qt setmodal does not work - c++

I am trying to set this QT UI to be "modal less", I tried setModal(false), but unfortunately it does not work. meanings: it compiles and runs but I still cannot have the child UI and parent to work in parallel. I am using QT 4.8. On Visual Studio 2010. Here is my code:
realtimedlg::realtimedlg(QWidget *parent)
{
ui.setupUi(this);
parentWnd = parent;
init();
timer1.start(100, this);
this->setModal(false); // this does not do anything!
}

You don't need to call setModal(false) at all, because false is default value already.
As stated in the Qt docs:
This property holds whether show() should pop up the dialog as modal
or modeless.
By default, this property is false and show() pops up the dialog as
modeless. Setting his property to true is equivalent to setting
QWidget::windowModality to Qt::ApplicationModal.
exec() ignores the value of this property and always pops up the
dialog as modal.
So, when you instantiate your realtimedlg object your should do this from the heap and just call show() method:
realtimedlg* dlg = new realtimedlg(this);
dlg->show();
You don't need to call exec(). Calling of it makes your dialog modal.

Related

Where to initialize a rich edit control on another dialog?

I have an MFC dialog based application that has 2 Dialogs: Main Dialog CMyDlgand Second dialog CMyDlg2.
On the main Dialog I add a Button "Go dialog 2". So I added a handler for the button so that when clicked it pops up the second dialog. Everything works fine But on the second Dialog I have added a Rich Edit Control from toolbox. I Added for it a variable. I also added a class for the second dialog.
Now If I run the Application I get the dialog one and if I pressed "Go to dialog 2" I got what I want. But I need at some point to change the font of the rich edit control but my program crashes.
So I overrided OnInitDialog and inside it do some changes to the control but program crashes. After debugging I found that the handle of rich edit is null?!
So how and where can I change the color or do some initializations to the control?
(I called AfxInitRichEdit2() in OnInitInstance())
BOOL CMyDlg2::OnInitDialog() {
m_richEdit.SetWindowText("Hello there!"); // program crashes because the handle m_richEdit is null.
return TRUE;
}
And this is the handler of button that creates the Dialog2 and that contains the rich edit control:
void CMyDlg::OnBnClickedButton1(){
CMyDlg2 theDlg;
theDlg.DoModal();
// TODO: Add your control notification handler code here
}
If I create the rich edit control programmatically then everything works fine because I create it at OnInitDialog and then it works fine but I need the one that is I added using the wizard toolbox.
*** The thing is that if I write:
m_richEdit.SetWindowText(""); // program crashes but if I wirte:
GetDlgItem(IDC_RICHEDIT221).SetWindowText(""); it works fine?
You probably have the following code inserted by wizard:
void DoDataExchange(CDataExchange* pDX)
{
CDialogEx::DoDataExchange(pDX);
DDX_Control(pDX, IDC_RICHEDIT22, m_richEdit);
}
This tells the dialog to associate m_richEdit with the dialog control IDC_RICHEDIT22. But this association is not performed until the base class method CDialog::OnInitDialog(); is called.
BOOL CMyDlg2::OnInitDialog()
{
//this line should work:
GetDlgItem(IDC_RICHEDIT22)->SetWindowText("Hello");
//this line won't work:
//m_richEdit.SetWindowText("Hello there!"); <- richedit's handle is NULL
//this line will subclass m_richEdit
//plus run other initialization
CDialog::OnInitDialog();
//m_richEdit is ready
m_richEdit.SetWindowText("Hello there!");
return TRUE;
}
It's recommended to put CDialog::OnInitDialog() int the first line, to make sure the initialization is done.
GetDlgItem works because the control IDC_RICHEDIT22 exists in the dialog template and you have a valid dialog handle. You are basically making a simple call based on WinAPI's GetDlgItem:
HWND hedit = ::GetDlgItem(m_hWnd, IDC_RICHEDIT22);
::SetWindowText(hedit, "Hello world");
There is no additional initialization needed.
But m_richEdit is just a C++ object, declared as CRichEditCtrl m_richEdit; The constructor for this C++ class doesn't do much besides setting m_hWnd to NULL.
Once it's associated with a valid window handle, we can begin using its windows methods such as CRichEdit::SetWindowText

How to disable minimizing by taskbar icon click

I've stumbled across very strange behaviour during work on my program.
I've written custom changeEvent class, which allows me to hide program to SysTray on minimizing.
But when i double click on taskbar app icon, the function goes crazy. It creates 2 to 4 systray icons and on requesting window show again, it just shows main window borders without any content inside.
Here's my changeEvent code:
void MainWindow::changeEvent(QEvent *e) {
QMainWindow::changeEvent(e);
if(e->type()==QEvent::WindowStateChange)
if(isMinimized()) {
trayIcon=new QSystemTrayIcon(QIcon(":/icon/itime.ico"));
connect(trayIcon,SIGNAL(activated(QSystemTrayIcon::ActivationReason)),this,SLOT(on_show(QSystemTrayIcon::ActivationReason)));
QAction *showAction=new QAction("Pokaż",trayIcon);
connect(showAction,SIGNAL(triggered()),this,SLOT(on_show()));
QMenu *trayIconMenu=new QMenu;
trayIconMenu->addAction(showAction);
trayIcon->setContextMenu(trayIconMenu);
trayIcon->show();
this->hide();
}
}
on_show(QSystemTrayIcon::ActivatioReason) SLOT:
void MainWindow::on_show(QSystemTrayIcon::ActivationReason reason) {
if(reason) {
if(reason!=QSystemTrayIcon::DoubleClick)
return;
}
if(this->isMinimized()) {
this->raise();
this->showNormal();
this->setWindowState(Qt::WindowActive);
trayIcon->hide();
}
}
on_show() SLOT is just the same besides that first if.
Soo, I would like to know whether there is any way to disable minimizing of window by taskbar icon click.
If there's none, then maybe you have any ideas what can go wrong in here when doubleclicking on icon in taskbar?
Thanks for help!
I've managed to work around that problem by overloading closeEvent function and leaving alone changeEvent function.
So, I'm using boolean flag to distinct between closing of program by menu item and by clicking "X" button and the rest stays just the same, as posted in my earlier post with one change.
I've moved this whole block of code to window constructor in order to prevent multiple creation of trayIcon, as pointed out by Nicolas.
trayIcon=new QSystemTrayIcon(QIcon(":/icon/itime.ico"));
connect(trayIcon,SIGNAL(activated(QSystemTrayIcon::ActivationReason)),this,SLOT(on_show(QSystemTrayIcon::ActivationReason)));
QAction *showAction=new QAction("Pokaż",trayIcon);
connect(showAction,SIGNAL(triggered()),this,SLOT(on_show()));
QMenu *trayIconMenu=new QMenu;
trayIconMenu->addAction(showAction);
trayIcon->setContextMenu(trayIconMenu);
Thanks for your help!

Display the input of QLineEdit in a different window and or dialog?

I am writing a small QT gui application where there is a QLineEdit in my mainwindow.ui and I want to display the entered text in a separate dialog and or window when a button is pressed.
Now, I have stored the input in a variable, and I am also able to show this string on a label within this same mainwindow,
void MainWindow::on_GoButton_clicked()
{
QString mytext = ui->lineEdit_1->text();
ui->label_1->setText(mytext);
}
Now, I want to open a popup dialog (can be a window also), for example SecDialog;
SecDialog secdialog;
secdialog.setModal(true);
secdialog.exec();
and display the text of mainwindow->mytext string variable in a label of the SecDialog. How can I do that ??? I know it is a basic level question, but I think it will help clear lot of my doubts reagrding moving values of variables in between forms and classes.
Situation
So this is your situation:
From your code, the dialog is a modal dialog:
SecDialog secdialog;
//secdialog.setModal(true); // It's not needed since you already called exec(), and the
// dialog will be automatically set to be modal just like what
// document says in Chernobyl's answer
secdialog.exec();
Solution
To make the dialog display the text from the Window,
the concept is to pass the information(text) from the Window
to the dialog, and use a setter function from the dialog to display it.
Like Floris Velleman's answer, he passed the mytext string (by reference) to a customized dialog constructor and called the setter theStringInThisClass(myString) at once.
The implementation detail of this function is complemented by Chernobyl's answer (use the name setLabelText instead):
void SecDialog::setLabelText(QString str)
{
ui->label->setText(str); // this "ui" is the UI namespace of the dialog itself.
// If you create the dialog by designer, it's from dialog.ui
// Do not confuse with the ui from mainwindow.ui
}
Chernobyl suggested another way which calls the setter in the slot function and it bypasses the need of defining another constructor, but basically the concept is the same:
void MainWindow::on_GoButton_clicked()
{
QString mytext = ui->lineEdit_1->text();
ui->label_1->setText(mytext);
SecDialog secdialog;
secdialog.setLabelText(myText); // display the text in dialog
secdialog.exec();
}
Comment
I try to illustrate the concept as clear as possible, because from my previous experience on your question, you just "copy & paste" codes from answers and took them as your final solution, which is not right. So I hope this summary could help you understand the concept and then you may write your own code.
This task can be easy done with getter/setter method or with signal and slot, but setter is more suitable here. In SecDialog header:
public:
void setLabelText(QString str);
//in cpp
void SecDialog::setLabelText(QString str)
{
ui->label->setText(str);//it is label dialog
}
Usage:
secDialog.setLabelText(myText);
Also line where you set modal to true is not necessary because
This property holds whether show() should pop up the dialog as modal
or modeless. By default, this property is false and show() pops up the
dialog as modeless. Setting his property to true is equivalent to
setting QWidget::windowModality to Qt::ApplicationModal. exec()
ignores the value of this property and always pops up the dialog as
modal.
Assuming SecDialog is a custom class with an interface file as well you might want to pass it as a constructor argument or pass it by using another function.
So in the SecDialog constructor you could have something like:
SecDialog::SecDialog(QWidget* parent, const QString& myString)
: QDialog(parent),
theStringInThisClass(myString)
{}
And then you could call it like:
SecDialog secdialog(this, mytext);

How to create dialog without blocking main form?

For now I can do:
void MainWindow::on_actionPATH_triggered() {
std::unique_ptr<QDialog> win(new QDialog());
win->exec();
}
Should I use async / run in separate threadto avoid blocking main window or is there way to subscribe to close even and delete / free object there?
You can use just show()
void MainWindow::on_actionPATH_triggered() {
QDialog* win = new QDialog();
//needed connect
win->setAttribute(Qt::WA_DeleteOnClose);//we don't want memory leak
win->show();
}
and use
win->setModal(false);//but it is default option, you don't need to change it
From doc:
By default, this property is false and show() pops up the dialog as
modeless. Setting his property to true is equivalent to setting
QWidget::windowModality to Qt::ApplicationModal. exec() ignores the
value of this property and always pops up the dialog as modal.
Qt::WA_DeleteOnClose will delete your dialog, when user close it.
You can also set parent to dialog:
QDialog* win = new QDialog(this);
In this case win will be delete with your mainWindow.
Info about Qt parent child relationship
And you don't need here separate thread.

Qt show modal dialog (.ui) on menu item click

I want to make a simple 'About' modal dialog, called from Help->About application menu. I've created a modal dialog window with QT Creator (.ui file).
What code should be in menu 'About' slot?
Now I have this code, but it shows up a new modal dialog (not based on my about.ui):
void MainWindow::on_actionAbout_triggered()
{
about = new QDialog(0,0);
about->show();
}
Thanks!
You need to setup the dialog with the UI you from your .ui file. The Qt uic compiler generates a header file from your .ui file which you need to include in your code. Assumed that your .ui file is called about.ui, and the Dialog is named About, then uiccreates the file ui_about.h, containing a class Ui_About. There are different approaches to setup your UI, at simplest you can do
#include "ui_about.h"
...
void MainWindow::on_actionAbout_triggered()
{
about = new QDialog(0,0);
Ui_About aboutUi;
aboutUi.setupUi(about);
about->show();
}
A better approach is to use inheritance, since it encapsulates your dialogs better, so that you can implement any functionality specific to the particular dialog within the sub class:
AboutDialog.h:
#include <QDialog>
#include "ui_about.h"
class AboutDialog : public QDialog, public Ui::About {
Q_OBJECT
public:
AboutDialog( QWidget * parent = 0);
};
AboutDialog.cpp:
AboutDialog::AboutDialog( QWidget * parent) : QDialog(parent) {
setupUi(this);
// perform additional setup here ...
}
Usage:
#include "AboutDialog.h"
...
void MainWindow::on_actionAbout_triggered() {
about = new AboutDialog(this);
about->show();
}
In any case, the important code is to call the setupUi() method.
BTW: Your dialog in the code above is non-modal. To show a modal dialog, either set the windowModality flag of your dialog to Qt::ApplicationModal or use exec() instead of show().
For modal dialogs, you should use exec() method of QDialogs.
about = new QDialog(0, 0);
// The method does not return until user closes it.
about->exec();
// In this point, the dialog is closed.
Docs say:
The most common way to display a modal dialog is to call its exec() function. When the user closes the dialog, exec() will provide a useful return value.
Alternative way: You don't need a modal dialog. Let the dialog show modeless and connect its accepted() and rejected() signals to appropriate slots. Then you can put all your code in the accept slot instead of putting them right after show(). So, using this way, you wouldn't actually need a modal dialog.