How can I use %SCAN within a macro variable name? - sas

I'm trying to write robust code to assign values to macro variables. I want the names of the macro variables to depend on values coming from the variable 'subgroup'. So subgroup could equal 1, 2, or 45 etc. and thus have macro variable names trta_1, trta_2, trt_45 etc.
Where I am having difficulty is calling the macro variable name. So instead of calling e.g. &trta_1 I want to call &trta_%SCAN(&subgroups, &k), which resolves to trta_1 on the first iteration. I've used a %SCAN function in the macro variable name, which is throwing up a warning 'WARNING: Apparent symbolic reference TRTA_ not resolved.'. However, the macro variables have been created with values assigned.
How can I resolve the warning? Is there a function I could run with the %SCAN function to get this to work?
data data1 ;
input subgroup trta trtb ;
datalines ;
1 30 58
2 120 450
3 670 3
run;
%LET subgroups = 1 2 3 ;
%PUT &subgroups;
%MACRO test;
%DO k=1 %TO 3;
DATA test_&k;
SET data1;
WHERE subgroup = %SCAN(&subgroups, &k);
CALL SYMPUTX("TRTA_%SCAN(&subgroups, &k)", trta, 'G');
CALL SYMPUTX("TRTB_%SCAN(&subgroups, &k)", trtb, 'G');
RUN;
%PUT "&TRTA_%SCAN(&subgroups, &k)" "&TRTB_%SCAN(&subgroups, &k)";
%END;
%MEND test;
%test;

Using the structure you've provided the following will achieve the result you're looking for.
data data1;
input subgroup trta trtb;
datalines;
1 30 58
2 120 450
3 670 3
;
run;
%LET SUBGROUPS = 1 2 3;
%PUT &SUBGROUPS;
%MACRO TEST;
%DO K=1 %TO 3;
%LET X = %SCAN(&SUBGROUPS, &K) ;
data test_&k;
set data1;
where subgroup = &X ;
call symputx(cats("TRTA_",&X), trta, 'g');
call symputx(cats("TRTB_",&X), trtb, 'g');
run;
%PUT "&&TRTA_&X" "&&TRTB_&X";
%END;
%MEND TEST;
%TEST;
However, I'm not sure this approach is particularly robust. If your list of subgroups changes you'd need to change the 'K' loop manually, you can determine the upper bound of the loop by dynamically counting the 'elements' in your subgroup list.
If you want to call the macro variables you've created later in your code, you could a similar method.
data data2;
input subgroup value;
datalines;
1 20
2 25
3 15
45 30
;
run ;
%MACRO TEST2;
%DO K=1 %TO 3;
%LET X = %SCAN(&SUBGROUPS, &K) ;
data data2 ;
set data2 ;
if subgroup = &X then percent = value/&&TRTB_&X ;
format percent percent9.2 ;
run ;
%END;
%MEND TEST2;
%TEST2 ;
Effectively, you're re-writing data2 on each iteration of the loop.

This should cover your requirements. You can load and unload an array of macro variable without a macro. I have included an alternate method of unloading a macro variable array with a macro for comparison.
Load values into macro variables including Subgroup number within macro variable name e.g. TRTA_45.
data data1;
input subgroup trta trtb;
call symput ('TRTA_'||compress (subgroup), trta);
call symput ('TRTB_'||compress (subgroup), trtb);
datalines;
1 30 58
2 120 450
3 670 3
45 999 111
;
run;
No need for macro to load or refer to macro variables.
%put TRTA_45: &TRTA_45.;
%let Subgroup_num = 45;
%put TRTB__&subgroup_num.: &&TRTB_&subgroup_num.;
If you need to loop through the macro variables then you can use Proc SQL to generate a list of subgroups.
proc sql noprint;
select subgroup
, count (*)
into :subgroups separated by ' '
, :No_Subgroups
from data1
;
quit;
%put Subgroups: &subgroups.;
%put No_Subgroups: &No_Subgroups.;
Use a macro to loop through the macro variable array and populate a table.
%macro subgroups;
data subgroup_data_macro;
%do i = 1 %to &no_subgroups.;
%PUT TRTA_%SCAN(&subgroups, &i ): %cmpres(&TRTA_%SCAN(&subgroups, &i ));
%PUT TRTB_%SCAN(&subgroups, &i ): %cmpres(&TRTB_%SCAN(&subgroups, &i ));
subgroup = %SCAN(&subgroups, &i );
TRTA = %cmpres(&TRTA_%SCAN(&subgroups, &i ));
TRTB = %cmpres(&TRTB_%SCAN(&subgroups, &i ));
output;
%end;
run;
%mend subgroups;
%subgroups;
Or use a data step (outside a macro) to loop through the macro variable array and populate a table.
data subgroup_data_sans_macro;
do i = 1 to &no_subgroups.;
subgroup = SCAN("&subgroups", i );
TRTA = input (symget (compress ('TRTA_'||subgroup)),20.);
TRTB = input (symget (compress ('TRTB_'||subgroup)),20.);
output;
end;
run;
Ensure both methods (within and without a macro) produce the same result.
proc compare
base = subgroup_data_sans_macro
compare = subgroup_data_macro
;
run;

Related

sas macro : how to make multiful column using macro?

I'm SAS user.
I want to assign year columns using date values.
for example, here is my code, below.
I want to make Y_2010, Y_2011, Y_2012 , Y_2013, Y_2014 in work.total data set.
but there is only Y_2014 as a result.
How can I change the code as I can get right result which I intended first?
options mcompilenote = all;
%let a = Y_ ;
%macro B(YMIN, YMAX) ;
%do i = &YMIN %to &YMAX ;
DATA TOTAL ;
SET SASUSER.EMPDATA ;
IF YEAR(HIREDATE) = &i THEN &a&i = 1 ;
ELSE &a&i = 0 ;
RUN;
%end;
%mend;
%B (2010, 2014) ;
Because you are repeatedly re-creating the output dataset only the final version is available. To fix the macro move the %DO loop inside the DATA step so that you are generating all of the variables in a single data step.
%macro B(YMIN, YMAX) ;
DATA TOTAL ;
SET SASUSER.EMPDATA ;
%do i = &YMIN %to &YMAX ;
IF YEAR(HIREDATE) = &i THEN &a&i = 1 ;
ELSE &a&i = 0 ;
%end;
RUN;
%mend;
But there is no need to a macro for this. Just use normal SAS statements. For example you could use an ARRAY statement to define the variables and then loop over the array and set the values. Note that the result of a boolean expression in SAS is 0 when false and 1 when true so you can eliminate the IF/THEN/ELSE statement and just use an assignment statement.
DATA TOTAL ;
SET SASUSER.EMPDATA ;
array &a &a&ymin - &a&ymax;
do i=&ymin to &ymax ;
&a[i-&ymin+1] = (year(hiredata)=i);
end;
drop i;
RUN;

space separated list intersection

Note: code edited after remarks from #user667489 but issues remain.
I built a fairly simple macro to return the intersection of 2 space separated lists as a new space separated list but for some reason the definition of the macro returns errors.
The macro loops through both lists and keep an element if a match is found (very straightforward, no handling of duplicates or optimization).
I cannot make sense of the log, which shows a combination of following error messages:
ERROR: Macro keyword LET appears as text.
ERROR: Macro keyword MACRO appears as text.
%macro list_intersection
(list1= /* space separated list, or unique term */
,list2= /* space separated list, or unique term */
);
%local output;
%local i;
%local j;
%let i = 1;
%let j = 1;
%do %while (%length(%scan(&list1,&i)));
%do %while (%length(%scan(&list2,&j)));
%if (%scan(&list1,&i) = %scan(&list2,&j)) %then
%let output = &output %scan(&list1,&i);
%let j = %eval(&j+1);
%end;
%let i = %eval(&i+1);
%end;
&output
%mend;
Can you help me circling the issue ?
I'm also open to a more efficient/robust/simple way of achieving the same output.
Reproducible log
Using SAS 9.3, I put above code in a separate program for it not to be polluted, save project, close and reopen. Open program, click run button, and here is the complete log:
1 The SAS System 09:50 Monday, January 22, 2018
1 ;*';*";*/;quit;run;
2 OPTIONS PAGENO=MIN;
3 %LET _CLIENTTASKLABEL='Program3';
ERROR: Macro keyword LET appears as text.
4 %LET _CLIENTPROJECTPATH='F:\CI\Projects\Wealth Indicators\106 Explore DIM_PHYSICALPERSON\SAS\Rework_table_auto2.egp';
ERROR: Macro keyword LET appears as text.
5 %LET _CLIENTPROJECTNAME='Rework_table_auto2.egp';
ERROR: Macro keyword LET appears as text.
6 %LET _SASPROGRAMFILE=;
ERROR: Macro keyword LET appears as text.
7
8 ODS _ALL_ CLOSE;
9 OPTIONS DEV=ACTIVEX;
10 GOPTIONS XPIXELS=0 YPIXELS=0;
11 FILENAME EGSR TEMP;
12 ODS tagsets.sasreport13(ID=EGSR) FILE=EGSR STYLE=HtmlBlue
12 ! STYLESHEET=(URL="file:///C:/Program%20Files/SASHome/x86/SASEnterpriseGuide/5.1/Styles/HtmlBlue.css") NOGTITLE NOGFOOTNOTE
12 ! GPATH=&sasworklocation ENCODING=UTF8 options(rolap="on");
13
14 GOPTIONS ACCESSIBLE;
15 %macro list_intersection
ERROR: Macro keyword MACRO appears as text.
16 (list1= /* space separated list, or unique term */
17 ,list2= /* space separated list, or unique term */
18 );
19 %local output;
ERROR: Macro keyword LOCAL appears as text.
20 %local i;
ERROR: Macro keyword LOCAL appears as text.
21 %local j;
ERROR: Macro keyword LOCAL appears as text.
22 %let i = 1;
ERROR: Macro keyword LET appears as text.
23 %let j = 1;
ERROR: Macro keyword LET appears as text.
24 %do %while (%length(%scan(&list1,&i)));
ERROR: Macro keyword DO appears as text.
25 %do %while (%length(%scan(&list2,&j)));
ERROR: Macro keyword DO appears as text.
26 %if (%scan(&list1,&i) = %scan(&list2,&j)) %then
ERROR: Macro keyword IF appears as text.
27 %let output = &output %scan(&list1,&i);
28 %let j = %eval(&j+1);
ERROR: Macro keyword LET appears as text.
29 %end;
ERROR: Macro keyword END appears as text.
30 %let i = %eval(&i+1);
ERROR: Macro keyword LET appears as text.
31 %end;
ERROR: Macro keyword END appears as text.
32 &output
33 %mend;
ERROR: Macro keyword MEND appears as text.
34
35 GOPTIONS NOACCESSIBLE;
36 %LET _CLIENTTASKLABEL=;
ERROR: Macro keyword LET appears as text.
37 %LET _CLIENTPROJECTPATH=;
2 The SAS System 09:50 Monday, January 22, 2018
ERROR: Macro keyword LET appears as text.
38 %LET _CLIENTPROJECTNAME=;
ERROR: Macro keyword LET appears as text.
39 %LET _SASPROGRAMFILE=;
ERROR: Macro keyword LET appears as text.
40
41 ;*';*";*/;quit;run;
42 ODS _ALL_ CLOSE;
43
44
45 QUIT; RUN;
46
Initial code before edit:
%macro list_intersection
(list1= /* space separated list, or unique term */
,list2= /* space separated list, or unique term */
);
%local output =;
%local i = 1;
%local j = 1;
%do %while (%length(%scan(&list1,&i)));
%do %while (%length(%scan(&list2,&j)));
%if (%scan(&list1,&i) = %scan(&list2,&j) %then
%local output = &output %scan(&list1,&i);
%let j = %eval(&j+1);
%end;
%let i = %eval(&i+1);
%end;
&output
%mend;
A few things immediately stand out:
You cannot use %local to set a value for a macro variable. Instead of %local i=1; you must write two separate statements: %local i; %let i = 1;. %local initialises macro variables to an empty string.
You have unbalanced brackets in your %if statement.
Try moving %let j = %eval(&j+1); into the outer %do %while loop.
Also, you probably want to make sure that %scan only uses space as a delimiter - it defaults to space plus . < ( + & ! $ * ) ; ^ - / , % |
Here's a working version:
%macro list_intersection
(list1= /* space separated list, or unique term */
,list2= /* space separated list, or unique term */
);
%local output;
%local i;
%local j;
%let i = 1;
%do %while (%length(%scan(&list1,&i,%str( ))));
%let j = 1;
%do %while (%length(%scan(&list2,&j,%str( ))));
%if %scan(&list1,&i,%str( )) = %scan(&list2,&j,%str( )) %then
%let output = &output %scan(&list1,&i,%str( ));
%let j = %eval(&j+1);
%end;
%let i = %eval(&i+1);
%end;
&output
%mend;
%put %list_intersection(list1=1 2 3,list2=2 3 4);
You can use SAS functions to make that much easier. Use the COUNTW() function to find the upper bound for the %DO loop. Use the FINDW() function to test if word is found in the other list.
%macro list_intersection
(list1 /* space separated list of terms */
,list2 /* space separated list of terms */
);
%local output i next ;
%do i=1 %to %sysfunc(countw(&list1,%str( ))) ;
%let next=%scan(&list1,&i,%str( ));
%if %sysfunc(findw(&list2,&next,,s)) %then %let output=&output &next ;
%end;
&output
%mend;
You could include the i modifier in the findw() call to make it case insensitive. You could also test if the word is already in the output string to eliminate duplicates.
%macro list_intersection_nodups
(list1 /* space separated list of terms */
,list2 /* space separated list of terms */
);
%local output i next ;
%do i=1 %to %sysfunc(countw(&list1,%str( ))) ;
%let next=%scan(&list1,&i,%str( ));
%if %sysfunc(findw(&list2,&next,,si)) and not %sysfunc(findw(&output,&next,,si))
%then %let output=&output &next ;
%end;
&output
%mend;
Example:
274 %put %list_intersection_nodups(A B a C,a c d);
A C

Increment variable name

Is it possible to increment different prefixed variable names in a simple way? For example, if my dataset has columns for Score1 all the way to Score20, I can simply do:
input Score1-Score20;
But what if I have Score1 Rank1 Total1 to Score20 Rank20 Total20, is there a way to increment these without manually typing out each one? So the result would look like:
Score1 Rank1 Total1 Score2 Rank2 Total2 Score3 Rank3 Total3 etc...
Do you care if the variables are created in a different order than in the input file? If not then use an ARRAY. Try this example.
data x ;
array x(3,20) a1-a20 b1-b20 c1-c20 ;
infile cards truncover;
do block=1 to 20;
do item=1 to 3;
input x(item,block) #;
end;
end;
put (_all_) (=);
list;
cards;
1 1 1 2 2 2 3 3 3 4 4 4 5 5 5
;
If you need them in that order then you need to use some type of code generation.
You could create a simple function style macro to emit the list of names.
%macro namelist(baselist,n);
%local i j;
%do i=1 %to &n ;
%do j=1 %to %sysfunc(countw(&baselist));
%scan(&baselist,&j)&i
%end;
%end;
%mend namelist;
...
input %namelist(Rank Total Score,20) ;
Or you could use a simple data step to build the list into a macro variable.
data _null_;
length i 8 basename $30 namelist $32000;
do i=1 to 20 ;
do basename='Rank ','Total','Score';
namelist=catx(' ',namelist,cats(basename,i));
end;
end;
call symputx('namelist',namelist);
run;
...
input &namelist ;
You could probably do a macro for this. I think this would work:
%macro mymacro(runs);
%do i=1 %to &runs;
input Score&i Rank&i Total&i;
run;
%end;
%mend create;
%mymacro(20)
Try here for better documentation: https://support.sas.com/documentation/cdl/en/mcrolref/61885/HTML/default/viewer.htm#a000543755.htm
The same question was asked here earlier in the week, the answer is the same.
https://communities.sas.com/t5/General-SAS-Programming/Variables-listing/m-p/238350#M34601
You could create a macro to create the names.
data _null_;
length var $1000.;
do i=1 to 10;
var=catt(var, " Total"||put(i, 2. -l), " Male"||put(i, 2. -l), " Female"||put(i, 2. -l));
end;
call symputx('input_list', var);
run;
%put &input_list;

Find three most recent data year for each row

I have a data set with one row for each country and 100 columns (10 variables with 10 data years each).
For each variable I am trying to make a new data set with the three most recent data years for that variable for each country (which might not be successive).
This is what I have so far, but I know its wrong because of the nest loop, and its has same value for recent1 recent2 recent3 however I haven't figured out how to create recent1 recent2 recent3 without two loops.
%macro test();
data Maternal_care_recent;
set wb;
keep country MATERNAL_CARE_2004 -- MATERNAL_CARE_2013 recent_1 recent_2 recent_3;
%let rc = 1;
%do i = 2013 %to 2004 %by -1;
%do rc = 1 %to 3 %by 1;
%if MATERNAL_CARE_&i. ne . %then %do;
recent_&rc. = MATERNAL_CARE_&i.;
%end;
%end;
%end; run; %mend; %test();
You don't need to use a macro to do this - just some arrays:
data Maternal_care_recent;
set wb;
keep country MATERNAL_CARE_2004-MATERNAL_CARE_2013 recent_1 recent_2 recent_3;
array mc {*} MATERNAL_CARE_2004-MATERNAL_CARE_2013;
array recent {*} recent1-recent3;
do i = 2013 to 2004 by -1;
do rc = 1 to 3 by 1;
if mc[i] ne . then do;
recent[rc] = mc[i];
end;
end;
run;
Maybe I don't get your request, but according to your description:
"For each variable I am trying to make a new data set with the three most recent data years for that variable for each country (which might not be successive)" I created this sample dataset with dt1 and dt2 and 2 locations.
The output will be 2 datasets (and generally the number of the variables starting with DT) named DS1 and DS2 with 3 observations for each country, the first one for the first variable, the second one for the second variable.
This is the sample dataset:
data sample_ds;
length city $10 dt1 dt2 8.;
infile datalines dlm=',';
input city $ dt1 dt2;
datalines;
MS,5,0
MS,3,9
MS,3,9
MS,2,0
MS,1,8
MS,1,7
CA,6,1
CA,6,.
CA,6,.
CA,2,8
CA,1,5
CA,0,4
;
This is the sample macro:
%macro help(ds=);
data vars(keep=dt:); set &ds; if _n_ not >0; run;
%let op = %sysfunc(open(vars));
%let nvrs = %sysfunc(attrn(&op,nvars));
%let cl = %sysfunc(close(&op));
%do idx=1 %to &nvrs.;
proc sort data=&ds(keep=city dt&idx.) out=ds&idx.(where=(dt&idx. ne .)) nodupkey; by city DESCENDING dt&idx.; run;
data ds&idx.; set ds&idx.;
retain cnt;
by city DESCENDING dt&idx.;
if first.city then cnt=0; else cnt=cnt+1;
run;
data ds&idx.(drop=cnt); set ds&idx.(where=(cnt<3)); rename dt&idx.=act&idx.; run;
%end;
%mend;
You will run this macro with:
%help(ds=sample_ds);
In the first statement of the macro I select the variables on which I want to iterate:
data vars(keep=dt:); set &ds; if _n_ not >0; run;
Work on this if you want to make this work for your code, or simply rename your variables as DT1 DT2...
Let me know if it is correct for you.
When writing macro code, always keep in mind what has to be done when. SAS processes your code stepwise.
Before your sas code is even compiled, your macro variables are resolved and your macro code is executed
Then the resulting SAS Base code is compiled
Finally the code is executed.
When you write %if MATERNAL_CARE_&i. ne . %then %do, this is macro code interpreded before compilation.
At that time MATERNAL_CARE_&i. is not a variable but a text string containing a macro variable.
The first time you run trhough your %do i = 2013 %to 2004 by -1, it is filled in as MATERNAL_CARE_2013, the second as MATERNAL_CARE_2012., etc.
Then the macro %if statement is interpreted, and as the text string MATERNAL_CARE_1 is not equal to a dot, it is evaluated to FALSE
and recent_&rc. = MATERNAL_CARE_&i. is not included in the code to pass to your compiler.
You can see that if you run your code with option mprint;
The resolution;
options mprint;
%macro test();
data Maternal_care_recent;
set wb;
keep country MATERNAL_CARE_: recent_:;
** The : acts as a wild card here **;
%do i = 2013 %to 2004 %by -1;
if MATERNAL_CARE_&i. ne . then do;
%do rc = 1 %to 3 %by 1;
recent_&rc. = MATERNAL_CARE_&i.;
%end;
end;
%end;
run;
%mend;
%test();
Now, before compilation of if MATERNAL_CARE_&i. ne . then do, only the &i. is evalueated and if MATERNAL_CARE_2013 ne . then do is passed to the compiler.
The compiler will see this as a test if the SAS variable MATERNAL_CARE_1 has value missing, and that is just what you wanted;
Remark:
It is not essential that I moved the if statement above the ``. It is just more efficient because the condition is then evaluated less often.
It is however essential that you close your %ifs and %dos with an %end and your ifs and dos with an end;
Remark:
you do not need %let rc = 1, because %do rc = 1 to 3 already initialises &rc.;
For completeness SAS is compiled stepwise:
The next PROC or data step and its macro code are only considered when the preveous one is executed.
That is why you can write macro variables from a data step or sql select into that will influence the code you compile in your next step,
somehting you can not do for instance with C++ pre compilation;
Thanks everyone. Found a hybrid solution from a few solutions posted.
data sample_ds;
infile datalines dlm=',';
input country $ maternal_2004 maternal_2005
maternal_2006 maternal_2007 maternal_2008 maternal_2009 maternal_2010 maternal_2011 maternal_2012 maternal_2013;
datalines;
MS,5,0,5,0,5,.,5,.,5,.
MW,3,9,5,0,5,0,5,.,5,0
WE,3,9,5,0,5,.,.,.,.,0
HU,2,0,5,.,5,.,5,0,5,0
MI,1,8,5,0,5,0,5,.,5,0
HJ,1,7,5,0,5,0,.,0,.,0
CJ,6,1,5,0,5,0,5,0,5,0
CN,6,1,.,5,0,5,0,5,0,5
CE,6,5,0,5,0,.,0,5,.,8
CT,2,5,0,5,0,5,0,5,0,9
CW,1,5,0,5,0,5,.,.,0,7
CH,0,5,0,5,0,.,0,.,0,5
;
%macro test(var);
data &var._recent;
set sample_ds;
keep country &var._1 &var._2 &var._3;
array mc {*} &var._2004-&var._2013;
array recent {*} &var._1-&var._25;
count=1;
do i = 10 to 1 by -1;
if mc[i] ne . then do;
recent[count] = mc[i];
count=count+1;
end;
end;
run;
%mend;

How to scan a numeric variable

I have a table like this:
Lista_ID 1 4 7 10 ...
in total there are 100 numbers.
I want to call each one of these numbers to a macro i created. I was trying to use 'scan' but read that it's just for character variables.
the error when i runned the following code was
there's the code:
proc sql;
select ID INTO: LISTA_ID SEPARATED BY '*' from
WORK.AMOSTRA;
run;
PROC SQL;
SELECT COUNT(*) INTO: NR SEPARATED BY '*' FROM
WORK.AMOSTRA;
RUN;
%MACRO CICLO_teste();
%LET LIM_MSISDN = %EVAL(NR);
%LET I = %EVAL(1);
%DO %WHILE (&I<= &LIM_MSISDN);
%LET REF = %SCAN(LISTA_ID,&I,,'*');
DATA WORK.UP&REF;
SET WORK.BASE&REF;
FORMAT PERC_ACUM 9.3;
IF FIRST.ID_CLIENTE THEN PERC_ACUM=0;
PERC_ACUM+PERC;
RUN;
%LET I = %EVAL(&I+1);
%END;
%MEND;
%CICLO_TESTE;
the error was that:
VARIABLE PERC IS UNITIALIZED and
VARIABLE FIRST.ID_CLIENTE IS UNITIALIZED.
What I want is to run this macro for each one of the Id's in the List I showed before, and that are referenced in work.base&ref and work.up&ref.
How can I do it? What I'm doing wrong?
thanks!
Here's the CALL EXECUTE version.
%MACRO CICLO_teste(REF);
DATA WORK.UP&REF;
SET WORK.BASE&REF;
BY ID_CLIENTE;
FORMAT PERC_ACUM 9.3;
IF FIRST.ID_CLIENTE THEN PERC_ACUM=0;
PERC_ACUM+PERC;
RUN;
%CICLO_TESTE;
DATA _NULL_;
SET amostra;
*CREATE YOUR MACRO CALL;
STR = CATT('%CLIO_TESTE(', ID, ')');
CALL EXECUTE(STR);
RUN;
First you should note that SAS macro variable resolve is intrinsically a "text-based" copy-paste action. That is, all the user-defined macro variables are texts. Therefore, %eval is unnecessary in this case.
Other miscellaneous corrections include:
Check the %scan() function for correct usage. The first argument should be a text string WITHOUT QUOTES.
run is redundant in proc sql since each sql statement is run as soon as they are sent. Use quit; to exit proc sql.
A semicolon is not required for macro call (causes unexpected problems sometimes).
use %do %to for loops
The code below should work.
data work.amostra;
input id;
cards;
1
4
7
10
;
run;
proc sql noprint;
select id into :lista_id separated by ' ' from work.amostra;
select count(*) into :nr separated by ' ' from work.amostra;
quit;
* check;
%put lista_id=&lista_id nr=&nr;
%macro ciclo_teste();
%local ref;
%do i = 1 %to &nr;
%let ref = %scan(&lista_id, &i);
%*check;
%put ref = &ref;
/* your task below */
/* data work.up&ref;*/
/* set work.base&ref;*/
/* format perc_acum 9.3;*/
/* if first.id_cliente then perc_acum=0;*/
/* perc_acum + perc;*/
/* run; */
%end;
%mend;
%ciclo_teste()
tested on SAS 9.4 win7 x64
Edited:
In fact I would recommend doing this to avoid scanning a long string which is inefficient.
%macro tester();
/* get the number of obs (a more efficient way) */
%local NN;
proc sql noprint;
select nobs into :NN
from dictionary.tables
where upcase(libname) = 'WORK'
and upcase(memname) = 'AMOSTRA';
quit;
/* assign &ref by random access */
%do i = 1 %to &NN;
data _null_;
a = &i;
set work.amostra point=a;
call symputx('ref',id,'L');
stop;
run;
%*check;
%put ref = &ref;
/* your task below */
%end;
%mend;
%tester()
Please let me know if you have further questions.
Wow that seems like a lot of work. Why not just do the following:
data work.amostra;
input id;
cards;
1
4
7
10
;
run;
%macro test001;
proc sql noprint;
select count(*) into: cnt
from amostra;
quit;
%let cnt = &cnt;
proc sql noprint;
select id into: x1 - :x&cnt
from amostra;
quit;
%do i = 1 %to &cnt;
%let x&i = &&x&i;
%put &&x&i;
%end;
%mend test001;
%test001;
now in variables &x1 - &&x&cnt you have your values and you can process them however you like.
In general if your list is small enough (macro variables are limited to 64K characters) then you are better off passing the list in a single delimited macro variable instead of multiple macro variables.Remember that PROC SQL will automatically set the count into the macro variable SQLOBS so there is no need to run the query twice. Or you can use %sysfunc(countw()) to count the number of entries in your delimited list.
proc sql noprint ;
select id into :idlist separated by '|' from .... ;
%let nr=&sqlobs;
quit;
...
%do i=1 %to &nr ;
%let id=%scan(&idlist,&i,|);
data up&id ;
...
%end;
If you do generate multiple macro variables there is no need to set the upper bound in advance as SAS will only create the number of macro variables it needs based on the number of observations returned by the query.
select id into :idval1 - from ... ;
%let nr=&sqlobs;
If you are using an older version of SAS the you need set an upper bound on the macro variable range.
select id into :idval1 - :idval99999 from ... ;