problems with gluLookAt - opengl

I am trying to test gluLookAt using this code. But I can see only a black screen. What is wrong with this code ? Is there any basic concept about glulookAt (or opengl camera) that I need to understand.
glViewport(0,0,640,480);
glEnable(GL_DEPTH_TEST);
glClearColor(0,0,0,1);
glMatrixMode(GL_PROJECTION);
glLoadIdentity();
gluLookAt(0,0,5,0,0,0,0,0,1);
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT);
glBegin(GL_POLYGON);
glColor3f(1, 0, 0);
glVertex2d(0.25, 0.25);
glVertex2d(-0.25, 0.25);
glVertex2d(-0.25, -0.25);
glVertex2d(0.25, -0.25);
glEnd();

One issue is the up vector of gluLookAt is in the same direction as the look direction.
All you need to do is set +Y up and it should work...
gluLookAt(0, 0, 0.5, //position is +0.5 along Z (NOTE: 0.5, not 5. see below),
0, 0, 0, //looking at a 0.5x0.5 X/Y quad at the origin
0, 1, 0 //rotated such that +Y is up
);
The other issue is that gluLookAt shouldn't be applied to the projection matrix. It'll work for now but will break lighting later. Move it to the modelview matrix:
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
gluLookAt(... as before ...);
Assuming the projection matrix hasn't been set, changing the from position of gluLookAt back to your 5 will make the quad disappear. This is because the default projection gives a viewing volume of an orthographic -1 to 1 cube. With the "camera" now too far away it won't see anything. This is where you'll want to investigate changing the projection matrix. Maybe increase the size of the orthographic projection with glOrtho(), or look into the more complex but natural gluPerspective().

Related

How to place coordinates > 100.0f in opengl?

When I place coordinates like this:
display(){
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
glTranslatef(0.0f, 0.0f, 360.0f);
drawTeapot();
glutSwapBuffers();
}
The teapot is not visible and I want it visible at 360.0f.
I am using this for init,
init()
{
glMatrixMode(GL_PROJECTION);
glLoadIdentity();
gluPerspective(45, width/height, -1000, 1000);
}
It's not a case placing coordinates > 100.0f. For starters your furstrum is wrong as the zNear value should be > 0. There is no negative region of a viewing frustrum :).
The translation you are doing on the ModelView matrix is the wrong way. i.e invert the z translation to -360.0f.
See here for more information on OpenGL axis. If you translate an object n-units to the left, from the camera's point of view you have moved it n-units to the right.
your zNear plane shouldn't be negative
gluPerspective(45, width/height, 0.1, 1000);
have you tried placing the teapot at -360 ? . are you sure your view is looking towards +z and not -z
whats your scaling of the teapot?. Maybe it's just too tiny to be seen so far away

How can I define starting position of glutWireCube?

I am rather new to programming so I may not use the correct terminology. I am trying to create a dog out of only glutwirecubes, however I cannot figure out how to define a starting position for the back legs, nor can I figure out how to close the space between my 'shoulder' and 'elbows'. I have each body part assigned to rotate by key press. I also realize that my use of glPushMatrix and glPopMatrix may not be correct as I do not fully understand how the matrix stack is saved/loaded.
glPushMatrix();
glTranslatef(-1, 0, 0);
glRotatef((GLfloat)body,1, 0, 0);//sets rotations about x,y,z axis
glTranslatef(1, 0, 0);
glPushMatrix();
glScalef(2.0, 0.4, 0.5);//sets dimensions of cube
glutWireCube(2.0);//sets scale of wire cube
glPopMatrix();
glPopMatrix();
glPushMatrix();
glTranslatef(-1, 0, 0);
glRotatef((GLfloat)shoulder, 0, 0, 1);//sets rotations about x,y,z axis
glTranslatef(1, 0, 0);
glPushMatrix();
glScalef(1.5, 0.4, 0.5);//sets dimensions of cube
glutWireCube(.75);//sets scale of wire cube
glPopMatrix();
glTranslatef(1,0,0);
glRotatef((GLfloat)elbow,0,0,1);//sets rotations about x,y,z axis
glTranslatef(1,0,0);
glPushMatrix();
glScalef(1.5,0.4,0.5);//sets dimensions of cube
glutWireCube(.75);//sets scale of wire cube
glPopMatrix();
glPopMatrix();
glutSwapBuffers();
The picture is the position I am aiming for, however my cubes always start oriented horizontally.
with glTranslate right before, as for its friends !
For instance you might translate so that the center is now at the corner, so that your rotations rotate around this new handle.

OpenGL change background without changing perspective of previously drawn pictures

So I draw an 'I' and use gluLookAt(0.f,0.f,3.f,0.f,0.f,0.f,0.f,1.f,0.f), and the I is moderate size. Then I add a drawScene() function which draw the background with gradient color, and then the 'I' becomes super big. I guess it is because I change matrix mode to GL_PROJECTION and GL_MODELVIEW in drawScene(), and those change the perspective maybe? I guess glPushMatrix() and glPopMatrix() are needed to reserve matrix status, but I have hard time finding where to put them. So how can I make the 'I' look normal size? Here are my drawI() and drawScene():
void drawI(int format)
{
glBegin(format);
glColor3f(0, 0, 1);
glVertex2f(point[3][0], point[3][1]);
glVertex2f(point[2][0], point[2][1]);
glVertex2f(point[1][0], point[1][1]);
glVertex2f(point[12][0], point[12][1]);
glVertex2f(point[10][0], point[10][1]);
glEnd();
glBegin(format);
glVertex2f(point[10][0], point[10][1]);
glVertex2f(point[11][0], point[11][1]);
glVertex2f(point[12][0], point[12][1]);
glEnd();
glBegin(format);
glVertex2f(point[9][0], point[9][1]);
glVertex2f(point[10][0], point[10][1]);
glVertex2f(point[3][0], point[3][1]);
glVertex2f(point[4][0], point[4][1]);
glVertex2f(point[6][0], point[6][1]);
glColor3f(1, 0.5, 0);
glVertex2f(point[7][0], point[7][1]);
glVertex2f(point[8][0], point[8][1]);
glEnd();
glBegin(format);
glColor3f(0, 0, 1);
glVertex2f(point[5][0], point[5][1]);
glVertex2f(point[6][0], point[6][1]);
glVertex2f(point[4][0], point[4][1]);
glEnd();
}
void drawScene()
{
glBegin(GL_QUADS);
//red color
glColor3f(1.0,0.0,0.0);
glVertex2f(-1.0,-1.0);
glVertex2f(1.0,-1.0);
//blue color
glColor3f(0.0,0.0,1.0);
glVertex2f(1.0, 1.0);
glVertex2f(-1.0, 1.0);
glEnd();
}
Thanks a lot!
So I take glMatrixMode() and glLoadIdentity() out of drawScene() and drawI() and put them in display(). I changed drawScene() and drawI() above, and here is my display()
void display()
{
glMatrixMode(GL_PROJECTION);
glLoadIdentity();
gluPerspective(70.f,1.f,0.001f,30.f);
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
drawScene();
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
gluLookAt(0.f,0.f,3.f,0.f,0.f,0.f,0.f,1.f,0.f);
drawI(GL_TRIANGLE_FAN);
glutSwapBuffers();
}
The normal way to do this (in a 3D mode) is in your code, before you call drawI or drawScene would be:
glMatrixMode(GL_PROJECTION);
glLoadIdentity();
gluPerspective(fov, aspect, near, far); // fov is camera angle in degrees, aspect is width/height of your viewing area, near and far are your near and far clipping planes.
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
gluLookAt(0.0,0.0,3.0,0.0,0.0,0.0,0.0,1.0,0.0)
In your 2D rendering, you probably don't need the call to gluPerspective, but these calls should be done in your code before you call drawI or drawScene. Do this and delete the glMatrixMode() and glLoadIdentity() calls from drawI and drawScene.
Edit:
If your "I" is still too big, there are a number of things you could do, but you should probably be operating in 3D (giving a Z coordinate also).
You could scale the object:
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
gluLookAt(0.0,0.0,3.0,0.0,0.0,0.0,0.0,1.0,0.0)
glScalef(0.5, 0.5, 0.5);
You could move the camera further back (you'll need to include the gluPerspective() call as well):
gluLookAt(0.0,0.0,50.0,0.0,0.0,0.0,0.0,1.0,0.0);
Perhaps the easiest way to control the rendered image size in a 3D mode is to both move the camera (eye) back a way and then control the image size by changing the camera aperture angle (fov in the gluPerspective() call). A wider fov will shrink the rendered image; a smaller fov will enlarge it.
I don't know what the values for your coordinates are in drawI since they're variables, but a camera position of 3.0, an fov of 70.0 and an aspect of 1 should give you left, right, top and bottom clipping planes of about +/- 2.1 at Z = 0.
If you kept everything else the same and moved the camera to 50.0, the clipping planes would be at about +/- 35.0, so your "I" would occupy a much smaller portion of the viewing area.
If you then left the camera position at 50.0, but changed the fov to 40.0, the clipping planes would be at about +/- 18.2. Your "I" would fill a larger area than it did at cameraZ = 50.0, fov = 70.0, but a smaller area than cameraZ = 3.0, fov = 70.0.
You can play with camera position and fov to get the image size you want, or you could just scale the image. I like to keep camera position constant and change the fov. If I provide a function that changes the fov based on user input (maybe a mouse scroll), it's a good way to provide a zoom in/out effect.
BTW, in your original code, if you called:
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
gluLookAt(0.0,0.0,3.0,0.0,0.0,0.0,0.0,1.0,0.0)
Then later in DrawI or drawScene call:
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
You've trashed the matrix loaded by your earlier call to gluLookAt().

Understanding the window coordinates' interpretation in OpenGL

I was trying to understand OpenGL a bit more deep and I got stuck with below issue.
This segment describes my understanding, and the outputs are as assumed.
glViewport(0, 0 ,800, 480);
glMatrixMode(GL_PROJECTION);
glLoadIdentity();
glFrustum(-400.0, 400.0, -240.0, 240.0, 1.0, 100.0);
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
glTranslatef(0, 0, -1);
glRotatef(0, 0, 0, 1);
glBegin(GL_QUADS);
glVertex3f(-128, -128, 0.0f);
glVertex3f(128, -128, 0.0f);
glVertex3f(128, 128, 0.0f);
glVertex3f(-128, 128, 0.0f);
glEnd();
The window coordinates (Wx, Wy, Wz) for the above snippet are
(272.00000286102295, 111.99999332427979, 5.9604644775390625e-008)
(527.99999713897705, 111.99999332427979, 5.9604644775390625e-008)
(527.99999713897705, 368.00000667572021, 5.9604644775390625e-008)
(272.00000286102295, 368.00000667572021, 5.9604644775390625e-008)
I did a glReadPixels() and dumped to a bmp file. In the image I get a quad as expected with the (Wx, Wy) mentioned above ( since incase of images, the origin is at the top left, while verifying the bmp image I took care of subtracting the the window height i.e 480). This output was as per my understanding - (Wx, Wy) will be used as a 2D coordinate and Wz will be used for depth purpose.
Now comes the issue. I tried the below code snippet.
glViewport(0, 0 ,800, 480);
glMatrixMode(GL_PROJECTION);
glLoadIdentity();
glFrustum(-400.0, 400.0, -240.0, 240.0, 1.0, 100.0);
glMatrixMode(GL_MODELVIEW);
glLoadIdentity();
glTranslatef(100, 0, -1);
glRotatef(30, 0, 1, 0);
glBegin(GL_QUADS);
glVertex3f(-128, -128, 0.0f);
glVertex3f(128, -128, 0.0f);
glVertex3f(128, 128, 0.0f);
glVertex3f(-128, 128, 0.0f);
glEnd()
The window coordinates for the above snippet are
(400.17224205479812, 242.03174613770986, 1.0261343689191909)
(403.24386530741430, 238.03076912806583, 0.99456100555566640)
(403.24386530741430, 241.96923087193414, 0.99456100555566640)
(400.17224205479812, 237.96825386229017, 1.0261343689191909)
When I dumped output to a bmp file, I expected to have a very small parallelogram(approx like a 4 x 4 square transformed to a parallelogram) based on the above (Wx, Wy). But this was not the case. The image had a different set of coordinates as below
(403, 238)
(499, 113)
(499, 366)
(403, 241)
I have mentioned the coordinates in CW direction as seen on the image.
I got lost here. Can anyone please help in understanding what and why it is happening in the 2nd case??
How come I got a point (499, 113) on the screen when it was no where in the calculated window coordinates?
I used gluProject() to the window coordinates.
Note : I'm using OpenGL 2.0. I'm just trying to understand the concepts here, so please don't suggest to use versions > OpenGL 3.0.
edit
This is an update for the answer posted by derhass
The homogenous coordinates after the projection matrix for the 2nd case is as follows
(-0.027128123630699719, -0.53333336114883423, -66.292930483818054, -63.000000000000000)
(0.52712811245482882, -0.53333336114883423, 64.292930722236633, 65.00000000000000)
(0.52712811245482882, 0.53333336114883423, 64.292930722236633, 65.000000000000000)
(-0.027128123630699719, 0.53333336114883423, -66.292930483818054, 63.000000000000000)
So here for the vertices where z > -1, the vertices will get clipped at the near plane. When this is the case, shouldn't GL use the projected point at z = -1 plane?
The thing you are missing here is clipping.
After this
glMatrixMode(GL_PROJECTION);
glLoadIdentity();
glFrustum(-400.0, 400.0, -240.0, 240.0, 1.0, 100.0);
you basically have a camera at origin, looking along the -z direction, and the near plane at z=-1, the far plane at z=-100. Now you draw a 128x128 square rotated at 30 degrees aliong the y (up) axis, and shifted by -1 along z (and 100 along x, but that is not the crucial point here). Since You rotated the square around its center point, the z value for two of the points will be way before the near plane, while the other two should fall into the frustum. (And you can also see that as those two points match your expectations).
Now directly projecting all 4 points to window space is not what GL does. It transforms the points to clip space, intersects the primitives with all 6 sides of the viewing frustum and finally projects the clipped primitives into window space for rasterization.
The projection you did is actually only meaningful for points which lie inside the frustum. Two of your points lie behind the camrea, and projecting points behind the camera will create an mirrored image of these points in front of the camera.

OpenGL: GL_QUADS does not draw square

I'm trying to draw a square on the screen but it clearly draws a rectangle.
This is my render code:
glClear(GL_COLOR_BUFFER_BIT);
glTranslatef(0,0,-0.1);
glBegin(GL_QUADS);
glVertex3f(0,0,0);
glVertex3f(1,0,0);
glVertex3f(1,1,0);
glVertex3f(0,1,0);
glEnd();
SDL_GL_SwapBuffers();
And OpenGL Init code:
glClearColor(0,0,0,0.6f);
glMatrixMode(GL_PROJECTION);
glLoadIdentity();
gluPerspective(30,640.0/480.0,.3f,200.0);
glMatrixMode(GL_MODELVIEW);
Why is this happening?
I don't see anywhere in your code where you have set-up the glViewport. I will rather write something like this in your init method:
glViewport(0,0,640,480); // Reset The Current Viewport
glMatrixMode(GL_PROJECTION); // Select The Projection Matrix
glLoadIdentity(); // Reset The Projection Matrix
// Calculate The Aspect Ratio Of The Window
gluPerspective(30.0f,(GLfloat)640/(GLfloat)480,0.3f,200.0f);
glMatrixMode(GL_MODELVIEW); // Select The Modelview Matrix
glLoadIdentity();
also check the second Nehe tutorial it will help you to start with OpenGL for very basic stuff like drawing primitives such as triangle, square etc...
Try using gluOrtho2D to generate a correct orthogonal projection matrix, in your case gluOrtho2D(0,640,0,480), this is assuming you want a square in 2D and not 3D.
This will of course change your coordinate system from (0,1),(0,1) to (0,640),(0,480).