I've the below XML.
<chapter num="1">
<section level="sect2">
<page>22</page>
</section>
<section level="sect3">
<page>23</page>
</section>
</chapter>
here I'm trying to get the first occurrence of <page>.
I'm using the below XSLT.
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:ntw="Number2Word.uri" exclude-result-prefixes="ntw">
<xsl:output method="html"/>
<xsl:strip-space elements="*"/>
<xsl:variable name="ThisDocument" select="document('')"/>
<xsl:template match="/">
<xsl:text disable-output-escaping="yes"><![CDATA[<!DOCTYPE html>]]></xsl:text>
<html>
<body>
<xsl:apply-templates/>
</body>
</html>
</xsl:template>
<xsl:template match="chapter">
<section class="tr_chapter">
<xsl:value-of select="//page[1]/text()"/>
<div class="chapter">
</div>
</section>
</xsl:template>
</xsl:stylesheet>
but the output that I get all the page valyes printed. I only want the first one.
Current output.
<!DOCTYPE html>
<html>
<body>
<section class="tr_chapter">2223
<div class="chapter">
</div>
</section>
</body>
</html>
the page values are printed here after <section class="tr_chapter">, i want only 22 but I'm getting 2223
here I'm using //page[1]/text(), because I'm not sure that the page comes within the section, it is random.
please let me know how I can get only the first page value.
here is the transformation http://xsltransform.net/3NzcBsR
Try:
<xsl:value-of select="(//page)[1]"/>
http://xsltransform.net/3NzcBsR/1
Note that this gets the value of the first page element in the entire document.
If you want to search the contents of the chapter context element in your template for the first page descendant then use <xsl:value-of select="descendant::page[1]"/> or <xsl:value-of select="(.//page)[1]"/>.
Related
I'm trying to strip all tags from a xml doc and i need to strip all text from a specific node only. For more clearity see the below example:
<root>
<p>My 1st Semester Visual</p>
<p>
<b>Self Reflection</b>
</p>
<p>The activity</p>
<content-block>
<div class="imageWrapper" />
</content-block>
<p id="5fce699db97470099ea6c7e6"> </p>
<content-block>
<div class="carousel">
<div class="carouselHeader" />
<div class="carouselNavbar">
<div class="carouselNavbarThumbnails" />
</div>
</div>
My Space Unit Flyer
</content-block>
<div>
<br />
</div>
</root>
Result:
<root><text>My 1st Semester VisualSelf ReflectionThe activity
My Space Unit Flyer
</text><contentBlocks>2</contentBlocks></root>
Expected result: I also need to remove text that is inside the <content-block>.
<root><text>My 1st Semester VisualSelf ReflectionThe activity
</text><contentBlocks>2</contentBlocks></root>
My xslt:
<xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" encoding="UTF-8" indent="no" omit-xml-declaration="yes"/>
<!-- Strip out white space -->
<xsl:strip-space elements="*"/>
<!-- Strip out all html tags, only leaving text contents -->
<xsl:template match="*">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="root">
<root>
<text>
<xsl:apply-templates/>
</text>
<contentBlocks>
<xsl:if test="//content-block">
<xsl:value-of select="count(//content-block)"/>
</xsl:if>
<xsl:if test="figure">
<xsl:value-of select="count(figure)"/>
</xsl:if>
</contentBlocks>
</root>
</xsl:template>
</xsl:transform>
Thanks in advance
<!-- Add this to your code. It suppresses content-block. -->
<xsl:template match="content-block"/>
I'm trying to transform some xml with content encoded as html entities. I want to output the entity content as valid html.
The xml is like this ..
<?xml version="1.0" encoding="UTF-8"?><memo Version="1.0">
<header>
<meta title="==PROGRAMMING=="/>
<meta favourite="false"/>
<meta uuid="85f94ab2-77a8-XXXXXXXXXXXXXXX"/>
<meta createdTime="1551038092051"/>
</header>
<contents>
<content><p value="memo2" >=====</p><p>https://medium.freecodecamp.org/</p><p>=====</p>
</content>
</contents>
</memo>
I have some xslt as so..
xslt_src = '''
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<head>
<xsl:apply-templates select="memo/header/meta"/>
</head>
<body>
<xsl:apply-templates select="memo/contents"/>
</body>
</html>
</xsl:template>
<xsl:template match="memo/header/meta">
<xsl:apply-templates select="#title"/>
</xsl:template>
<xsl:template match="memo/contents">
<div class='content'>
<xsl:value-of select="content/text()"/>
</div>
</xsl:template>
<xsl:template match="#title">
<span id='title'>
<xsl:value-of select="."/>
</span>
</xsl:template>
</xsl:stylesheet>
'''
I process it with lxml in Python...
_________________________________________________________________python
from lxml import etree
xslt = etree.XML(xslt_src)
transform = etree.XSLT(xslt)
src = open('simple.xml').read()
xml = etree.XML(str.encode(src))
result = transform(xml)
root = result.getroot()
print('-----------------------out 1')
print(etree.tostring(root, pretty_print=True).decode('utf-8'))
print('-----------------------out 2')
content = root.xpath('/html/body/div/text()')
print(content[0])
==============================================================
etree.tostring(root) prints the structured document but leaves the html entities as encoded in the original xml.
-----------------------out 1
<html>
<head>
<span id="title">==PROGRAMMING==</span>
</head>
<body>
<div class="content"><p value="memo2" >=====</p><p>https://medium.freecodecamp.org/</p><p>=====</p>
</div>
</body>
</html>
but if I print root.xpath('/html/body/div/text()')[0] (the node with the html content) I get what I want...
-----------------------out 2
<p value="memo2" >=====</p><p>https://medium.freecodecamp.org/</p><p>=====</p>
=======================================================================
My question is: how can I make etree.tostring(root) replace the html entities with valid html, as is printed when I use the text attribute directly?
Cheers!
bitrat
Instead of:
<xsl:value-of select="content/text()"/>
try:
<xsl:value-of select="content" disable-output-escaping="yes"/>
I am transforming XML files with XSL to HTML files. Is it possible to embed the original XML file in the HTML output? When yes, how is that possible?
Update 1: To make my need better understandable: In my HTML file, I want a form where I can download the original XML file. Therefore I have to embed the original XML file into my HTML file (e.g. as a hidden input field)
Thanks
If you want to copy the nodes through you can simply do <xsl:copy-of select="/"/> where you want to insert them, however, putting arbitrary XML nodes into HTML does not make sense usually. If you want to serialize an XML document to plain text to render it then you can use solutions like http://lenzconsulting.com/xml-to-string/, for instance:
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:import href="http://lenzconsulting.com/xml-to-string/xml-to-string.xsl"/>
<xsl:output method="html" doctype-public="XSLT-compat" omit-xml-declaration="yes" encoding="UTF-8" indent="yes" />
<xsl:template match="/">
<html>
<head>
<title>Test</title>
</head>
<body>
<section>
<h1>Test</h1>
<xsl:apply-templates/>
<section>
<h2>Source</h2>
<pre>
<xsl:apply-templates mode="xml-to-string"/>
</pre>
</section>
</section>
</body>
</html>
</xsl:template>
<xsl:template match="data">
<ul>
<xsl:apply-templates/>
</ul>
</xsl:template>
<xsl:template match="item">
<li>
<xsl:apply-templates/>
</li>
</xsl:template>
</xsl:transform>
transforms an XML input like
<data>
<item att="value">
<!-- comment -->
<foo>bar</foo>
</item>
</data>
into the HTML
<!DOCTYPE html
PUBLIC "XSLT-compat">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Test</title>
</head>
<body>
<section>
<h1>Test</h1>
<ul>
<li>
bar
</li>
</ul>
<section>
<h2>Source</h2><pre><data>
<item att="value">
<!-- comment -->
<foo>bar</foo>
</item>
</data></pre></section>
</section>
</body>
</html>
XML
<books>
<book title="XML Today" author="David Perry" release="2016"/>
<book title="XML and Microsoft" author="David Perry" release="2015"/>
<book title="XML Productivity" author="Jim Kim" release="2015"/>
</books>
The following XSL code iterates through all books by David Perry.
XSL
<xsl:key name="title-search" match="book" use="#author"/>
<xsl:template match="/">
<HTML>
<BODY>
<xsl:for-each select="key('title-search', 'David Perry')">
<DIV>
<xsl:value-of select="#title"/>
</DIV>
</xsl:for-each>
</BODY>
</HTML>
</xsl:template>
HTML output
<HTML>
<BODY>
<DIV>XML Today</DIV>
<DIV>XML and Microsoft</DIV>
</BODY>
</HTML>
Now I would like to iterate not only through all books by David Perry but through all books by any author.
How would a corresponding outer loop look like?
Or in other words: How do I iterate through all values of my title-search key.
The output should be something like this:
<HTML>
<BODY>
<H1>David Perry</H1>
<DIV>XML Today</DIV>
<DIV>XML and Microsoft</DIV>
<H1>Jim Kim</H1>
<DIV>XML Productivity</DIV>
</BODY>
</HTML>
This should do the job:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="title-search" match="book" use="#author"/>
<xsl:template match="/books">
<HTML>
<BODY>
<xsl:apply-templates select="book" />
</BODY>
</HTML>
</xsl:template>
<xsl:template match="book">
<xsl:variable name="author" select="#author" />
<xsl:if test="generate-id(.) = generate-id(key('title-search', $author)[1])">
<H1><xsl:value-of select="#author" /></H1>
<xsl:apply-templates select="//book[#author = $author]" mode="titles"/>
</xsl:if>
</xsl:template>
<xsl:template match="book" mode="titles">
<DIV>
<xsl:value-of select="#title"/>
</DIV>
</xsl:template>
</xsl:stylesheet>
It uses a technique called Muenchian grouping. Each element in an XML document implicitly has a unique ID assigned to it by the XSLT processor (it can also be explicitly assigned with the id attribute in the document itself). This part:
generate-id(.) = generate-id(key('title-search', $author)[1])
basically tests if the ID of the current book element is the same as that of the first book element with the same author. The variable $author is taken from the current book, The key is used to look up the <book> elements with that same author, the [1] predicate takes the first one. As a result, the <H1> is only generated for the first occurrence of that specific author, and in that same if element we're then applying the template for listing the books of that author. The mode is used to avoid a clash between these templates. There's no doubt a solution that doesn't use modes, but this works too. You could also do a lot of this with <xsl:for-each> but I made separate templates because XSLT is declarative and works best when treating it as such.
Grouping is a lot easier in XSLT 2, but when stuck with XSLT 1, the Muenchian grouping technique often provides a solution once you grok it.
Try this:
XSLT2:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="/">
<HTML>
<BODY>
<xsl:for-each-group select="books/book" group-by="#author">
<H1><xsl:value-of select="current-grouping-key()"/></H1>
<xsl:for-each select="current-group()">
<DIV><xsl:value-of select="#title"/></DIV>
</xsl:for-each>
</xsl:for-each-group>
</BODY>
</HTML>
</xsl:template>
</xsl:stylesheet>
EXAMPLE
Here is an example from MSDN. It show how to transform a XML file into HTML using xsl:key.
Example XML (input)
<books>
<book title="XML Today" author="David Perry" release="2016"/>
<book title="XML and Microsoft" author="David Perry" release="2015"/>
<book title="XML Productivity" author="Jim Kim" release="2015"/>
</books>
Example XSL (input)
<xsl:key name="title-search" match="book" use="#author"/>
<xsl:template match="/">
<HTML>
<BODY>
<xsl:for-each select="key('title-search', 'David Perry')">
<DIV>
<xsl:value-of select="#title"/>
</DIV>
</xsl:for-each>
</BODY>
</HTML>
</xsl:template>
Example HTML (output)
<HTML>
<BODY>
<DIV>XML Today</DIV>
<DIV>XML and Microsoft</DIV>
</BODY>
</HTML>
MY PROBLEM
I would like to produce the same HTML output but using a different XML input. How should the corresponding XSL file look like?
My XML (input)
<books>
<book>
<a n="author"><s>David Perry</s></a>
<a n="title"><s>XML Today</s></a>
<a n="release"><i>2016</i></a>
</book>
<book>
<a n="author"><s>David Perry</s></a>
<a n="title"><s>XML and Microsoft</s></a>
<a n="release"><i>2015</i></a>
</book>
<book>
<a n="author"><s>Jim Kim</s></a>
<a n="title"><s>XML Productivity</s></a>
<a n="release"><i>2015</i></a>
</book>
</books>
My XSL (input)
???
My HTML (output)
<HTML>
<BODY>
<DIV>XML Today</DIV>
<DIV>XML and Microsoft</DIV>
</BODY>
</HTML>
In the first example, your key matched book elements by their author attribute, but in the new XML, you want to match them by the a element where the n attribute is "author", so the key looks like this.
<xsl:key name="title-search" match="book" use="a[#n='author']/s"/>
Then, to get the title for the a matched book you would do this...
<xsl:value-of select="a[#n='title']/s"/>
Therefore your XSLT would look like this:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html" />
<xsl:key name="title-search" match="book" use="a[#n='author']/s"/>
<xsl:template match="/">
<HTML>
<BODY>
<xsl:for-each select="key('title-search', 'David Perry')">
<DIV>
<xsl:value-of select="a[#n='title']/s"/>
</DIV>
</xsl:for-each>
</BODY>
</HTML>
</xsl:template>
</xsl:stylesheet>
You could actually drop the /s in the expressions here, if the s element was only ever going to be the only element under each a element.
This would work too:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html" />
<xsl:key name="title-search" match="book" use="a[#n='author']"/>
<xsl:template match="/">
<HTML>
<BODY>
<xsl:for-each select="key('title-search', 'David Perry')">
<DIV>
<xsl:value-of select="a[#n='title']"/>
</DIV>
</xsl:for-each>
</BODY>
</HTML>
</xsl:template>
</xsl:stylesheet>
This is basic XSLT transformation, you can do something like this:
<xsl:template match="book">
<div>
Author: <xsl:value-of select="a[#n='author']/s" />
title: <xsl:value-of select="a[#n='title']/s" >
release: <xsl:value-of select="a[#n='release']/s" >
</div>
</xsl:template>