Premake not working with g++ on Linux? - c++

Question

Premake Version: 4.3 (downloaded here)
When running make on Linux, I get the following error: "g++: x86_64: No such file or directory." Upon removing the $(ARCH) from CFLAGS, make works fine.
Red Hat:
System Version ("cat /etc/redhat-release"): Red Hat Enterprise Linux Server release 6.5 (Santiago)
Kernel Version ("uname -r"): 2.6.32-431.11.2.el6.x86_64
"uname -p": x86_64
"uname -m": x86_64
C++ compiler: g++
Ubuntu:
System Version ("cat /etc/issue"): Ubuntu 12.04.5 LTS
Kernel Version ("uname -r"): 3.2.0-67-generic
"uname -p": x86_64
"uname -m": x86_64
C++ compiler: g++
I've also run the same program successfully on Mac.
Mac:
System Version: OS X 10.10 (14A389)
Kernel Version: Darwin 14.0.0
"uname -p": i386
"uname -m": x86_64
C++ compiler: clang
premake4.lua
solution "Hello"
configurations { "Debug", "Release" }
configuration { "Debug" }
defines { "_DEBUG", "DEBUG" }
flags { "Symbols", "ExtraWarnings" }
configuration { "Release" }
defines { "NDEBUG" }
flags { "Optimize" }
project "hello"
kind "ConsoleApp"
language "C++"
location "."
files { "hello.cpp" }
hello.cpp is the standard hello world program.
Is there a reason for the $(ARCH)? From looking at the documentation for both clang and g++, it does not seem like providing just the architecture type without a flag is a compiler option. Am I missing something?

Answer 1

That $(ARCH) variable has been in the generated makefiles for quite some time, but it appears it has outlived its usefulness. I have removed it for now; if there is still a need to inject flags into the build we can find a safer name.
You can get a fixed version from the Premake 4.x BitBucket repository.