Match a word just once - AWK - regex

Question

I was reading GNU awk manual but I didnt find a regular expression wich whom I can match a string just once.
For example from the files aha_1.txt, aha_2.txt, aha_3.txt, .... I would like to print the second column $2 from the first time ana appears in the files (aha_1.txt, aha_2.txt, aha_3.txt, ....). In addition, the same thing when pedro appears.
aha_1.txt
luis 321 487
ana 454 345
pedro 341 435
ana 941 345
aha_2.txt
pedro 201 723
gusi 837 134
ana 319 518
cindy 738 278
ana 984 265
.
.
.
.
Meanwhile I did this but it counts all the cases not just the first time
/^ana/ {print $2 }
/^pedro/ {print $2 }
Thanks for your help :-)

Answer 1

Just call the exit command after printing the first value(second column in the line which starts with the string ana).
$ awk '$1~/^ana$/{print $2; exit}' file
454

Answer 2

Original question
Only processing one file.
awk '/ana/ { if (ana++ == 0) print $2 }' aha.txt
or
awk '/ana/ && ana++ == 0 { print $2 }' aha.txt
Or, if you don't need to do anything else, you can exit after printing, as suggested by Avinash Raj in his answer.
Revised question
I have many files (aha.txt, aha_1.txt, aha_2.txt, ...) each file has ana inside and I need just to take the fist time ana appears in each file and the output has to be one file.
That's sightly different as a question. If you have GNU grep, you can use (more or less):
grep -m1 -e ana aha*.txt
That will list the whole line, not just column 2, and will list the filenames too, so it isn't a perfect match.
Using awk, you have to work a bit more:
awk 'FILENAME != old_file { ana = 0; old_file = FILENAME }
/ana/ { if (ana++ == 0) print $2 }' aha*.txt