I'm trying to use the Regular Expression Extractor in JMeter. When I try to parse the following string:
8EC4146730CC4A27afMCCam3ZeAl4uWt3qMMi9cE7Q5YtIkS5BDaba6bI1cgv41dm07wWlFjAmCcRLd97tmLyuO0ycKflQzhaoQS68CGaRo1oqsL1ZQyLGJMM
From the html snippet:
YourCourse
</dt>
Using this Regular Expression:
<a href='siw_portal.url\?([^"]+)' id="STU_COURSE" title='Your course'>Your Course</a>
</dt>
And Template is set to $1$.
The Regular Expression Extractor doesn't find the string.
Any ideas on why this isn't working, or how to debug this will be much appreciated.
Thanks
Because you made a mistake with the quotes:
<a href="siw_portal.url\?([^"]+)".......title="Your course"
// __^ __^ __^ __^
instead of
<a href='siw_portal.url\?([^"]+)'.......title='Your course'
You can test your regex using any online regex tester, which will help you with simple syntax errors, and also provide hints which cn be really useful for a beginner.
I like this one: http://regex101.com/
You have used different quotation marks in your regex to the sample you are matching, which is why you don't find a match. You are matching " when the sample uses '.
You can make it work in both cases using ["'] or choose the correct ' or "
In your sample, try:
<a href=["']siw_portal\.url([^"^']+)["'] id=["']STU_COURSE["'] title=["']Your course["']>Your Course</a>
</dt>
This should work
<a href="siw_portal.url(.+?)" id="STU_COURSE" title="Your course">YourCourse<\/a>
<\/dt>
Related
I want to extract ID and Name from a single regular expression, but I'm not able to get the correct response
<a href="/profiles/6635/Name"
I have used below regular expression
<a href="/profiles/(.*?)/(.*?)"
As #WiktorStribiżew suggested, you should fix your regular expression to
<a href="/profiles/([^/]+)/([^/]+)"
But also use $1$ and $2$ to get both values in in Template field, for example
$1$$2$
Will save to variable concatenated value - 6635Name
What you use <a href="/profiles/(.*?)/(.*?)" is fine to capture ID and name from <a href="/profiles/6635/Name" because a lazy way (non-greedy) (.*?) you use will match only between profiles/ and the second / same like using [^\/]+ and then between / and " so , check again that you put everything right .
You may need to escape / like this \/so , change it to :
<a href="\/profiles\/(.*?)\/(.*?)"
This is your same regex here DEMO
And if you need to make sure with java tester use this tool :Java regex tester
I know regexes aren't the best for web parsing, but I'm using it as an exercise.
I'm using Район:[^<>]*\n\s*<[^<>]*>\n\s*<a[^<>]*>([^<>]+)<\/a>
to try to match:
Район: </span>
<span class="company__contacts-item-text">
<a class="link" href="/moscow/top/marina-roscha/">Марьина роща</a>
I've been looking at it for a while but I don't know what I've been doing wrong. How can I capture something that would have newlines and different urls in the tags?
Try this regex:
Район:.+?<a[^>]+>(.+?)</a>
DESCRIPTION
DEMO
https://regex101.com/r/wA4oH0/1
I need some help with Regular expression to Search and Replace in Sublime to do the following.
I have HTML-code with links like
href="http://www.example.com/test=123"
href="http://www.example.com/test=6546"
href="http://www.example.com/test=3214"
I want to replace them with empty links:
href=""
href=""
href=""
Please help me to create a Reg. ex. filter to match my case. I guess it would sound like "starts with Quote, following with http:// .... ends with Quote and has digitals and '=' sign", but I'm not very confident of how to write this in Reg. ex. way.
(?<=href=")[^"]*
Try this.Replace by empty string.
See demo.
https://regex101.com/r/sH8aR8/40
Sorry this might be a simple question, but I could not figure it out. What I need is to filter out all the <a href...> and </a> strings out from a html text. Not sure what regular expression I should use? I tried the following search without any luck:
/<\shref^(>)>
what I mean here is to search for any string starting with "< href" and any string not containing '>' and finally '>'. My search code is not working. What is the correct one?
If I understand what you're looking for it should be <\shref[^>]*>.
Another way would be to use non-greedy matching:
/<a\shref.\{-}>
I think I got it:
/<a\shref[^>]+>
where [] is a set and ^ is not.
I have a string like this:
This <span class="highlight">is</span> a very "nice" day!
What should my RegEx-pattern in VB look like, to find the quotes within the tag? I want to replace it with something...
This <span class=^highlight^>is</span> a very "nice" day!
Something like <(")[^>]+> doesn't work :(
Thanks
It depends on your regex flavor, but this works for most of them:
"(?=[^<]*>)
EDIT: For anyone curious how this works. This translates into English as "Find a quote that is followed by a > before the next <".
Regexes are fundamentally bad at parsing HTML (see Can you provide some examples of why it is hard to parse XML and HTML with a regex? for why). What you need is an HTML parser. See Can you provide an example of parsing HTML with your favorite parser? for examples using a variety of parsers.
If you are using VB.net you should be able to use HTMLAgilityPack.
Try this: <span class="([^"]+?)?">
This should get your the first attribute value in a tag:
<[^">]+"(?<value>[^"]*)"[^>]*>
If your intention is to replace ALL quotation marks within tags, you could use the following regular expression:
(<[^>"]*)(")([^>]*>)
That will isolate the substrings before and after your quotation mark. Note that this does not attempt to match opening and closing quotation marks. It simply matches a quotation mark within a tag.