I am using RegReplace https://github.com/facelessuser/RegReplace to run a regular expression find and replace in sublime text.
I want to add a new line either side of my tags. I know to select a tag the regex is <(.*?)(.)>.
What is the correct regex to add a mew line either side of the tag, without replacing the content? Something like \n <(.*?)(.)> \n?
Use a positive lookahead and \K
(?=<(.*?)(.)>)|<(.*?)(.)>\K
Replace the matched boundary with \n character.
DEMO
OR
You could simply do like this,
(?=<[^<>]*>)|<[^<>]*>\K
Replace the matched boundary with \n character.
DEMO
Related
Trying to do this in the Atom editor (1.39.1 x64, uBuntu 18.04), though assume this applies to other text editors using regular expressions.
Say we have this text:
This text has some double-spaces. Lets try to remove them.
But not after a full-stop or if three or more spaces.
Which we would like to change to:
This text has some double-spaces. Lets try to remove them.
But not after a full-stop or if three or more spaces.
Using Find with Regex enabled (.*), all occurrences are correctly found using: [a-zA-Z] [a-zA-Z]. But what goes in the Replace row to enforce the logic:
1st letter, single space, 2nd letter?
You can use this
([a-z])\s{2}([a-z])
and replace by $1 $2
Regex Demo
If your editor supports lookarounds you can use
(?<=[a-z])\s{2}(?=[a-z])
Replace by single space character
Regex demo
Note:- don't forget to use i flag for case insensitivity or just change the character class to [a-zA-Z]
I have a couple of sentences that need processing using regular expressions. They're in a text file and I'm opening it in notepad++.
<tag>There are two tags here</tag>
<tag>How am i supposed to
feel when this is happening?</tag>
<tag>I'm not sure.
But oh well<tag>
Is it possible to use notepad++'s regular expressions and replace functionality to produce an output like so:
<tag>There are two tags here</tag>
<tag>How am i supposed to feel when this is happening?</tag>
<tag>I'm not sure. But oh well<tag>
So that sentences that span over two or more lines are joined based on the fact that there is a > at the end of the sentence. Thanks.
Replace this:
[\r\n]+(?!<)
with a space
Click for Demo
Explanation:
[\r\n]+ - matches 1+ occurrences of a \r or \n
(?!<) - negative lookahead to validate that the above match is not followed by an opening tag <
Before Replacement with space:
After replacing the matches with space:
I have a text file with a list of elements separated by line-breaks, like this:
alpha
beta
gamma
...
I want to get it into this format:
(alpha),
(beta),
(gamma),
...
So I am using following regular expressions in Notepad++ for replacing those lines:
Find: ([^\n]+)
Replace: \($1\),
but the output now strangely has another line-break for each line into it:
(alpha
),
(beta
),
(gamma
),
...
I have no clue how this is happening. When I solely use $1 or \), apart for replacement it works just fine, but everytime I put a literal after the backreference it puts a line-break in between. I know that I can work around that with another regular expression afterwards, but could anybody explain to me why exactly this is happening?
Instead of [^\n] (=any char but an LF, line feed, \n) you should use . that only matches any char other than line break chars. Use the following regex to match a non-empty line:
^.+$
Replace with \($0\), where $0 replacement backreference (also called placeholder) stands for the whole match and the parentheses are escaped (since parentheses are special metacharacters inside Boost replacement patterns used to define conditional replacement patterns).
No need to use the m modifier here since ^ and $ anchors match start and end of the line respectively by default in Notepad++.
See the NPP S&R settings:
I need to add text to first line of all my JSP's in eclipse, this is the regex I a using \A.* but some how it selects the first line, I just want to prepend text to the start of the file. any help will be very much appreciated.
The .* pattern matches any 0+ chars other than line break characters, so it matches the first line.
It seems that Eclipse Find/Replace regex feature does not match entirely zero-width patterns (e.g. (?=,) will not find and insert a text before commas).
A workaround is to match and capture some text with (...) (where ... stand for a consuming pattern) capturing group and use $1 in the replacement pattern to reinsert the matched text.
Use
\A(.*)
Replace with MY_NEW_TEXT_HERE_AT_THE_START_OF_FILE$1.
I need to cut lines that have 6 or more characters, hyphen, then other characters or symbols. Hyphen and rest of line should be removed. Source text:
0402CS-2
0402CS-3
0402
7812-C
0603CS-1
0603CS-2
0603CS-3
As a result, I need this:
0402CS
0402CS
0402
7812-C
0603CS
0603CS
0603CS
To do that, I use Notepad++ regexp replace feature. Find pattern: ^([^\-]{6,})\-.+$ Replace pattern: \1
But there is no option "multiline", so, symbols "^" and "$" doesn't match ONLY beginning and end of the line and actually I have result:
0402CS
0402CS
0402
7812 <-- that's wrong!
0603CS
0603CS
0603CS
Please advice me how to fix find pattern? Or, maybe there is other handful and powerful free text editor that can do that?
^([^\n\-]{6,})\-.+$
^^
Just use \n as due to [^-] the regex can traverse to line below as use that line to make a match.
See demo.
https://regex101.com/r/BHO93c/1
for the input
0402
7812-C the regex matches both lines as 1 line and makes a match.
See demo if 0402 is not there.
https://regex101.com/r/BHO93c/2
That happens because the [^-] character class also matches a newline.
Add \n to it:
^([^\n-]{6,})-.+$
See the regex online demo (note the m multiline modifier (making ^ match the start of the line, and $ - the end of the line) and g modifier (enabling search for multiple occurrences) that is ON by default in Notepad++).
Note that escaping the hyphen is not necessary inside a character class when it is at the start/end of the class, and you never need to escape the hyphen outside the character class.