Creating a Palindrome String Checker C++ using Arrays and No Pointers - c++

Question

Sorry if this seems really noobish and all, and the fact is, i've only been studying this for about a month now. I can't seem to get this to work right, wondering if any of you can help me out. The program once compiled only says that the inputted words are "not palindrome" even if they are.
#include <iostream>
#include <cstring>
#include <string>
using namespace std;
bool isPal (char[], int);
int main ()
{
const int size = 10;
int flag = 0;
char arr[size];
cout << "Enter Word\n";
cin.getline(arr,10);
flag = isPal(arr, size);
if (flag == true)
cout << "Word is Palindrome\n";
else
cout << "Not Palindrome\n";
return 0;
}
bool isPal (char arr [],int size)
{
int q = 0;
char arr2[size];
for (int i = 0;i < size - 1; i++)
{
arr2[i] = arr[9 - q]; //here I attempt to reverse arr1 and assign each element to arr2
q++;
}
for (int j = 0; j < size - 1; j++)
{
if (arr [j] != arr2[j])
return false;
}
return true
}

Answer 1

If you only want to use plain C arrays then check with below code:-
bool isPallindrome ( char *p, int size ) //Remember here size must be one character before null //terminator.
{
char *begin, *end;
begin = p;
end = p + size;
while ( begin != end )
{
if( *begin != *end )
break;
begin++;
end--;
}
if ( begin != end )
return false;
return true;
}

Answer 2

Initialize the arr2
Use strlen to know the length you Input rather than use size, because your input data is not always fixed in 10
In your original code:
input: 1234567
*arr => "1234567\0"
*arr2 => "??\07654321"
Use size replaced by q
bool isPal (char arr [],int size)
{
//q=0; /* modified 3 */
char arr2[size] = ""; /* modified 1 */
for (int i=0; i<strlen(arr); i++) /* modified 2 */
{
arr2[i] = arr[strlen(arr)-i-1]; /* modified 2 */
//q++; /* modified 3 */
}
for (int i=0; i<strlen(arr); i++) /* modified 2 */
{
if (arr[i] != arr2[i])
return false;
}
return true
}
Array is "a pointer point to begin of array address", But for newbie, it's not easy to know how it works. You can reserve this thread until you learn the chapter pointer
Following the example of modified original code:
char arr[size];
char arr2[size];
// char *parr = (char*)malloc(sizeof(char)*size);
// char *parr2 = (char*)malloc(sizeof(char)*size);
cin.getline(arr,10);
// parr = &arr[0];
// cin.getline(parr, 10);
arr2[i] = arr[9 - q];
// parr1 = &arr[9-q];
// parr2 = &arr2[i]
// *parr2 = *parr1;
if (arr [j] != arr2[j])
// parr1 = &arr[j]
// parr2 = &arr2[j]
// if (*parr1 != *parr2)