My output is not correct when displayed - c++

Question

My output name is not being displayed in my program. I have been looking at the code and
I just can't find my error
input
name : John Dough
id : 123445
start date : 10312014
shift: 2
output
name : ^^^^^^ <<<< I am having problem my name not being displayed
id : 123445
start date : 10312014
shift : 2
code
//This program demostrates a class and a derived class with constructors.
#include <iostream>
#include <string>
#include <iomanip>
using namespace std;
class Employee
{
private:
char EmpName;
int EmpNum;
int HireDate;
public:
void setEmpName(char);
void setEmpNum(int);
void setHireDate(int);
char getEmpName() const;
int getEmpNum() const;
int getHireDate() const;
Employee();
};
void Employee::setEmpName(char x)
{
EmpName = x;
}
void Employee::setEmpNum(int y)
{
EmpNum = y;
}
void Employee::setHireDate(int z)
{
HireDate = z;
}
char Employee::getEmpName() const
{
return EmpName;
}
int Employee::getEmpNum() const
{
return EmpNum;
}
int Employee::getHireDate() const
{
return HireDate;
}
Employee::Employee()
{
cout << "I will ask you some questions about an employee.\n\n";
}
class ProductionWorker : public Employee
{
private:
int Shift;
double HourlyPayRate;
public:
void setShift(int);
void setHourlyPayRate(double);
int getShift() const;
double getHourlyPayRate() const;
ProductionWorker();
};
void ProductionWorker::setShift(int a)
{
Shift = a;
}
void ProductionWorker::setHourlyPayRate(double b)
{
HourlyPayRate = b;
}
int ProductionWorker::getShift() const
{
return Shift;
}
double ProductionWorker::getHourlyPayRate() const
{
return HourlyPayRate;
}
ProductionWorker::ProductionWorker()
{
cout << "After answering the questions,\n";
cout << "I will display the employee's information.\n\n\n";
}
int main()
{
ProductionWorker info;
char name[100];
int num;
int date;
int shift;
double rate;
cout << "What is the employee's name? ";
cin.getline(name, 100);
cout << "What is the employee's number? ";
cin >> num;
cout << "What is the employee's hire date?\n";
cout << "(Month, day, and year without any slashes,\n";
cout << "dashes, commas, or other punctuation.)\n";
cout << "For example, January 14, 1983 would look like 01141983. ";
cin >> date;
cout << "Does the employee work shift 1 or shift 2? ";
cin >> shift;
cout << "How much does the employee make per hour? ";
cin >> rate;
info.setEmpName(name[100]);
info.setEmpNum(num);
info.setHireDate(date);
info.setShift(shift);
info.setHourlyPayRate(rate);
cout << "\n\nHere is the employee's data:\n\n";
cout << "Employee's Name: " << info.getEmpName() << endl;
cout << "Employee's Number: " << info.getEmpNum() << endl;
cout << "Employee's Hire Date: " << info.getHireDate() << endl;
cout << "Employee's Shift: " << info.getShift() << endl;
cout << setprecision(2) << fixed;
cout << "Employee's Hourly Pay Rate: $" << info.getHourlyPayRate() << endl << endl;
return 0;
}

Answer 1

This is wrong: you're accessing an out-of-range character instead of passing the array to the function
char name[100];
//.. initialize name..
info.setEmpName(name[100]); // Accesses the 100th character (out-of-range [0-99])
void Employee::setEmpName(char x)
{
EmpName = x;
}
I would go for using std::string by changing EmpName (also wrong, it's not a single character) to a std::string
class Employee
{
private:
string EmpName;
int EmpNum;
int HireDate;
public:
void setEmpName(std::string& name);
void setEmpNum(int);
void setHireDate(int);
string getEmpName() const;
int getEmpNum() const;
int getHireDate() const;
Employee();
};
Also don't forget to change char name[100] to a std::string in the main function.
Live Example
You can of course accomplish this also with char arrays, in that case if you intend to use a fixed-size array you could either pass it by reference or just copy the content of a pointer to the array into a memory array for Employee.

Answer 2

There are multiple problems with your code.
First, the data type of Employee::EmpName should not be char. It should be a char array or even better would be a std::string.
Second the parameter of the setEmpName function should be either a const char* or a const std::string&.
Third, the name variable should perhaps be a std::string instead of a char array. Of course if you make that change the parameter of the setEmpName function should be const std::string&.
Fourth, when calling the setEmpName function you should just call it as follows: info.setEmpName(name).
Next, you should use std::getline(cin, name) instead of cin.getline(name, 100).

Answer 3

I'm first correcting your mistakes and then giving you a better alternative solution.
The member of your class and the setter function's parameter are only a single char. Change them to arrays:
char EmpName[100];
and
void setEmpName(char[]);
and in the implementation, you need to copy the content of the given array to your member:
void Employee::setEmpName(char[] x) {
memcpy(EmpName, x, 100);
}
However, this is the C way to do this.
The C++ way to do this is to use std::string. For this, change the types of the member, the parameters in the setter and in the getter as well as the type in main to std::string. To read a std::string, use the free-standing overload of getline which only takes the stream and the string (but no count):
getline(cin, name);