Wrong output for sum of digits using loop c++ [closed] - c++

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i was required to make a program that asks users for a positive integer value, while the program uses loop to get the sum of all the numbers from 1 through n (user input). So lets say the user enters 5, the program would do 1+2+3+4+5 = 15
this is the code so far
#include <iostream>
using namespace std;
int main()
{
int number; int sum = 0; // variables
cout <<"Please input an integer greater than zero\n"
<<"Please refrain from using a negative integer." <<endl;
cin >> number; // user input
for (int i=1; i <= number; i++) // looping statement
{
sum = sum + i; // formula that takes user digits and finds sum
cout << sum;
}
My issue is that when i compile the program,for example, i enter 3, the program's output would be "136"
i want it to say 1+2+3 = 6 or much something like "the sum of the integer is 6" i just want to show the total of the value.
I'm new in c++ any help would be appreciated. Thank you!

Answer 1

You are writing cout << sum inside your loop. That means you get one number output every time your loop runs (it's really writing 1 then 3 then 6 which gets all smushed together and comes out as 136). Move that statement after the following }.

Answer 2

Here's how you can get your 1+2+3=6 output:
#include <iostream>
using namespace std;
int main()
{
int number; int sum = 0; // variables
cout <<"Please input an integer greater than zero\n"
<<"Please refrain from using a negative integer." <<endl;
cin >> number; // user input
for (int i=1; i <= number; i++) // looping statement
{
sum = sum + i; // formula that takes user digits and finds sum
if ( i == number )
cout << i;
else
cout << i << "+";
}
cout << "=" << sum;
}