I need to write a RegEx to match the "1-234-5678" string if there are no dash characters around it.
I have the following RegEx:
\b\d\-\d{3}\-\d{4}\b
Now this works fine and matches "1-234-5678" correctly in the strings below:
text 1-234-5678 text
111 1-234-5678 1212
The RegEx also correctly NOT matches "1-234-5678" in the strings below:
text1-234-5678text
1111-234-56781212
But the problem is that it also matches in the following strings:
text-1-234-5678-text
111-1-234-5678-1212
It's because \b matches before and after the dashes.
How can I eliminate matches if there's a dash in front or after the data?
Use a negative lookbehind and negative lookahead to check whether the above mentioned format is not preceded and followed by a - symbol,
(?<!-)\b\d\-\d{3}\-\d{4}\b(?!-)
DEMO
Related
For example we have a string:
asd/asd/asd/asd/1#s_
I need to match this part: /asd/1#s_ or asd/1#s_
How is it possible to do with plain regex?
I've tried negative lookahead like this
But it didn't work
\/(?:.(?!\/))?(asd)(\/(([\W\d\w]){1,})|)$
it matches this '/asd/asd/asd/asd/asd/asd/1#s_'
from this 'prefix/asd/asd/asd/asd/asd/asd/1#s_'
and I need to match '/asd/1#s_' without all preceding /asd/'s
Match should work with plain regex
Without any helper functions of any programming language
https://regexr.com/
I use this site to check if regex matches or not
here's the possible strings:
prefix/asd/asd/asd/1#s
prefix/asd/asd/asd/1s#
prefix/asd/asd/asd/s1#
prefix/asd/asd/asd/s#1
prefix/asd/asd/asd/#1s
prefix/asd/asd/asd/#s1
and asd part could be replaced with any word like
prefix/a1sd/a1sd/a1sd/1#s
prefix/a1sd/a1sd/a1sd/1s#
...
So I need to match last repeating part with everything to the right
And everything to the right could be character, not character, digit, in any order
A more complicated string example:
prefix/a1sd/a1sd/a1sd/1s#/ds/dsse/a1sd/22$$#!/123/321/asd
this should match that part:
/a1sd/22$$#!/123/321/asd
If you want the match only, you can use \K to reset the match buffer right before the parts that you want to match:
^.*\K/a\d?sd/\S+
The pattern will match
^ Start of string
.* Match any char except a newline until end of the line
\K Forget what is matched until now
/a\d?sd/ match a, optional digits and sd between forward slashes
\S+ Match 1+ non whitespace chars
See a regex demo
I'm looking for a regex pattern which can do this exactly.
Should match the length which is 12 characters alphaNumeric
Should also check for the occurrence of hyphen - twice in the word
No spaces are allowed.
I have tried the following regex:
^([a-zA-Z0-9]*-[a-zA-Z0-9]*){2}$
Some sample cases
-1234abcd-ab
abcd12-avc-a
-abcd-abcdacb
ac12-acdsde-
The regex should match for all the above.
And should be wrong for the below
-abcd-abcd--a
abcd-abcdefg
I've been using this regex ^([a-zA-Z0-9]*-[a-zA-Z0-9]*){2}$ for matching the above patterns, but the problem is, it doesn't have a length check of 12. I'm not sure how to add that into the above pattern. Help would be appreciated.
Use this:
(?=^.{12}$)(?=^[^-]*-[^-]*-[^-]*$)[a-zA-Z0-9-]+ /gm
The first positive lookahead asserts the total length to be 12.
The second positive lookahead asserts the presence of exactly two hyphens.
Rest is just matching the possible characters in the character set.
Demo
I have this regex
(?<=TG00).*?(?=#)
which extracts all strings between TG00 and #. Demo: https://regex101.com/r/04oqua/1
Now, from above results I want to extract only the string which contains TG40 155963. How can I do it?
Try this pattern:
TG00[^#]*TG40 155963[^#]*#
This pattern just says to find the string TG40 155963 in between TG00 and an ending #. For the sample data in your demo there were 3 matches.
Demo
For some reason appending .*? to your lookbehind results in engine error, but works fine with lookahead. Regex below does not match your text exactly, but it does extract it via capture group.
(?<=TG00).*?(TG40 155963)(?=.*?#)
You can use this regex with a lookahead and negated character class:
(?<=TG00)(?=[^#]*TG40 155963)[^#]+(?=#)
RegEx Demo
RegEx Explanation:
(?<=TG00): Assert that we have TG00 at previous position
(?=[^#]*TG40 155963): Lookahead to assert we have string TG40 155963 after 0 or more non-# characters, ahead
[^#]+: Match 1+ non-# characters
I have this regexp:
^[a-z0-9]+([.\-][a-z0-9]+)*$
I need exclude from match only one word "www".
I tried the negative lookahead but without a success.
Use a negative lookahead like this:
^(?!www$)[a-z0-9]+([.-][a-z0-9]+)*$
^^^^^^^^
This will not match a string equal to www.
See the regex demo
If you want to fail a match with strings that contain -www- or .www., use
^(?!.*\bwww\b)[a-z0-9]+([.-][a-z0-9]+)*$
See another regex demo. This pattern contains a (?!.*\bwww\b) lookahead that fails the whole match if there is a www somewhere inside the string and it has no digits or letters round it due to \b word boundaries.
I am trying to match Strings with optional number of hyphens.
For example,
string1-string2,
string1-string2-string3,
string1-string2-string3 and so on.
Right now, I have something which matches one hyphen. How can I make the regex to match optional number of hyphens?
My current regex is: arn:aws:iam::\d{12}:[a-zA-Z]/?[a-zA-Z]-?[a-zA-Z]*
What do I need to add?
Use this regex:
^\\w+(-\\w+)*$
Explanation:
\\w+ - match any string containing [a-zA-Z_0-9]
(-\\w+)* - match a hyphen followed by a string zero or more times
Regex101
Note that this won't match an empty string, or a string containing weird characters. You could handle these cases manually or you could update the regex.