Counting how many times a condition succeeds in SAS - sas

Question

I have a table A with real time values in it.
Amount Count Pct1 Pct2
300 2 0.000 100.000
1,891 2 0.001 100.000
500 2 0.000 100.000
100 2 0.000 100.000
1,350 2 0.001 100.000
2,648 2 0.001 100.000
2,255 2 0.001 100.000
500 2 0.000 100.000
200 2 0.000 30.441
10 2 0.000 100.000
1,928 2 0.001 100.000
40 2 0.000 100.000
200 2 0.000 100.000
256 2 0.000 100.000
254 2 0.000 100.000
100 2 0.001 100.000
50 1 0.000 33.333
1,512 2 0.001 100.000
I have a table B with a set of conditions. I want to generate the Condition success count in SAS. i.e. If I pass the row 1 in the below table as a condition to the table A it succeeds 2 times. I am using a join to generate a cartesin product and its not efficient. I want an efficient way to solve this problem (similar to what countifs function does in excel). Thanks a lot for your help.
Amount Count Pct1 Pct2 Condion Success Count
1,576 2 0 100 4
1,537 2 0 100 4
1,484 2 0 100 5
1,405 2 0 100 5
1,290 2 0 100 6
1,095 2 0 100 6
948 2 0 100 6
932 2 0 100 6
914 2 0 100 6
887 2 0 100 6
850 2 0 100 6
774 2 0 100 6
707 2 0 100 6
704 2 0 100 6
695 2 0 100 6
646 2 0 100 6
50 1 0 5.42 16
50 1 0 5.42 16

Answer 1

You said that you have tried join to make to make a cartesian product. However, since you didn't post any code I am not sure if you tried to make full product and then calculate the rows. Doing the counting in one SQL statement is much faster since actually full cartesian product is not written anywhere. Like this:
proc sql;
create table tableC as
select c.*, coalesce(s,0) as SuccessCount from TableB c
left join (
select id, count(*) as s from TableA a,TableB b
where
a.amount >= b.amount and
a.count >= b.count and
a.pct1 >= b.pct1 and
a.pct2 >= b.pct2
group by id
) as d
on c.id = d.id
;
quit;
Note that tableB needs to have some unique id column. You should always have some column to use as id but if you don't have it already simple create it like this for example:
data tableB;
set tableB;
id = _N_;
run;