Suppose I want to use the std::max function in my namespace A. How would I do this?
namespace A {
void fun()
{
double x = std::max(5.0, 1.0); // I don't want to have to write the std::
}
void fun()
{
using namespace std;
double x = max(5.0, 1.0); // I don't want to have to use the using directive to introduce the entire namespace
}
}
Is there a way of doing this?
You can "import" individual symbols by naming them in a using declaration:
namespace A
{
using std::max;
This means that A::max is defined and designates the same function as std::max; so attempts to look up max in namespace A will find the intended function.
(This is an Answer version of Brandon's comment on the original post)
Related
Is it any way to omit outer namespace name for some functions from other namespace inside top-level one?
void sample_func();
namespace foo {
void first_func();
namespace bar {
void second_func();
void sample_func();
}
Everything is trivial for first_func(): just typing using foo::first_func; allows to call it just as fist_func();
Everything is simple if I want to call second_func without any prefix: just using foo::bar::second_func; allows to call it as second_func();
But is there any way to call it as bar::second_func();? It will increase code readability - much better to type and see something like bar::sample_func instead of full foo::bar::sample_func without names confusion: obviously using namespace foo::bar is not an option in that case.
UPD I am not interested in importing the whole foo or bar namespace (i. e. using namespace ... directive! I need just some functions from them.
You can use
namespace bar = foo::bar;
to import foo::bar into current namespace as just bar.
Prefix it with the namespace:: or :: if not in a namespace i.e
::sample_func();
foo::first_func();
bar::second_func();
bar::sample_func();
You can use
using namespace foo;
in any declarative region where you wish to use just first_func() and bar::sample_func().
Example:
int main()
{
using namespace foo;
first_func();
bar::sample_func();
}
I want to explain my question over an instance. I am using an third party library, having its own namespace. I want to import a part of this library, having its own namespace inside the namespace mentioned below.
namespace library {
namespace part {
}
}
There is also a hierarchy in the current project. I want to import and extend the library::part inside to my project with another name. I try to do as below:
#include <library/part>
namespace project {
namespace my_part = library::part;
}
namespace project {
namespace my_part {
void my_extension_1();
void my_extension_2();
}
}
The scenario can be done with the current tools of the language? If not, how should a workaround can be done? Still not, why?
Edit: Error message gcc 5.3.0 dumps:
error: conflicting declaration of namespace ‘project::my_part’
Edit: There is a suggestion about extending the original namespace, but that I am asking for. library::part users should not have a direct access to the functions I have added.
I believe you want to make a namespace of your own that contains
everything that library::part contains, and more besides, without
putting anything more into library::part. Like this?
namespace library {
namespace part {
const int library_part_i = 123;
}
}
namespace project {
namespace part {
using namespace library::part;
void my_extension_1(){};
void my_extension_2(){};
}
}
int main()
{
// const int i = library_part_i; <- Does not compile
// const int i = project::library_part_i; <- Does not compile
const int i = project::part::library_part_i;
// library::part::my_extension_1(); <- Does not compile
project::part::my_extension_2();
return 0;
}
I have a simple question for namespace in C++. There are errors when I compiling the following little piece of code. I don't understand why. Thanks for any help in advance!
#include <iostream>
using namespace std;
int x=100;
namespace first
{
int x=1;
}
namespace second
{
int x=2;
}
int main(){
{
using namespace first;
cout<<x<<endl;
}
{
using namespace second;
cout<<x<<endl;
}
cout<<x<<endl;
}
If I comment out the x declared in the global scope and the last statement. It works fine. But in my mind, the first x is declared in the std namespace and using namespace first and second in the main will be invalid after the the code block they are declared(so the namespace will be std again). So the above code should work. Where am I wrong?
But in my mind, the first x is declared in the std namespace
Your mind is wrong. The using namespace std makes names from std available in the global namespace, it doesn't mean names declared in the global namespace are in std.
x is declared in the global namespace.
so the namespace will be std again
No, nothing in your file is in namespace std, only the contents of <iostream> are in namespace std.
The error is that when you try to use x there are two different variables in scope, ::x and first::x that you could be referring to, so it is ambiguous. You can disambiguate with a using declaration instead of a using directive:
{
using first::x;
cout<<x<<endl;
}
This says that in that scope x refers to first::x
in this case x variable is ambiguous. The compiler can't find which x you are going to use. You can write like this.
#include <iostream>
using namespace std;
int x=100;
namespace first
{
int x=1;
}
namespace second
{
int x=2;
}
int main(){
{
cout<<first::x<<endl;
}
{
cout<<second::x<<endl;
}
cout<<x<<endl;
}
now your code will compile.
The first x is not in the std namespace. It would only be in the std namespace if defined like this:
namespace std
{
int x;
}
Because it's not in that namespace, it's matched by references to x later in the program, and such references become ambiguous when another namespace declaring x is also being used (as in using namespace first / second).
A recent thread on SO triggerred this.
An anonymous namespace is considered to be equivalent to
namespace unique { /* empty body */ }
using namespace unique;
namespace unique { namespace-body }
I fail to recollect the exact reason as to why it is not equivalent to
namespace unique { namespace-body }
using namespace unique;
Also tried searching (including google) but in vain. Please share any information you have in this regards.
The specification that exists now was introduced in 1995 in N0783 to correct for a corner case. To quote that paper (page 9):
The WP defines the semantics of an unnamed namespace as being equivalent to:
namespace UNIQUE {
// namespace body
}
using namespace UNIQUE;
This is incorrect because it makes the code in an unnamed namespace dependent on
whether the code is in an original namespace or a namespace extension.
namespace {} // If you remove this line, the
// use of ::f below is invalid
namespace {
void f()
{
using ::f;
}
}
The WP should be changed to define an unnamed namespace as being equivalent to:
namespace UNIQUE {}
using namespace UNIQUE;
namespace UNIQUE {
// namespace body
}
With using namespace I make the whole contents of that namespace directly visible without using the namespace qualifier. This can cause problems if using namespace occurs in widely used headers - we can unintendedly make two namespaces with identical classes names visible and the compiler will refuse to compile unless the class name is prepended with the namespace qualifier.
Can I undo using namespace so that the compiler forgets that it saw it previously?
No, but you can tell your coworkers that you should never have a using directive or declaration in a header.
As others said, you can't and the problem shouldn't be there in the first place.
The next-best thing you can do is bring in your needed symbols so that they are preferred by the name look-up:
namespace A { class C {}; }
namespace B { class C {}; }
using namespace A;
using namespace B;
namespace D {
using A::C; // fixes ambiguity
C c;
}
In some cases you can also wrap the offending includes with a namespace:
namespace offender {
# include "offender.h"
}
No, C++ Standard doesn't say anything about "undo". The best you are allowed to do is to limit scope of using:
#include <vector>
namespace Ximpl {
using namespace std;
vector<int> x;
}
vector<int> z; // error. should be std::vector<int>
But unfortunately using namespace Ximpl will bring all names from std namespace as well.
Not to my knowledge... But as a rule I only use "using namespace" in .cpp files.
The closest, that I'll try to use in header files is following:
//example.h
#ifndef EXAMPLE_H_
#define EXAMPLE_H_
/**
* hating c++ for not having "undo" of using namespace xx
*/
#define string std::string
#define map std::map
class Example {
public:
Example (const char *filename);
Example (string filename);
~Example ();
private:
map<string,complicated_stuff*> my_complicated_map;
};
#undef string
#undef map
#endif //EXAMPLE_H_
after all, defines are #undef -able.
There are 2 problems:
1. it is ugly
2. separate #define and #undef for each name from the corresponding namespace are used
As stated you should not use using namespace sth in header files. When you need functionality from a namespace in your implementation you can leverage scopes like this:
void func() {
// some code agnostic to your namespace.
{
using namespace sth;
// some code aware of sth.
}
// some other code agnostic to your namespace.
}