Switch statement for Coke Machine code - c++

Question

I have always used if else statements over switch statements, but I decided I wanted to try a switch out. I did the basic Coke Machine program with a switch and I cannot for the life of me figure out why it does not work how it should. When I use a number 1-5 for my input it continues to give the the switch default error message instead of the case cout statements (such as "You chose Coke"). Obviously something must be wrong that I am not seeing/
#include <iostream>
using namespace std;
int main()
{
int number;
cout << "Beverage List" << endl;
cout << "Coke = 1" << endl;
cout << "Dr. Pepper = 2" << endl;
cout << "Water = 3" << endl;
cout << "Sprite = 4" << endl;
cout << "Lemonade = 5" << endl << endl << endl;
cout << "Enter a number to choose a beverage: ";
cin >> number;
switch (number)
{
case '1':
cout << "You chose Coke";
break;
case '2':
cout << "You chose Dr. Pepper";
break;
case '3':
cout << "You chose Water";
break;
case '4':
cout << "You chose Sprite";
break;
case '5':
cout << "You chose Lemonade";
break;
default:
cout << "Error: Choice was not valid. Here is your money back.";
}
cout << "\n";
system("pause");
return 0;
}

Answer 1

The character '1' is not the same as the number 1.
Change
case '1':
to
case 1:

Answer 2

It looks like your case statements are comparing chars, not integers:
case '5':
Try this instead:
case 5: