After passing pointer to the main function, cannot print the content properly - c++

Question

I am practicing using pointers to create objects and access data. I created a stuct called BigNum to represent a number with multiple digits. When I try to print the content of the struct inside the readDigits function, it can be printed pretty well. However, after passing the pointer to the main function, the content of the stuct is printed out to be random numbers. Why? How to fix it?
struct BigNum{
int numDigits; //the number of digits
int *digits; //the content of the big num
};
int main(){
BigNum *numPtr = readDigits();
for (int i=0; i<(numPtr->numDigits);i++ ){
std::cout << (numPtr->digits)[i] << std::endl;
}
return 0;
}
BigNum* readDigits(){
std::string digits;
std::cout << "Input a big number:" << std::endl;
std::cin >> digits;
int result[digits.length()];
toInt(digits,result);
BigNum *numPtr = new BigNum();
numPtr->numDigits = digits.length();
numPtr->digits = result;
/* When I try to print in here, it's totally okay!
std::cout << "Here is the content:" << std::endl;
for (int i=0; i<numPtr->numDigits;i++ ){
std::cout << (numPtr->digits)[i] << std::endl;
}
*/
return numPtr;
}
void toInt(std::string& str, int result[]){
for (int i=0;i<str.length() ;i++ ){
result[str.length()-i-1] = (int)(str[i]-'0');
}
}

Answer 1

BigNum* readDigits(){
//....
int result[digits.length()];
//....
numPtr->digits = result;
return numPtr;
}
result is stored on the stack. So if you return it as part of numPtr, it will be invalid as soon as you exit the function. Instead of storing it on the stack you have to allocate it with new.

Answer 2

You have undefined behavior because you assign address of automatic object to digits pointer. When readDigits() returns this memory is not valid anymore. You should assign to this pointer address of heap-based object (or some equivalent, e.g. use vector or smart pointer):
#include <vector>
struct BigNum{
int numDigits; //the number of digits
std::vector<int> digits; //the content of the big num
};
Then you can insert numbers into vector this way:
int input;
while ( std::cin >> input) //enter any non-integer to end the loop
{
digits.push_back(input);
}

Answer 3

The problem is that within the function BigNum* readDigits() you assign apointer to stack memory to the pointer of your newly allocated BigNum:
int result[digits.length()]; // <--- variable is on the stack!!!
toInt(digits,result);
BigNum *numPtr = new BigNum();
numPtr->numDigits = digits.length();
numPtr->digits = result; // <--- make pointer to stack memory available to caller of readDigits
Now if you proceed the access to numPtr->digits is ok since the memory of result is still valid on the stack (as long as you are within readDigits). Once you've left ´readDigits()´ the memory of result is overwritten depending on what you do (calling other functions, ...).
Right now I'm even wondering why you don't get a compiler error with ´int result[digits.length()];´ since ´digits.length()´ is not constant and the size of required stack memory has to be defined at compile time... so I'm thinking that the size of result is actually 0...?? Would be a nice thing to test!
My recommendation is to modify the code of readDigits as follows:
BigNum* readDigits()
{
std::string digits;
int i;
std::cout << "Input a big number:" << std::endl;
std::cin >> digits;
//int result[digits.length()];
//toInt(digits,result);
BigNum *numPtr = new BigNum();
numPtr->numDigits = digits.length();
numPtr->digits = (int *)malloc(sizeof(int) * numPtr->numDigits); // allocate heap memory for digits
toInt(digits, numPtr->digits);
/* When I try to print in here, it's totally okay!
std::cout << "Here is the content:" << std::endl;
for (i = 0; i <numPtr->numDigits; i++)
{
std::cout << (numPtr->digits)[i] << std::endl;
}
*/
return numPtr;
}
Remember to free your memory if ´BigNum *numPtr´ is no longer used (´free(numPtr->digits);´) otherwise you'll get a memory leak (sooner or later):
int main()
{
BigNum *numPtr = readDigits();
int i;
for (i = 0; i < (numPtr->numDigits); i++)
{
std::cout << (numPtr->digits)[i] << std::endl;
}
free(numPtr->digits); // free memory allocated by readDigits(..)
return 0;
}