++

Question

I am trying to achieve the following but in a way that follows the c++ standard :
#include <iostream>
using namespace std;
#define MAKE_BOTH(MAKE_FUNC) \
MAKE_FUNC(FIRST) \
MAKE_FUNC(SECOND) \
MAKE_FUNC(THIRD) \
MAKE_FUNC(FOURTH)
#define MAKE_STRINGS(NAME) #NAME,
const char* genericString[] {
MAKE_BOTH(MAKE_STRINGS)
};
#define MAKE_ENUM(NAME) NAME = (1L << __COUNTER__),
enum genericEnum {
MAKE_BOTH(MAKE_ENUM)
};
int main()
{
cout << FIRST << endl;
cout << SECOND << endl;
cout << THIRD << endl;
cout << FOURTH << endl;
}
If you think a while about this code, this creates both, enums and array of "strings" which consists of the same names as enums. The examle code expands to :
const char* genericString[] {
"FIRST",
"SECOND",
"THIRD",
"FOURTH"
};
enum genericEnum {
FIRST = 1L << 0; (1)
SECOND = 1L << 1; (2)
THIRD = 1L << 2; (4)
FOURTH = 1L << 3; (8)
};
Basically the enums are assigned power of 2 values, the question is - is there a relatively simple way of achieving the same thing without using COUNTER ?
The problem is similar to this one:
Counting preprocessor macros
but I have to increase the value of counter each time the macro is used at compile time, I could not figure out how to do it without using the non-standard COUNTER macro.
Please beware the c++ 11 is not an option, but using boost is, I tried the boost approach as well but it is not possible to call the #include directive by a macro which unables me from incrementing the boost preprocessor counter.

Answer 1

You may generate something like this:
enum genericEnum
{
MY_ENUM_BASE=0,
FIRST,
PAST_FIRST= (FIRST<<1)-1,
SECOND,
PAST_SECOND= (SECOND<<1)-1,
THIRD,
PAST_THIRD= (THIRD<<1)-1,
FOURTH,
PAST_FOURTH= (FOURTH<<1)-1,
};
using standard macroprocessor without using COUNTER,
i.e. defining MAKE_ENUM as
#define MAKE_ENUM(NAME) NAME, PAST##_NAME= (NAME<<1)-1,