I want to declare a pointer array to character without using string - c++

Question

Here is the code::
#include <iostream>
using namespace std;
const int MAX = 4;
int main ()
{
char key[20];
char *names[MAX];
for (int i=0; i<MAX; i++)
{
cout << " entr keys\n";
cin >> key;
names[i]=key;
cout<< names[i];
}
for(int i=0; i<MAX;i++)
{
cout << names[i];
}
return 0;
}
When I enter the keys and print them in the 1st for loop they show the right value, but when I print names[i] in the 2nd for loop it keeps showing the last key entered again and again.
Please tell me: where am I going wrong?

Answer 1

When you run names[i]=key; you don't really copy key's string value to names[i].
It just makes name[i] point to where key is (since both name[i] & key are pointers).
so all in all you're overwriting key several times, and making all of names pointers point to key.
You need to copy those strings either by working with std::string instead of char* or by using strcpy. I'd recommend on working with std::string.
Using std::string your code should look like this:
#include <iostream>
#include <string>
using namespace std;
const int MAX = 4;
int main ()
{
string names[4];
for (int i = 0; i < MAX; i++)
{
cout << "entr keys" << endl;
cin >> names[i];
cout << names[i];
}
for(int i=0; i<4;i++)
{
cout << names[i];
}
return 0;
}

Answer 2

Every time you execute the lines
cout << " entr keys\n";
cin >> key;
you're inserting a null-terminated string into key, e.g. "hello\0".
Afterwards you copy key's address and store it into a cell of the names pointers array:
names[i]=key; // Now I point to 'key'
cout<< names[i];
then the cycle starts again. Anyway from the second time on you're inserting null-terminated strings into key and thus overwriting the previous contents. The second time if you had entered "hi\0" the contents of the key array would become
['h', 'i', '\0', 'l', 'l', 'o', '\0']
anyway you're going to only print the first string since the null terminator will prevent the other content from being displayed.
When the program ends you're going to have four pointers to the same key array and that array will only contain the last element inserted which overwrote the previous ones.
In order to solve you can make your array a bidimensional one (or use a string array):
const int MAX = 4;
int main ()
{
char key[4][20]; // <- Now this has two indices
char *names[4];
for (int i = 0; i < MAX; i++)
{
cout << " entr keys\n";
cin >> key[i];
names[i]=key[i];
cout<< names[i];
}
for(int i=0; i<4;i++)
{
cout << names[i];
}
return 0;
}
Live Example

Answer 3

Corrected program:
#include <iostream>
using namespace std;
#include <cstring>
const int MAX = 4;
int main ()
{
char key[20];
char *names[MAX];
for (int i = 0; i < MAX; i++)
{
cout << " entr keys\n";
cin >> key;
names[i] = new char[strlen(key) + 1];//names[i]=key;
strcpy(names[i], key);
cout<< names[i];
}
for(int i=0; i<MAX;i++)
{
cout << names[i];
}
for(int i=0; i<MAX;i++)
{
delete [] names[i];
}
return 0;
}
You need to allocate space for each names[i] and when done, deallocate
also, changed the hardcoded 4 to MAX