Hi I know that we can validate Min and Max Length of a number using Regex.
But can we validate Min and Max Value for a floating point number using the same?
Min Value : 0.00
Max Value :100,000,000.00
Could anyone please just apply Min and Max Value to following Regex:
^(?=.*\d)(?!.*?\.[^.\n]*,)\d*(,\d*,?)*(\.\d*)?$
Above Regex matches a floating number with optional decimal point and commas.
Regex is for strings. You try to compare floats. It's just not the right tool. It's worse than eating your soup with a fork. It's like writing on paper with a knife or cutting your hair with a teaspoon.
Look here for a solution with positive integers without thousands separator :
Using regular expressions to compare numbers
I leave the task to you to extend that solution to using floats, thousands separator and negative numbers.
I guess this should help you. This regex will match 0.00 to 100,000,000.00 upto 2 decimal places.
^(:?(?=[1])(10{0,8})|(?=[^0])(\d{1,8})|0)\.[0-9]{1,2}$
But keep in mind that its always best to compare numbers numerically that using regex.
Here is the link to verify it.
Related
I have a range of values and I want to count the decimal points of all values in the range and display the max count. the formula should exclude the zeroes at the end(not count ending zeroes in the decimal points).
for example, in the above sample, in the whole range the max of count of decimal places is 4 excluding the ending zeroes. so the answer is 4 to be displayed in cell D2
I tried doing regex, but do not know how do I do it for a whole range of values.
Please help!
try:
=INDEX(MAX(LEN(IFERROR(REGEXEXTRACT(TO_TEXT(A2:C4), "(\..+)")*1))-2))
Player0's solution is a good start, but uses TO_TEXT which seems to rely on the formatting of your cells.
If you want to safely compute the number of decimal places, use the TEXT function instead.
TEXT(number, format) requires a format whose max. number of decimal places has to be specified. There is no way around this, because formulas like =1/3 can have infinitely many decimal places.
Therefore, first decide on the max, precision for your use-case (here we use 8). Then use below function which works independently from your document's formatting and language:
=INDEX(MAX(
LEN(REGEXEXTRACT(
TEXT(ABS(A2:C4); "."&REPT("#";8));
"[,.].*$"
))-1
))
We subtract -1 since LEN(REGEXEXTRACT()) also counts the decimal separator (. for english, , for many others) .
Everything after the 8th decimal place is ignored. If all your numbers are something like 123.00000000987 the computed max. is 0. If you prefer it to be 8 instead, then add ROUNDUP( ; 8):
=INDEX(MAX(
LEN(REGEXEXTRACT(
TEXT(ROUNDUP(ABS(A2:C4);8); "."&REPT("#";8));
"[,.].*$"
))-1
))
I am fairly new to RegEx and have had a search around online but am unable to find a regex that fits my requirements.
The ultimate aim is to search a string of text and extract the lowest monetary amount, however as the string may contain more than one £amount, then i'm happy for a regex to just extract all monetary values it can find and then I can write a calculation in order to return the lowest amount.
The string may have numbers that are not monetary values / numerous amounts, therefore the regex should always look for a £ symbol first OR it could end with a "p" or "P" to signify pence. For example "I need 2 of these at £10 each and one of those at 50p" - should return 10.00 & 0.50 - I can then calculate that 0.50 is the lowest amount.
As people also write their amounts in various ways, I need the regex to be able to spot different patterns - including the "," for every thousand. All below values should be valid:
£0
£0.00
£0.00p
£0000
£0000.00
£0000.00p
£0,000
£0,000.00
£0,000.00p
0p
Hopefully someone may be able to advise the best way to approach this.
Thanks
This works on your data set:
(?=^£|.*p$)£?\d*(?:,\d{3})*(\.\d{2})?p?
But it may improperly match some edge cases as well because everything is optional...
https://regex101.com/r/WptUn6/3
My current regex is : ^[0-9]{1,2}([,.][0-9]{1,2})?$ which allows for numeric values up to 99. I am not the greatest with regex and was wondering could someone help me to adjust this to include numbers in the hundreds, example, 100.
Edit: Its for money values.
For example I want to be able to withdraw money values, for example, 100:99, not 100:100.
It cannot be negative, and my program already prevents values less than 1 being entered.
Thanks
You can use this regex for 0..100 range (both inclusive):
^([0-9]{1,2}|100)$
OR for your example:
^([0-9]{1,2}|100)([,.][0-9]{1,2})?$
This should do: ^[0-9]{1,3}([,.][0-9]{1,3})?$
((^(100)([.][0]+)?$)|(^[0-9]{1,2}([.][0-9]+)?$))
This regular expression is for 0.0000.... to 100.000000....
What regular expression do I use to extract, for example, 1.09487 from the following text contained in a .txt file? Also, how would I modify the regular expression to account for the case where the float is negative (for example, -1.948)?
I tried several suggestions on Google as well as a regular expression generator, but none seem to work. It seems I want to use an anchor (such as ^) to start searching for digits at the word "serial" and then stop at "(", but this doesn't seem to work.
Output in .txt file:
Entropy = 7.980627 bits per character.
Optimum compression would reduce the size
of this 51768 character file by 0 percent.
Chi square distribution for 51768 samples is 1542.26, and randomly
would exceed this value less than 0.01 percent of the times.
Arithmetic mean value of data bytes is 125.93 (127.5 = random).
Monte Carlo value for Pi is 3.169834647 (error 0.90 percent).
Serial correlation coefficient is 1.09487 (totally uncorrelated = 0.0).
Thanks for any help.
This should be sufficient:
(?<=Serial correlation coefficient is )[-\d.]+
Unless you're expecting garbage, this will work fine.
try this:
(-?\d+\.\d+)(?=\s\(totally)
check here
I am currently trying to validate UK telephone numbers:
The format I'm looking for is: 01234 567891 or 01234567891 - So I need the number to have 5 numbers then a space then 6 numbers or simply a 11 numbers.
The number must start with a 0.
I've had a look at a couple of examples:
/^[0-9]{10,11} - to check that the chars are all numbers
/^0[0-9]{9,10}$/ - to check that the first number is a 0
I'm just unsure how to put all these together and check if there is a space or not.
Could someone help me with this regex?
Thanks
Try this regex:
/^0\d{4}\s?\d{6}$/
Many people try to do input validation and formatting in a single step.
It is better to separate these processes.
Match UK telephone number in any format
^(?:(?:\(?(?:0(?:0|11)\)?[\s-]?\(?|\+)44\)?[\s-]?(?:\(?0\)?[\s-]?)?)|(?:\(?0))(?:(?:\d{5}\)?[\s-]?\d{4,5})|(?:\d{4}\)?[\s-]?(?:\d{5}|\d{3}[\s-]?\d{3}))|(?:\d{3}\)?[\s-]?\d{3}[\s-]?\d{3,4})|(?:\d{2}\)?[\s-]?\d{4}[\s-]?\d{4}))(?:[\s-]?(?:x|ext\.?|\#)\d{3,4})?$
The above pattern allows the user to enter the number in any format they are comfortable with. Don't constrain the user into entering specific formats.
Extract NSN, prefix and extension
^(\(?(?:0(?:0|11)\)?[\s-]?\(?|\+)(44)\)?[\s-]?)?\(?0?(?:\)[\s-]?)?([1-9]\d{1,4}\)?[\d[\s-]]+)((?:x|ext\.?|\#)\d{3,4})?$
Next, extract the various elements.
$2 will be '44' if international format was used, otherwise assume national format with leading '0'.
$4 contains the extension number if present.
$3 contains the NSN part.
Validation and formatting
Use further RegEx patterns to check the NSN has the right number of digits for this number range. Finally, store the number in E.164 format or display it in E.123 format.
There's a very detailed list of validation and display formatting RegEx patterns for UK numbers at:
http://www.aa-asterisk.org.uk/index.php/Regular_Expressions_for_Validating_and_Formatting_UK_Telephone_Numbers
It's too long to reproduce here and it would be difficult to maintain multiple copies of this document.
If you are looking for all UK numbers, I'd look for a bit more than just that number, some are in the format 020 7123 4567 etc.
^\s*\(?(020[7,8]{1}\)?[ ]?[1-9]{1}[0-9{2}[ ]?[0-9]{4})|(0[1-8]{1}[0-9]{3}\)?[ ]?[1-9]{1}[0-9]{2}[ ]?[0-9]{3})\s*$
/\d*(*)*+*-*/
Simple Telephone Regex includes + () and - anywhere, as well as digits
I think ^0[\d]{4}\s?[\d]{5,6}} will work for you. I have used [\d] instead of [0-9].
I find that RegExr is a useful online tool to check and try your regular expressions. It also has a nice library of examples to help point you in the right direction
you should just count the number of digits and check that it's 10,
Some UK numbers have only 9 digits, not 10 (not including the leading 0).
These include 40 of the 01 area codes (using "4+5" format), the 016977 area code (using "5+4" format), all 0500 numbers and some 0800 numbers.
There's a list at: http://www.aa-asterisk.org.uk/index.php/01_numbers
This US numbers pattern accepts following phones as well:
800-432-4500, Opt: 9, Ext: 100316
800-432-4500, Opt: 9, Ext: X100316
800-432-4500, Option #3
(?:(?:\+?1\s*(?:[.-]\s*)?)?(?:\(\s*([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9])\s*\)|([2-9]1[02-9]|[2-9][02-8]1|[2-9][02-8][02-9]))\s*(?:[.-]\s*)?)?([2-9]1[02-9]|[2-9][02-9]1|[2-9][02-9]{2})\s*(?:[.-]\s*)?([0-9]{4}),?(?:\s*(?:#|x\.?|opt(\.|:|\.:)?|option)\s*#?(\d+))?,?(?:\s*(?:#|x\.?|ext(\.|:|\.:)?|extension)\s*(\d+))?
(used this answer in other topic as start point)