Adding a time delay to simulate lottery numbers being drawn - c++

Question

new to the forums here and beginning to learn C++. This site has already helped me so much with syntax and other things. What I'm trying to do with my code is have the number print to screen, have the time delay, then print the next number. Currently the time delay works, but it prints all 13 numbers generated. Any ideas of what I'm doing wrong?
Here's my code:
#include <iostream>
#include <iomanip>
#include <stdlib.h>
#include <windows.h>
using namespace std;
int main( )
{
// Function prototypes
int random ( int minValue, int maxValue);
// Constant declarations
const int maxValue = 9;
const int minValue = 0;
// Local variable declarations
int seed;
int numberOfPeople;
int peopleCount = 0;
int numberCount;
int number;
// Initialize the random number generator
cout << "Welcome to the Lottery!" << endl;
cout << "Enter your lucky number to start: " << endl;
cin >> seed;
srand (seed);
// Generate and display numbers
cout << "Enter the number of people participating in the lottery:" << endl;
cin >> numberOfPeople;
cout << "Your lucky lottery numbers for the day are:" << endl;
cout.setf (ios::left, ios::adjustfield);
cout << setw(8) << "Pick 3" << setw(10) << "Pick 4" <<
setw(15) << "Pick 6" << endl;
while (peopleCount < numberOfPeople) {
numberCount = 0;
while (numberCount < 13){
number = random (minValue, maxValue);
Sleep (500); // pauses for half a second
cout << number << " ";
if (numberCount == 2){
cout << " "; }
else if (numberCount == 6){
cout << " "; }
else if (numberCount == 12){
cout << endl; } //end if, else if
numberCount++;
} //end nested while
peopleCount++;
} // end while
return 0;
} // end main()
/**
* Produces a pseudo-random number
* #param minValue minimum value that can be generated
* #param maxValue maximum value that can be generated
*
* #return psuedo-random number in the specified range
*/
int random ( int minValue, // min possible number to be generated
int maxValue) // max possible number to be generated
{
return ( (rand() % maxValue) + minValue);
} // end random()

Answer 1

cout is generally buffered, and the newline causes the buffer to be flushed to the screen. As you display the numbers on the same line, this could explain that everything is displayed at onece despite the delay that you've build in.
Use cout.flush(); to force output to be done without buffering delay. You could as well use the manipulator form: cout << number << " " << flush;