Pyaudio : how to compress audio stream - compression

Question

I'm currently developping a VOIP tool in python working as a client-server as follows :
CHUNK = 1024
p = pyaudio.PyAudio()
stream = p.open(format = pyaudio.paInt16,
channels = 1,
rate = 44100,
input = True,
frames_per_buffer = CHUNK)
while 1:
connection.sendVoice(stream.read(CHUNK))
How could I proceed to compress the sent data to spare connection, maybe increase speed, ...

Answer 1

import time, sys,io
import pymedia.audio.sound as sound
import pymedia.audio.acodec as acodec
import pymedia.muxer as muxer
def voiceRecorder( secs, name ):
f = open(name,'wb')
secs = secs*5
dm= muxer.Demuxer('mp3')
snds= sound.getODevices()
rt = 44100
cparams= { 'id': acodec.getCodecID( 'mp3' ),
'bitrate': 128000/4,
'sample_rate': rt,
'channels': 2 }
ac= acodec.Encoder( cparams )
snd= sound.Input( rt, 2, sound.AFMT_S16_LE )
snd.start()
start_time = time.time()
while snd.getPosition()<= secs:
s= snd.getData()
if s and len( s ):
for fr in ac.encode( s ):
f.write( fr)
else:
time.sleep(.25)
snd.stop()
if __name__ == "__main__":
if len( sys.argv )!= 3:
print 'Usage: voice_recorder <seconds> <file_name>'
else:
voiceRecorder( int( sys.argv[ 1 ] ), sys.argv[ 2 ] )

Answer 2

Wow for my calculations are you sending a little more that 2KB, to be exact 2.0480KB of audio at every loop to your socket connection:
(16 * 44.1 / 8) * 1024/44100 = 2.0480
One simple way to send less data is reducing the chunk size if you change the chunk to 512 now are you sending just a bit more that 1KB.
Another way is try use zlib package in python to compress the stream.read data after send it through your socket, but for it do not forget to unzip in the other side.