Print duplicates of strings - c++

Question

I am working a code that will find the amount of duplicated words from a imported file.
The input stream represents a file containing a series of lines. The function should
examine each line looking for consecutive occurrences of the same token on the same line and
print each duplicated token along how many times it appears consecutively. Non-repeated
tokens are not printed.
Here is what I have:
#include <iostream>
#include <fstream>
#include <cstdlib>
#include <string>
using namespace std;
int main()
{
ifstream in("file.txt");
if (! in)
{
cerr << "Could not open file.txt.";
return EXIT_FAILURE;
}
string str;
int count = 0;
int len=str.length();
while(getline(in,str)){
for(int i = 0; i < len; i++){
if(str.at(i) == str.at(i+1)){
count++;
}
else if(str.at(i) != str.at(i+1)){
i++;
}
}
cout << str << "*" << count << endl;
}
}
The .txt contains:
hello how how are you you you you
I I I am Jack's Jack's smirking smirking smirking smirking smirking revenge
bow wow wow yippee yippee yo yippee yippee yay yay yay
one fish two fish red fish blue fish
It's the Muppet Show, wakka wakka wakka
The output should be:
how*2 you*4
I*3 Jack's*2 smirking*5
wow*2 yippee*2 yippee*2 yay*3
wakka*3

Answer 1

a=list('this is my laptop')
b=list(set(a))
for i in b:
if i==' ':
continue
c=a.count(i)
if c>1:
print('{} is {}'.format(i,c))

Answer 2

#include <iostream>
#include <string>
#include <fstream>
#include <cstdlib>
using namespace std;
int main()
{
ifstream in("file.txt");
if(!in){
cerr << "Could not open file.txt.";
return EXIT_FAILURE;
}
string str;
string str2;
string n;
string tab[100];
string tab3[100];
unsigned int tab2[100];
unsigned int tab4[100];
unsigned int i = 0;
unsigned int k = 0;
unsigned int l = 0;
unsigned int tablenght;
unsigned int tablenght2;
k = 0;
//it reads every line of text in file str2
while(getline(in,str2)){
//it add every line of text str2 to str so you get whole file text
str += str2;
str += ' ';
//you need to add a character to mark where was the new line
str += "0 ";
}
for(i = 0; i < str.length(); i++){
/*you check every single character in string str if that char is not
space than it writes it to string table tab, if that char is space than it
adds one to your index so it will write down the next word in next
index of table tab*/
if(str[i] != ' '){
tab[k] += str[i];
}else{
k++;
//that is for two spaces
if(str[i+1] == ' '){
k--;
}
}
}
//k+1 is actually how many words and indexes you wrote to table tab
tablenght = k+1;
l = 0;
k = 0;
for(i = 0; i < tablenght; i++){
//you need to reset the number of repeats k to zero if you go to another line
if(tab[i] == "0"){
k = 0;
}
//there you get the number k how many times does some word repeats itself
if(tab[i] == tab[i+1]){
k++;
//you need to reset k if tab current is not equal to tab next
}else{
k = 0;
}
//there you store k values into integer table tab2
tab2[l] = k+1;
l++;
}
l = 0;
/*there you need to check if current string of table tab is equal to next string
in table tab and if it is you need to set next string to tab3[l] if you dont do
that you get something like that you*4 you*4 you*4 you*4 instead of only you*4*/
for(i = 0; i < tablenght-1; i++){
if(tab[i] == tab[i+1]){
tab3[l] = tab[i+1];
tab4[l] = tab2[i];
}else{
l++;
}
if(tab[i+1] == "0"){
tab3[l] = tab[i+1];
}
k++;
}
tablenght2 = l;
//there you cout both tables
for(i = 0; i < tablenght2; i++){
/*you need to check if number is bigger than 1 because it need to cout only
the words that repeats itself for more than one time than you need to check
that table tab3 doesnt contain string with zero that we previously added
that we could check later if it needs to go in another line and we
need to check that tab3 index is not empty*/
if(tab4[i] > 1 && tab3[i] != "0" && !tab3[i].empty()){
cout << tab3[i] << "*" << tab4[i] << " ";
}
/*thats the zero that we wrote to table in the begining and that we can now
write a new line*/
if(tab3[i] == "0"){
cout << endl;
}
}
return 0;
}