I wrote some functions and create dll by C++ codes & used some of the C++ header files. But I found loadlibrary only supports C header files and I get this error:
Error using loadlibrary (line 419)
Failed to preprocess the input file.
Output from preprocessor is:LargeBaseConvertorClass.h
C:\Program Files (x86)\Microsoft Visual Studio 10.0\VC\INCLUDE\eh.h(26) : fatal error C1189: #error : "eh.h is only for
C++!"
I dont want to change my codes and I dont want to use mex functions.
How can I use my C++ dll in matlab? (I need a lot)
Thanks.
Ya Ali.
I've done two things to handle this before.
The first is to write a C wrapper around the C++ code.
//foo_c_wrapper.h
#ifndef FOO_C_WRAPPER_H
#define FOO_C_WRAPPER_H
#ifdef __cplusplus
extern "C" {
#endif
typedef void* FOO_HANDLE;//can use a predeclared pointer type instead
FOO_HANDLE init_foo(int a);
void bar(FOO_HANDLE handle);
void destroy_foo(FOO_HANDLE** handle);
//ect
#endif
//foo.hpp
#ifndef FOO_HPP
#define FOO_HPP
class Foo {public: Foo(int); ~Foo(); void bar();}
#ifdef __cplusplus
}
#endif
#endif
//foo_c_wrapper.cpp
#include "foo_c_wrapper.h"
#include "foo.hpp"
extern "C" {
FOO_HANDLE init_foo(int a) {return new Foo(a);}
void bar(FOO_HANLDE handle) {
Foo* foo = reinterpret_cast<Foo*>(handle);
foo->bar();
}
void destroy_foo(FOO_HANDLE** handle) {
Foo** foo = reinterpret_cast<Foo**>(handle);
delete *foo;
*foo = NULL;
}
}
The other option is to go the rout of creating a custom mex file. Unfortunately that topic is way too broad to go into details here, so I'm going to count "Creating a C++ compatable Mex File" as the summary of the following link:
http://www.mathworks.com/help/matlab/matlab_external/c-mex-file-examples.html#btgcjh1-14
I did that in the past by creating a a few C interface functions to create and manipulate the C++ objects. Doing this makes it possible to easily use C++ code from Matlab without having to modify it. As long as the header is only C, Matlab does not complain if C++ objects are created in the end.
For instance, if the class you want to use from Matlab is:
class MyClass
{
public:
double memberFunction();
};
Have a header file be (add prefix to have functions be exported):
int createObject();
double callFunction( int object );
Have the cpp file be something like:
static std::map<int,MyClass*> mymap;
int createObject()
{
MyClass* obj = new MyClass();
int pos = mymap.size();
mymap[pos] = obj;
return pos;
}
double callFunction( int obj )
{
return mymap[obj]->memberFunction();
}
Now, you can create MyClass objects and access members from Matlab.
You'll need to pass more parameters, handle map content better (check if object exists in the map and return errors if not, delete objects from the map when done...etc), but this is the general idea.
Related
I have a C++ header and cpp files like abc.hpp and abc.cpp which has 2 classes that is class A and class B, am trying to write a C layer containing different methods which calls the C++ layer methods, to call the C++ methods I need to create the instance of Class A and then use this instance to call C++ methods, I have created a C layer but tried different ways to create an instance of class B but it was not possible.
This is ABC.hpp
#ifndef ABC_HPP
#define ABC_HPP
namespace utils {
using std::vector;
using std::string;
class __declspec(dllexport) A
{
protected:
string m_color;
string m_type;
public:
A() {
// TODO: Complete the constructor by intializing everything
m_color = "";
m_type = "";
}
void setColor(string icolor){m_color = icolor;}
void setType(string itype){m_type = itype;}
string getColor(){return m_color;}
string getType() {return m_type;}
virtual ~A() {};
};
class __declspec(dllexport) B
{
// Member Variables
protected:
string file_name;
string place_name;
public:
void setFilename(fname){file_name = fname;}
void setPlaceName(pname){place_name = pname;}
string getFilename(){return file_name;}
string getplaceName() {return place_name;}
void getRes();
};
};
#endif
Similarly we have ABC.cpp
Next I create the C layer xyz_c.h
#ifndef XYZ_H
#define XYZ_H
#ifdef __cplusplus
extern "C"
{
#endif
__declspec(dllexport) int getPlaceNames(char** oNames);
#ifdef __cplusplus
}
#endif
#endif
Next I create XYZ.cpp
#include "XYZ.h"
#include "ABC.h"
#ifdef __cplusplus
extern "C" {
#endif
int getResults(char** oNames)
{
//here I need to create the instance of B to Call C++ layer getRes()
}
#ifdef __cplusplus
}
#endif
You cannot. C++ was designed to allow it to use the whole set of C legacy code already written, but the other side is not possible... simply because when C was designed there was no C++ available, and C doesn't have constructs as C++ has to be able to link routines written in C.
This means that if you want to combine C and C++ code, the program must be linked as a C++ program (built as) and you can include every routine you want (you can compile individual modules as C modules) but you have to access them from the C++ code including a extern "C" linkage statement in the C++ code (and never the reverse)
C++ has a naming convention for methods and c++ functions that includes information in the name about the types and number of parameters to allow for overloading and to include the object instance in the parameter list. This is simply unknown for a C compiler, so you cannot easily guess the name that the linker uses for something so simple as a void f(void) function (it can be something like 1f4void (yes, starting with a digit) making it impossible to be accessed from C (as C identifiers must start with a letter or underscore). If you declare f as extern "C" f(void), then you can call it from C modules, and it can even be implemented in C (and compiled in c), and the linker will know it as _f (or f is in use today also, depending on the compiler)
You can even write the int main(int argc, char **argv) funtion as a C function, but when you link it, you will need to use the C++ linker, if you want your program to include C++ code.
The proper way to do this is as follows. In your "C" interface code, you should have functions matching the c++ interface with the addition of a void* parameter. This parameter will be used to hold the instance for future usage by XYZ.
SO I would add a abc.c, with definitions as:
void setFilename(void* b, char *fname){
((B*)b)->setFilename(fname);
};
of course you will need to define also creator function such as:
void* CreateB(){
return (void*)new B();
}
I'm writing a small Wrapper API so i can call some C++ code (classes/ functions) from C.
I got the problem, that one of my C++ functions is initialised in my wrapper header with a "shared_ptr".
ClassName *ClassName _new(std::shared_ptr<Lib::Instance> p_Instance);
So as you can see, the wrapper file is infested with C++ style. This is bad because the Wrapper file should be readable by C AND C++.
This is my Wrapper.h file:
#ifdef __cplusplus
extern "C" {
#endif /* __cplusplus */
typedef struct ClassName ClassName;
ClassName *ClassName_new(std::shared_ptr<Lib::Instance> p_Instance);
void ClassName_setValue(ClassName* t, double p_value);
void ClassName_delete(ClassName* t);
#ifdef __cplusplus
}
#endif /* __cplusplus */
and this is my Wrapper.cpp file:
#include "Wrapper.h"
#include "ClassName.h"
extern "C"{
ClassName* ClassName_new(std::shared_ptr<Lib::Instance> p_Instance){
return new ClassName(p_Instance);
}
void ClassName_setValue(ClassName* t, double p_value){
t->setValue(p_value);
}
void ClassName_delete(ClassName* t){
delete t;
}
}
And this is the part of my main .cpp file
Header:
class ClassName: public Lib::Util::Task {
public:
ClassName(std::shared_ptr<Lib::Instance> p_Instance);
virtual ~ClassName();
void setValue(double p_value);
...
.Cpp:
ClassName::ClassName(std::shared_ptr<Lib::Instance> p_Instance) ...
...
void ClassName::setValue(double p_value){
doSomething()
}
...
I'm not allowed to change my structure of the main c++ file where I am using the ClassName(std::shared_ptr<Lib::Instance> p_Instance);
Do you have any ideas how I can fix this problem?
Maybe writing a second Wrapper?
Edit:
Here is the error given by the Terminal:
Wrapper.h:21:45: error: expected ‘)’ before ‘:’ token
ClassName *ClassName_new(std::shared_ptr<Lib::Instance> p_Instance);
^
The function cannot be used in C, so you can use the pre-processor to remove the declaration just like you used with extern "C":
// Wrapper.h
#ifdef __cplusplus
ClassName *ClassName_new(std::shared_ptr<Lib::Instance> p_Instance);
#endif
Although, it this wrapper isn't supposed to be used in C++ by anything other than Wrapper.cpp, then moving the declaration into Wrapper.cpp might be a better option.
If you need a way of invoking ClassName_new from C, I would suggest steering away from shared pointer. But you could make it work with an opaque wrapper:
// Wrapper.h
struct opaque_wrapper* make_instance(void);
void release_instance(struct opaque_wrapper*);
ClassName *ClassName_new(struct opaque_wrapper*);
// Wrapper.cpp
struct opaque_wrapper {
std::shared_ptr<Lib::Instance> p_Instance;
};
opaque_wrapper* make_instance() {
return new opaque_wrapper{std::make_shared<Lib::Instance>()};
}
void release_instance(struct opaque_wrapper* instance) {
delete instance;
}
ClassName *ClassName_new(struct opaque_wrapper* instance) {
return ClassName_new(instance->p_Instance);
}
I would suggest embedding the reference counter into the object and use boost::intrusive_ptr with it. This way you can pass a plain pointer to C functions and those C functions can still manage the object's lifetime directly calling C-style addref/release on it.
You cannot use classes from C++ in C.
You can define function prototypes of C calling convention C functions, to be used from C++ with the following wrapper code around in the header file:
#ifdef __cplusplus
extern "C" {
#endif
/* put here C calling convention C functions */
#ifdef __cplusplus
};
#endif
and you'll get a definitions file that can be used either in C or in C++. __cplusplus is a macro defined by the c++ compiler when compiling C++ code, and it introduces the extern "C" { environment to support C functions. Those functions follow the C style calling conventions (you cannot overload them, you cannot use method definitions or define classes in there)
I know this.
Calling C function from C++:
If my application was in C++ and I had to call functions from a library written in C. Then I would have used
//main.cpp
extern "C" void C_library_function(int x, int y);//prototype
C_library_function(2,4);// directly using it.
This wouldn't mangle the name C_library_function and linker would find the same name in its input *.lib files and problem is solved.
Calling C++ function from C???
But here I'm extending a large application which is written in C and I need to use a library which is written in C++. Name mangling of C++ is causing trouble here. Linker is complaining about the unresolved symbols. Well I cannot use C++ compiler over my C project because thats breaking lot of other stuff. What is the way out?
By the way I'm using MSVC
You need to create a C API for exposing the functionality of your C++ code. Basically, you will need to write C++ code that is declared extern "C" and that has a pure C API (not using classes, for example) that wraps the C++ library. Then you use the pure C wrapper library that you've created.
Your C API can optionally follow an object-oriented style, even though C is not object-oriented. Ex:
// *.h file
// ...
#ifdef __cplusplus
#define EXTERNC extern "C"
#else
#define EXTERNC
#endif
typedef void* mylibrary_mytype_t;
EXTERNC mylibrary_mytype_t mylibrary_mytype_init();
EXTERNC void mylibrary_mytype_destroy(mylibrary_mytype_t mytype);
EXTERNC void mylibrary_mytype_doit(mylibrary_mytype_t self, int param);
#undef EXTERNC
// ...
// *.cpp file
mylibrary_mytype_t mylibrary_mytype_init() {
return new MyType;
}
void mylibrary_mytype_destroy(mylibrary_mytype_t untyped_ptr) {
MyType* typed_ptr = static_cast<MyType*>(untyped_ptr);
delete typed_ptr;
}
void mylibrary_mytype_doit(mylibrary_mytype_t untyped_self, int param) {
MyType* typed_self = static_cast<MyType*>(untyped_self);
typed_self->doIt(param);
}
I would do it in the following way:
(If working with MSVC, ignore the GCC compilation commands)
Suppose that I have a C++ class named AAA, defined in files aaa.h, aaa.cpp, and that the class AAA has a method named sayHi(const char *name), that I want to enable for C code.
The C++ code of class AAA - Pure C++, I don't modify it:
aaa.h
#ifndef AAA_H
#define AAA_H
class AAA {
public:
AAA();
void sayHi(const char *name);
};
#endif
aaa.cpp
#include <iostream>
#include "aaa.h"
AAA::AAA() {
}
void AAA::sayHi(const char *name) {
std::cout << "Hi " << name << std::endl;
}
Compiling this class as regularly done for C++. This code "does not know" that it is going to be used by C code. Using the command:
g++ -fpic -shared aaa.cpp -o libaaa.so
Now, also in C++, creating a C connector:
Defining it in files aaa_c_connector.h, aaa_c_connector.cpp. This connector is going to define a C function, named AAA_sayHi(cosnt char *name), that will use an instance of AAA and will call its method:
aaa_c_connector.h
#ifndef AAA_C_CONNECTOR_H
#define AAA_C_CONNECTOR_H
#ifdef __cplusplus
extern "C" {
#endif
void AAA_sayHi(const char *name);
#ifdef __cplusplus
}
#endif
#endif
aaa_c_connector.cpp
#include <cstdlib>
#include "aaa_c_connector.h"
#include "aaa.h"
#ifdef __cplusplus
extern "C" {
#endif
// Inside this "extern C" block, I can implement functions in C++, which will externally
// appear as C functions (which means that the function IDs will be their names, unlike
// the regular C++ behavior, which allows defining multiple functions with the same name
// (overloading) and hence uses function signature hashing to enforce unique IDs),
static AAA *AAA_instance = NULL;
void lazyAAA() {
if (AAA_instance == NULL) {
AAA_instance = new AAA();
}
}
void AAA_sayHi(const char *name) {
lazyAAA();
AAA_instance->sayHi(name);
}
#ifdef __cplusplus
}
#endif
Compiling it, again, using a regular C++ compilation command:
g++ -fpic -shared aaa_c_connector.cpp -L. -laaa -o libaaa_c_connector.so
Now I have a shared library (libaaa_c_connector.so), that implements the C function AAA_sayHi(const char *name). I can now create a C main file and compile it all together:
main.c
#include "aaa_c_connector.h"
int main() {
AAA_sayHi("David");
AAA_sayHi("James");
return 0;
}
Compiling it using a C compilation command:
gcc main.c -L. -laaa_c_connector -o c_aaa
I will need to set LD_LIBRARY_PATH to contain $PWD, and if I run the executable ./c_aaa, I will get the output I expect:
Hi David
Hi James
EDIT:
On some linux distributions, -laaa and -lstdc++ may also be required for the last compilation command. Thanks to #AlaaM. for the attention
Assuming the C++ API is C-compatible (no classes, templates, etc.), you can wrap it in extern "C" { ... }, just as you did when going the other way.
If you want to expose objects and other cute C++ stuff, you'll have to write a wrapper API.
You will have to write a wrapper for C in C++ if you want to do this. C++ is backwards compatible, but C is not forwards compatible.
export your C++ functions as extern "C" (aka C style symbols), or use the .def file format to define undecorated export symbols for the C++ linker when it creates the C++ library, then the C linker should have no troubles reading it
#include <iostream>
//////////////
// C++ code //
//////////////
struct A
{
int i;
int j;
A() {i=1; j=2; std::cout << "class A created\n";}
void dump() {std::cout << "class A dumped: " << i << ":" << j << std::endl;}
~A() {std::cout << "class A destroyed\n";}
};
extern "C" {
// this is the C code interface to the class A
static void *createA (void)
{
// create a handle to the A class
return (void *)(new A);
}
static void dumpA (void *thisPtr)
{
// call A->dump ()
if (thisPtr != NULL) // I'm an anal retentive programmer
{
A *classPtr = static_cast<A *>(thisPtr);
classPtr->dump ();
}
}
static void *deleteA (void *thisPtr)
{
// destroy the A class
if (thisPtr != NULL)
{
delete (static_cast<A *>(thisPtr));
}
}
}
////////////////////////////////////
// this can be compiled as C code //
////////////////////////////////////
int main (int argc, char **argv)
{
void *handle = createA();
dumpA (handle);
deleteA (handle);
return 0;
}
You can prefix the function declaration with extern “C” keyword, e.g.
extern “C” int Mycppfunction()
{
// Code goes here
return 0;
}
For more examples you can search more on Google about “extern” keyword. You need to do few more things, but it's not difficult you'll get lots of examples from Google.
How can we call "C++" class member functions in 'C" code ?
I have two files .cpp, in which I have defined some classes with member functions and corresponding ".h" files which has included some other helping cpp/h files.
Now I want to call these functionality of CPP files in "C" file.
How can I do it?
C has no thiscall notion. The C calling convention doesn't allow directly calling C++ object member functions.
Therefor, you need to supply a wrapper API around your C++ object, one that takes the this pointer explicitly, instead of implicitly.
Example:
// C.hpp
// uses C++ calling convention
class C {
public:
bool foo( int arg );
};
C wrapper API:
// api.h
// uses C calling convention
#ifdef __cplusplus
extern "C" {
#endif
void* C_Create();
void C_Destroy( void* thisC );
bool C_foo( void* thisC, int arg );
#ifdef __cplusplus
}
#endif
Your API would be implemented in C++:
#include "api.h"
#include "C.hpp"
void* C_Create() { return new C(); }
void C_Destroy( void* thisC ) {
delete static_cast<C*>(thisC);
}
bool C_foo( void* thisC, int arg ) {
return static_cast<C*>(thisC)->foo( arg );
}
There is a lot of great documentation out there, too. The first one I bumped into can be found here.
I am trying to access a C++ class and call its method from a .c file.
I google this topic and find this http://developers.sun.com/solaris/articles/mixing.html
It says:
You can write extern "C" functions in C++ that access class M objects and call them from C code.
Here is a C++ function designed to call the member function foo:
extern "C" int call_M_foo(M* m, int i) { return m->foo(i); }
My question is where do I put the about line? In my C++ .h file? Or C .h file?
And it goes on and says:
Here is an example of C code that uses class M:
struct M; // you can supply only an incomplete declaration
int call_M_foo(struct M*, int); // declare the wrapper function
int f(struct M* p, int j) // now you can call M::foo
{
return call_M_foo(p, j);
}
But how/where do I create the class M in my C file?
And where do I put the above code? C .h file? C++ .h file? Or C .c file?
Thank you.
Thank you for GMan's detailed answer.
I did follow your suggestion. But I get compile error in my .c file.
main.c:33:
./some_class.h:24: error: expected ‘=’, ‘,’, ‘;’, ‘asm’ or ‘attribute’ before ‘’ token
./some_class.h:25: error: expected ‘)’ before ‘’ token
./some_class.h:26: error: expected ‘)’ before ‘*’ token
And here are my some_class.h line 24-26:
#ifdef __cplusplus
class M {
public:
M();
virtual ~M();
void method1(char* name, char* msg);
};
extern "C" {
#else
struct M;
#endif
/* access functions line 24-26 are here*/
M* M_new(void);
void M_delete(M*);
void M_method1(M*, char*, char*);
#ifdef __cplusplus
}
#endif
For some reason, my C compiler does not like extern "C" in GMan's original some_test.h. So I have to modify to above. It seems like the C compiler does not like/understand the struct M; line.
Any idea will be much appreciated.
Your header file, which is shared between your C and C++ code:
#ifdef __cplusplus // only actually define the class if this is C++
class some_class
{
public:
int some_method(float);
};
#else
// C doesn't know about classes, just say it's a struct
typedef struct some_class some_class;
#endif
// access functions
#ifdef __cplusplus
#define EXPORT_C extern "C"
#else
#define EXPORT_C
#endif
EXPORT_C some_class* some_class_new(void);
EXPORT_C void some_class_delete(some_class*);
EXPORT_C int some_class_some_method(some_class*, float);
Then your source file:
#include "some_foo.h"
int some_class::some_method(float f)
{
return static_cast<int>(f);
}
// access functions
EXPORT_C some_class* some_class_new(void)
{
return new some_class();
}
EXPORT_C void some_class_delete(some_class* this)
{
delete this;
}
EXPORT_C int some_class_some_method(some_class* this, float f)
{
return this->some_method(f);
}
Now compile that source, and link to it. Your C source would be something like:
#include "some_class.h"
some_class* myInstance = some_class_new();
int i = some_class_some_method(myInstance, 10.0f);
some_class_delete(myInstance);
If you're serious about mixing C and C++, you'll want macro's.
Here are some sample macro's that would make this much easier:
// in something like c_export.h
// extern "C" macro
#ifdef __cplusplus
#define EXPORT_C extern "C"
#else
#define EXPORT_C
#endif
// new
#define EXPORT_C_CLASS_NEW(classname) EXPORT_C \
classname * classname##_new(void)
#define EXPORT_C_CLASS_NEW_DEFINE(classname) \
EXPORT_C_CLASS_NEW(classname) \
{ return new classname (); }
// repeat as much as you want. allows passing parameters to the constructor
#define EXPORT_C_CLASS_NEW_1(classname, param1) EXPORT_C \
classname * classname##_new( param1 p1)
#define EXPORT_C_CLASS_NEW_1_DEFINE(classname, param1) \
EXPORT_C_CLASS_NEW_1(classname, param1) \
{ return new classname (p1); }
// delete
#define EXPORT_C_CLASS_DELETE(classname) EXPORT_C \
void classname##_delete( classname * this)
#define EXPORT_C_CLASS_DELETE_DEFINE(classname) \
EXPORT_C_CLASS_DELETE(classname) \
{ delete this; }
// functions
#define EXPORT_C_CLASS_METHOD(classname, methodname, ret) EXPORT_C \
ret classname##_##methodname##( classname * this)
#define EXPORT_C_CLASS_METHOD_DEFINE(classname, methodname, ret) \
EXPORT_C_CLASS_METHOD(classname, methodname, ret) \
{ return this->##methodname##(); }
// and repeat as necessary.
#define EXPORT_C_CLASS_METHOD_1(classname, methodname, ret, param1) EXPORT_C \
ret classname##_##methodname( classname * this, param1 p1)
#define EXPORT_C_CLASS_METHOD_1_DEFINE(classname, methodname, ret, param1) \
EXPORT_C_CLASS_METHOD_1(classname, methodname, ret, param1) \
{ return this->##methodname##(p1); }
And so on. Our header/source becomes:
// header
#include "c_export.h" // utility macros
#ifdef __cplusplus // only actually define the class if this is C++
class some_class
{
public:
int some_method(float);
};
#else
// C doesn't know about classes, just say it's a struct
typedef struct some_class some_class;
#endif
// access functions
EXPORT_C_CLASS_NEW(some_class);
EXPORT_C_CLASS_DELETE(some_class);
EXPORT_C_CLASS_METHOD_1(some_class, some_method, int, float);
// source
#include "some_foo.h"
int some_class::some_method(float f)
{
return static_cast<int>(f);
}
// access functions
EXPORT_C_CLASS_NEW_DEFINE(some_class);
EXPORT_C_CLASS_DELETE_DEFINE(some_class);
EXPORT_C_CLASS_METHOD_1_DEFINE(some_class, some_method, int, float);
And that's much more concise. It could be made simpler (possibly) with variadic macro's, but that's non-standard and I leave that to you. :] Also, you can make macro's for normal non-member functions.
Note that C does not know what references are. If you want to bind to a reference, your best bet is probably just to write the export definition manually. (But I'll think about it, maybe we can get it automatically).
Imagine our some_class took the float by (non-const)reference (for whatever reason). We'd define the function like so:
// header
// pass by pointer! v
EXPORT_C_CLASS_METHOD_1(some_class, some_method, int, float*) ;
// source
EXPORT_C_CLASS_METHOD_1(some_class, some_method, int, float*)
{
// dereference pointer; now can be used as reference
return this->some_method(*p1);
}
And there we go. C would interface with references with pointers instead:
// c source, if some_method took a reference:
float f = 10.0f;
int i = some_class_some_method(myInstance, &f);
And we pass f "by reference".
You need to split it among the C++ header and implementation files.
foo.h:
extern "C" int call_M_foo(M* m, int i);
foo.cc:
extern "C" int call_M_foo(M* m, int i) {
return m->foo(i);
}
To create the object of type M, you would need a similar function:
foo.h:
struct M;
extern "C" M* create_M();
foo.cc:
extern "C" M* create_M() {
return new M;
}
You have several questions combined here so I will answer them individually.
My question is where do I put the about line? In my c++ .h file? or c .h file?
The extern "C" line goes in the C++ file. It essentially tells the compiler to
limit everything whithin the extern "C" block to the C subset of C++, and to
export functions declared in this area accordingly.
But how/where do I create the class M in my c file?
You can't. C does not have the concept of classes, and there's absolutely no
way to instantiate a class directly. You essentially have to export a C function
in your C++ file which creates the class and returns it as a pointer. Then you
can pass that pointer around your C application. You can't actually modify the
class directly in your C application, because C does not support classes, and
your C++ compiler may insert "hidden" variables for bookkeeping inside the
actual declaration of the class.
And where do I put the above code?
The piece of code that uses a structure pointer goes in the C file. You are
forced to use a structure pointer because C does not support classes at all.
You can put function calls using that function anywhere in a C implementation
file, just like normal C function calls.
All the information you need is in the link you provide. You just need to understand that there needs to be a strict separation between C and C++ code.
C++ code can call any C code.
C code usually cannot call any C++ code.
C functions can be implemented by C++ code.
The key part to understand is that the C and C++ compilers mangle function names when making object files in different ways, so they would normally not be able to interoperate (at link time), except that C++ can be prompted to know the difference by using extern "C"
The prototype:
void f(int); might be mangled by a C compiler to: _f, but a C++ compiler might choose a very different name eg f_int, and so the linker would not know they are supposed to be the same.
However:
extern "C" void f(int);
would be mangled by a C++ compiler to _f, but a C compiler would choke on the extern "C". To avoid this you should used something like this:
#ifdef __cplusplus
extern "C" {
#endif
void f(int);
#ifdef __cplusplus
} /* closing brace for extern "C" */
#endif
Now the whole of the above section can live in a .h file and is, as the sun.com article states, a mixed-language header.
This means that a .c or .cpp file can #include this header and code can call f();
and either a .c or .cpp file can #include this header and implement it:
void f()
{
}
Now the good bit is that a .cpp file can implement this to call any C++ code it likes.
Now to answer your specific questions:
The first code sample can only go in a .cpp file.
The second code sample can only go in a .c file.
Additionally class M must be declared and defined in C++ files only.
The site you have linked to has the answer already:
You can declare function print in a
header file that is shared by C and
C++ code:
#ifdef __cplusplus extern "C"
#endif int print(int i, double d);
You can declare at most one function
of an overloaded set as extern "C"
Here is the example C header for the
wrapper functions:
int g_int(int);
double g_double(double);
Basically, there can be a header shared between the two that declares the function prototype, adding the extern "C" modifier if you are in C++ to ensure the function can be accessed in an object from C. You define the body of the function later on in the C++ code as usual, if necessary inside a class etc, and you use the function in C like normal.