I am running the below program.But am getting the below error Message.
401 ****
401 ****
(keeps on repeating)
The code(got from some forum) basically tries to connect to Twitter and fetch tweets.
When its ran on ubuntu terminal the 401 error message appear.
import sys
import json
import pymongo
import tweepy
consumer_key="XX" ##all the keys and codes have to be strings
consumer_secret="XX"
access_token = "XX"
access_token_secret = "XX"
# This is the listener, resposible for receiving data
class StdOutListener(tweepy.StreamListener):
def on_data(self, data):
# Twitter returns data in JSON format - we need to decode it first
decoded = json.loads(data)
# Also, we convert UTF-8 to ASCII ignoring all bad characters sent by users
print '#%s: %s' % (decoded['user']['screen_name'], decoded['text'].encode('ascii', 'ignore'))
print ''
return True
def on_error(self, status):
print status
if __name__ == '__main__':
l = StdOutListener()
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_token, access_token_secret)
print "Showing all new tweets for #programming:"
# There are different kinds of streams: public stream, user stream, multi-user streams
# In this example follow #programming tag
# For more details refer to https://dev.twitter.com/docs/streaming-apis
stream = tweepy.Stream(auth, l)
stream.filter(track=['programming'])
This is how it works..!!!
Twitter keeps track of the current time.
If an API request to authenticate comes from a server that claims it is a time that is outside of 15 minutes of Twitter time, it will fail with a 401 error.
Just reset your system's clock according to world clock or let it govern by internet your problem will be solved.
Good luck..!!!
Related
I have a terminal that served in webbrowser with wetty. I want to authenticate the user from gitlab to let user with interaction with the terminal(It is inside docker container. When user authenticated i ll allow him to see the containers terminal).
I am trying to do OAuth 2.0 but couldn't manage to achieve.
That is what i tried.
I created an application on gitlab.
Get the code and secret and make a http call with python script.
Script directed me to login and authentication page.
I tried to get code but failed(Their is no mistake on code i think)
Now the problem starts in here. I need to get the auth code from redirected url to gain access token but couldn't figure out. I used flask library for get the code.
from flask import Flask, abort, request
from uuid import uuid4
import requests
import requests.auth
import urllib2
import urllib
CLIENT_ID = "clientid"
CLIENT_SECRET = "clientsecret"
REDIRECT_URI = "https://UnrelevantFromGitlabLink.com/console"
def user_agent():
raise NotImplementedError()
def base_headers():
return {"User-Agent": user_agent()}
app = Flask(__name__)
#app.route('/')
def homepage():
text = 'Authenticate with gitlab'
return text % make_authorization_url()
def make_authorization_url():
# Generate a random string for the state parameter
# Save it for use later to prevent xsrf attacks
state = str(uuid4())
save_created_state(state)
params = {"client_id": CLIENT_ID,
"response_type": "code",
"state": state,
"redirect_uri": REDIRECT_URI,
"scope": "api"}
url = "https://GitlapDomain/oauth/authorize?" + urllib.urlencode(params)
print get_redirected_url(url)
print(url)
return url
# Left as an exercise to the reader.
# You may want to store valid states in a database or memcache.
def save_created_state(state):
pass
def is_valid_state(state):
return True
#app.route('/console')
def reddit_callback():
print("-----------------")
error = request.args.get('error', '')
if error:
return "Error: " + error
state = request.args.get('state', '')
if not is_valid_state(state):
# Uh-oh, this request wasn't started by us!
abort(403)
code = request.args.get('code')
print(code.json())
access_token = get_token(code)
# Note: In most cases, you'll want to store the access token, in, say,
# a session for use in other parts of your web app.
return "Your gitlab username is: %s" % get_username(access_token)
def get_token(code):
client_auth = requests.auth.HTTPBasicAuth(CLIENT_ID, CLIENT_SECRET)
post_data = {"grant_type": "authorization_code",
"code": code,
"redirect_uri": REDIRECT_URI}
headers = base_headers()
response = requests.post("https://MyGitlabDomain/oauth/token",
auth=client_auth,
headers=headers,
data=post_data)
token_json = response.json()
return token_json["access_token"]
if __name__ == '__main__':
app.run(host="0.0.0.0",debug=True, port=65010)
I think my problem is on my redirect url. Because it is just an irrelevant link from GitLab and there is no API the I can make call.
If I can fire
#app.route('/console')
that line on Python my problem will probably will be solved.
I need to make correction on my Python script or different angle to solve my problem. Please help.
I was totally miss understand the concept of auth2. Main aim is to have access_token. When i corrected callback url as localhost it worked like charm.
I want to get every tweet of the HousingWire on Twitter (https://twitter.com/HousingWire). I understood how to authenticate into the twitter account but how I can get the tweet of HousingWire?
I know how to stream the data based on the keywords,but I want to stream the HousingWire tweet. how I can do that?
import time
from tweepy import Stream
from tweepy import OAuthHandler
from tweepy.streaming import StreamListener
ckey=''
csecret=''
atoken=''
asecret=''
class listener(StreamListener):
def on_data(self,data):
try:
print data
#tweet=data.split(',"text":"')[1].split('","source')[0]
#print tweet
#savethis=str(time.time())+'::'+tweet
savefile=open('tweetdb.txt','a')
savefile.write(data)
savefile.write('\n')
savefile.close()
return True
except BaseException,e:
print 'failed on data',str(e)
time.sleep(5)
def on_error(self,status):
print status
auth=OAuthHandler(ckey,csecret)
auth.set_access_token(atoken,asecret)
twitterStream=Stream(auth,listener())
twitterStream.filter(track=["stock"])
You can use the below Python script to grab the last 3,240 tweets from HousingWire (Twitter only allows access to that many tweets from a user - no way to grab the complete history). Usage: Simply put their twitter screen name in the script.
#!/usr/bin/env python
# encoding: utf-8
import tweepy #https://github.com/tweepy/tweepy
import csv
#Twitter API credentials
consumer_key = ""
consumer_secret = ""
access_key = ""
access_secret = ""
def get_all_tweets(screen_name):
#Twitter only allows access to a users most recent 3240 tweets with this method
#authorize twitter, initialize tweepy
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_key, access_secret)
api = tweepy.API(auth)
#initialize a list to hold all the tweepy Tweets
alltweets = []
#make initial request for most recent tweets (200 is the maximum allowed count)
new_tweets = api.user_timeline(screen_name = screen_name,count=200)
#save most recent tweets
alltweets.extend(new_tweets)
#save the id of the oldest tweet less one
oldest = alltweets[-1].id - 1
#keep grabbing tweets until there are no tweets left to grab
while len(new_tweets) > 0:
print "getting tweets before %s" % (oldest)
#all subsiquent requests use the max_id param to prevent duplicates
new_tweets = api.user_timeline(screen_name = screen_name,count=200,max_id=oldest)
#save most recent tweets
alltweets.extend(new_tweets)
#update the id of the oldest tweet less one
oldest = alltweets[-1].id - 1
print "...%s tweets downloaded so far" % (len(alltweets))
#transform the tweepy tweets into a 2D array that will populate the csv
outtweets = [[tweet.id_str, tweet.created_at, tweet.text.encode("utf-8")] for tweet in alltweets]
#write the csv
with open('%s_tweets.csv' % screen_name, 'wb') as f:
writer = csv.writer(f)
writer.writerow(["id","created_at","text"])
writer.writerows(outtweets)
pass
if __name__ == '__main__':
#pass in the username of the account you want to download
get_all_tweets("J_tsar")
I'm attempting to use a script I found online, (https://confluence.atlassian.com/display/DOCSPRINT/The+Simplest+Possible+JIRA+REST+Examples) probably 5+ years old, to access Jira REST API. I have all the modules installed in Pyhton 2.7. However, when run the script I get an error that SimplePool cannot be imported. Having done my Goodiligence (Google searching), I see that SimplePool is deprecated in restkit 4.2.2 (which is the version I have installed). So, the doc that I found (http://pydoc.net/Python/restkit/2.3.0/restkit.pool.simple/) says to use TConnectionManager (which I did with no success). I still get a similar error. So, I stumbled upon another doc (http://benoitc.github.io/restkit/pool.html) and it says to use ConnectionPool, and I still get a similar error. I appreciate any direction given. Here is my code:
import simplejson as json
from restkit import * #added this line after finding the last document
from restkit import Resource, BasicAuth, request
from socketpool import ConnectionPool
SimplePool = ConnectionPool
def rest_test(server_base_url, user, password, issue_key):
'''
Use restkit to make a REST request to JIRA
'''
verbose = False
# A pool of connections
pool = SimplePool(factory=Connection)
# This sends the user and password with the request.
auth = BasicAuth(user, password)
resource_name = "issue"
complete_url = "%s/rest/api/latest/%s/%s" % (server_base_url, resource_name, issue_key)
resource = Resource(complete_url, pool_instance=pool, filters=[auth])
try:
response = resource.get(headers = {'Content-Type' : 'application/json'})
except Exception,ex:
# ex.msg is a string that looks like a dictionary
print "EXCEPTION: %s " % ex.msg
return
# Most successful responses have an HTTP 200 status
if response.status_int != 200:
print "ERROR: status %s" % response.status_int
return
# Convert the text in the reply into a Python dictionary
issue = json.loads(response.body_string())
# Pretty-print the JSON
if verbose:
print json.dumps(issue, sort_keys=True, indent=4)
# The properties of the issue include:
# self, html, key, transitions, expand, fields
print "Issue key: %s" % issue['key']
fields = issue['fields']
for field_name in fields:
field_object = fields[field_name]
print "Field %s = %s" % (field_name, field_object['type'])
# The type of the value of a field depends on the type of the field
if field_name in ["summary"]:
print " Value = %s" % field_object['value']
if __name__ == '__main__':
user = 'myuname'
password = '*****'
server_url = 'http://jira.mysite.com/'
issue_key = 'JRA-219'
rest_test(server_url, user, password, issue_key)
Here is the error returned:
File "simplest_client.py", line 30, in rest_test
pool = SimplePool()
TypeError: __init__() takes at least 2 arguments (1 given)
EXCEPTION: <?xml version="1.0" encoding="UTF-8" standalone="yes"?><status><status-code>404</status-code><message>null for uri: http://jira.mysite.com//rest/api/latest/issue/JRA-219</message></status>
I'm developing an application using Django and angularJS.
One of the major thing that worker server (coded in python, flask) does is downloading videos from s3 (which are uploaded by users) and uploading the videos to youtube.
Is there way to "delete a youtube video in python"?.
There is no such a code example written in python.
Does anyone know how to do this simply, like the code example below?
This is sample code for uploading video. I referred this code and implemented uploading feature.
def get_authenticated_service(args):
flow = flow_from_clientsecrets(CLIENT_SECRETS_FILE,
scope=YOUTUBE_UPLOAD_SCOPE,
message=MISSING_CLIENT_SECRETS_MESSAGE)
storage = Storage("%s-oauth2.json" % sys.argv[0])
credentials = storage.get()
if credentials is None or credentials.invalid:
credentials = run_flow(flow, storage, args)
return build(YOUTUBE_API_SERVICE_NAME, YOUTUBE_API_VERSION,
http=credentials.authorize(httplib2.Http()))
def initialize_upload(youtube, options):
tags = None
if options.keywords:
tags = options.keywords.split(",")
body=dict(
snippet=dict(
title=options.title,
description=options.description,
tags=tags,
categoryId=options.category
),
status=dict(
privacyStatus=options.privacyStatus
)
)
# Call the API's videos.insert method to create and upload the video.
insert_request = youtube.videos().insert(
part=",".join(body.keys()),
body=body,
media_body=MediaFileUpload(options.file, chunksize=-1, resumable=True)
)
resumable_upload(insert_request)
Make a file called: delete_video.py
Usage: python delete_video.py --id=MY_VID_ID
#!/usr/bin/python
import httplib
import httplib2
import os
import random
import sys
import time
from apiclient.discovery import build
from apiclient.errors import HttpError
from apiclient.http import MediaFileUpload
from oauth2client.client import flow_from_clientsecrets
from oauth2client.file import Storage
from oauth2client.tools import argparser, run_flow
# Explicitly tell the underlying HTTP transport library not to retry, since
# we are handling retry logic ourselves.
httplib2.RETRIES = 1
# Maximum number of times to retry before giving up.
MAX_RETRIES = 10
# Always retry when these exceptions are raised.
RETRIABLE_EXCEPTIONS = (httplib2.HttpLib2Error, IOError, httplib.NotConnected,
httplib.IncompleteRead, httplib.ImproperConnectionState,
httplib.CannotSendRequest, httplib.CannotSendHeader,
httplib.ResponseNotReady, httplib.BadStatusLine)
# Always retry when an apiclient.errors.HttpError with one of these status
# codes is raised.
RETRIABLE_STATUS_CODES = [500, 502, 503, 504]
# The CLIENT_SECRETS_FILE variable specifies the name of a file that contains
# the OAuth 2.0 information for this application, including its client_id and
# client_secret. You can acquire an OAuth 2.0 client ID and client secret from
# the Google Developers Console at
# https://console.developers.google.com/.
# Please ensure that you have enabled the YouTube Data API for your project.
# For more information about using OAuth2 to access the YouTube Data API, see:
# https://developers.google.com/youtube/v3/guides/authentication
# For more information about the client_secrets.json file format, see:
# https://developers.google.com/api-client-library/python/guide/aaa_client_secrets
CLIENT_SECRETS_FILE = "client_secrets.json"
# This OAuth 2.0 access scope allows an application to upload files to the
# authenticated user's YouTube channel, but doesn't allow other types of access.
YOUTUBE_DELETE_SCOPE = "https://www.googleapis.com/auth/youtube"
YOUTUBE_API_SERVICE_NAME = "youtube"
YOUTUBE_API_VERSION = "v3"
# This variable defines a message to display if the CLIENT_SECRETS_FILE is
# missing.
MISSING_CLIENT_SECRETS_MESSAGE = """
WARNING: Please configure OAuth 2.0
To make this sample run you will need to populate the client_secrets.json file
found at:
%s
with information from the Developers Console
https://console.developers.google.com/
For more information about the client_secrets.json file format, please visit:
https://developers.google.com/api-client-library/python/guide/aaa_client_secrets
""" % os.path.abspath(os.path.join(os.path.dirname(__file__),
CLIENT_SECRETS_FILE))
VALID_PRIVACY_STATUSES = ("public", "private", "unlisted")
def get_authenticated_service(args):
flow = flow_from_clientsecrets(CLIENT_SECRETS_FILE,
scope=YOUTUBE_DELETE_SCOPE,
message=MISSING_CLIENT_SECRETS_MESSAGE)
storage = Storage("%s-oauth2.json" % sys.argv[0])
credentials = storage.get()
if credentials is None or credentials.invalid:
credentials = run_flow(flow, storage, args)
return build(YOUTUBE_API_SERVICE_NAME, YOUTUBE_API_VERSION,
http=credentials.authorize(httplib2.Http()))
if __name__ == '__main__':
argparser.add_argument("--id", required=True, help="Video youtube ID")
args = argparser.parse_args()
if not args.id:
exit("Please specify a youtube ID using the --id= parameter.")
youtube = get_authenticated_service(args)
try:
resp = youtube.videos().delete(id=args.id, onBehalfOfContentOwner=None).execute()
except HttpError, e:
print "An HTTP error %d occurred:\n%s" % (e.resp.status, e.content)
Assuming that you are using the python client library I found this in the documentation.
delete(id=*, onBehalfOfContentOwner=None) Deletes a YouTube video.
Args: id: string, The id parameter specifies the YouTube video ID
for the resource that is being deleted. In a video resource, the id
property specifies the video's ID. (required)
onBehalfOfContentOwner: string, Note: This parameter is intended
exclusively for YouTube content partners.
pyGTrends does not seem to work. Giving errors in Python.
pyGoogleTrendsCsvDownloader seems to work, logs in, but after getting 1-3 requests (per day!) complains about exhausted quota, even though manual download with the same login/IP works flawlessly.
Bottom line: neither work. Searching through stackoverflow: many questions from people trying to pull csv's from Google, but no workable solution I could find...
Thank you in advance: whoever will be able to help. How should the code be changed? Do you know of another solution that works?
Here's the code of pyGoogleTrendsCsvDownloader.py
import httplib
import urllib
import urllib2
import re
import csv
import lxml.etree as etree
import lxml.html as html
import traceback
import gzip
import random
import time
import sys
from cookielib import Cookie, CookieJar
from StringIO import StringIO
class pyGoogleTrendsCsvDownloader(object):
'''
Google Trends Downloader
Recommended usage:
from pyGoogleTrendsCsvDownloader import pyGoogleTrendsCsvDownloader
r = pyGoogleTrendsCsvDownloader(username, password)
r.get_csv(cat='0-958', geo='US-ME-500')
'''
def __init__(self, username, password):
'''
Provide login and password to be used to connect to Google Trends
All immutable system variables are also defined here
'''
# The amount of time (in secs) that the script should wait before making a request.
# This can be used to throttle the downloading speed to avoid hitting servers too hard.
# It is further randomized.
self.download_delay = 0.25
self.service = "trendspro"
self.url_service = "http://www.google.com/trends/"
self.url_download = self.url_service + "trendsReport?"
self.login_params = {}
# These headers are necessary, otherwise Google will flag the request at your account level
self.headers = [('User-Agent', 'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:12.0) Gecko/20100101 Firefox/12.0'),
("Accept", "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8"),
("Accept-Language", "en-gb,en;q=0.5"),
("Accept-Encoding", "gzip, deflate"),
("Connection", "keep-alive")]
self.url_login = 'https://accounts.google.com/ServiceLogin?service='+self.service+'&passive=1209600&continue='+self.url_service+'&followup='+self.url_service
self.url_authenticate = 'https://accounts.google.com/accounts/ServiceLoginAuth'
self.header_dictionary = {}
self._authenticate(username, password)
def _authenticate(self, username, password):
'''
Authenticate to Google:
1 - make a GET request to the Login webpage so we can get the login form
2 - make a POST request with email, password and login form input values
'''
# Make sure we get CSV results in English
ck = Cookie(version=0, name='I4SUserLocale', value='en_US', port=None, port_specified=False, domain='www.google.com', domain_specified=False,domain_initial_dot=False, path='/trends', path_specified=True, secure=False, expires=None, discard=False, comment=None, comment_url=None, rest=None)
self.cj = CookieJar()
self.cj.set_cookie(ck)
self.opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(self.cj))
self.opener.addheaders = self.headers
# Get all of the login form input values
find_inputs = etree.XPath("//form[#id='gaia_loginform']//input")
try:
#
resp = self.opener.open(self.url_login)
if resp.info().get('Content-Encoding') == 'gzip':
buf = StringIO( resp.read())
f = gzip.GzipFile(fileobj=buf)
data = f.read()
else:
data = resp.read()
xmlTree = etree.fromstring(data, parser=html.HTMLParser(recover=True, remove_comments=True))
for input in find_inputs(xmlTree):
name = input.get('name')
if name:
name = name.encode('utf8')
value = input.get('value', '').encode('utf8')
self.login_params[name] = value
except:
print("Exception while parsing: %s\n" % traceback.format_exc())
self.login_params["Email"] = username
self.login_params["Passwd"] = password
params = urllib.urlencode(self.login_params)
self.opener.open(self.url_authenticate, params)
def get_csv(self, throttle=False, **kwargs):
'''
Download CSV reports
'''
# Randomized download delay
if throttle:
r = random.uniform(0.5 * self.download_delay, 1.5 * self.download_delay)
time.sleep(r)
params = {
'export': 1
}
params.update(kwargs)
params = urllib.urlencode(params)
r = self.opener.open(self.url_download + params)
# Make sure everything is working ;)
if not r.info().has_key('Content-Disposition'):
print "You've exceeded your quota. Continue tomorrow..."
sys.exit(0)
if r.info().get('Content-Encoding') == 'gzip':
buf = StringIO( r.read())
f = gzip.GzipFile(fileobj=buf)
data = f.read()
else:
data = r.read()
myFile = open('trends_%s.csv' % '_'.join(['%s-%s' % (key, value) for (key, value) in kwargs.items()]), 'w')
myFile.write(data)
myFile.close()
Although I don't know python, I may have a solution. I am currently doing the same thing in C# and though I didn't get the .csv file, I got created a custom URL through code and then downloaded that HTML and saved to a text file (also through code). In this HTML (at line 12) is all the information needed to create the graph that is used on Google Trends. However, this has alot of unnecessary text within it that needs to be cut down. But either way, you end up with the same result. The Google Trends data. I posted a more detailed answer to my question here:
Downloading .csv file from Google Trends
There is an alternative module named pytrends - https://pypi.org/project/pytrends/ It is really cool. I would recommend this.
Example usage:
import numpy as np
import pandas as pd
from pytrends.request import TrendReq
pytrend = TrendReq()
#It is the term that you want to search
pytrend.build_payload(kw_list=["Eminem is the Rap God"])
# Find which region has searched the term
df = pytrend.interest_by_region()
df.to_csv("path\Eminem_InterestbyRegion.csv")
Potentially if you have a list of terms to search you could make use of "for loop" to automate the insights as per your wish.