using std::async with template functions - c++

Question

How can I, or, can I, pass a template function to async?
Here is the code:
//main.cpp
#include <future>
#include <vector>
#include <iostream>
#include <numeric>
int
main
()
{
std::vector<double> v(16,1);
auto r0 = std::async(std::launch::async,std::accumulate,v.begin(),v.end(),double(0.0));
std::cout << r0.get() << std::endl;
return 0;
}
Here are the error messages:
^
a.cpp:13:88: note: candidates are:
In file included from a.cpp:1:0:
/usr/include/c++/4.8/future:1523:5: note: template std::future::type> std::async(std::launch, _Fn&&, _Args&& ...)
async(launch __policy, _Fn&& __fn, _Args&&... __args)
^
/usr/include/c++/4.8/future:1523:5: note: template argument deduction/substitution failed:
a.cpp:13:88: note: couldn't deduce template parameter ‘_Fn’
auto r0 = std::async(std::launch::async,std::accumulate,v.begin(),v.end(),double(0.0));
^
In file included from a.cpp:1:0:
/usr/include/c++/4.8/future:1543:5: note: template std::future::type> std::async(_Fn&&, _Args&& ...)
async(_Fn&& __fn, _Args&&... __args)
^
/usr/include/c++/4.8/future:1543:5: note: template argument deduction/substitution failed:
/usr/include/c++/4.8/future: In substitution of ‘template std::future::type> std::async(_Fn&&, _Args&& ...) [with _Fn = std::launch; _Args = {}]’:
a.cpp:13:88: required from here
/usr/include/c++/4.8/future:1543:5: error: no type named ‘type’ in ‘class std::result_of’

Answer 1

The problem is that to pass the second argument to std::async the compiler has to turn the expression &std::accumulate into a function pointer, but it doesn't know which specialization of the function template you want. To a human it's obvious you want the one that can be called with the remaining arguments to async, but the compiler doesn't know that and has to evaluate each argument separately.
As PiotrS.'s answer says, you can tell the compiler which std::accumulate you want with an explicit template argument list or by using a cast, or alternatively you can just use a lambda expression instead:
std::async(std::launch::async,[&] { return std::accumulate(v.begin(), v.end(), 0.0); });
Inside the body of the lambda the compiler performs overload resolution for the call to std::accumulate and so it works out which std::accumulate to use.

Answer 2

You have to disambiguate between possible instantiations by either explicitly passing the template arguments or using static_cast, so:
auto r0 = std::async(std::launch::async
, &std::accumulate<decltype(v.begin()), double>
, v.begin()
, v.end()
, 0.0);
or:
auto r0 = std::async(std::launch::async
, static_cast<double(*)(decltype(v.begin()), decltype(v.end()), double)>(&std::accumulate)
, v.begin()
, v.end()
, 0.0);