I was trying this in Notepad++, but I'm not entirely sure if it's possible there. I have an iCal file where I need to insert some missing "Organizer" fields. For example, I need
DTSTAMP:20140821T160519Z
UID:ExampleUID1
to be this
DTSTAMP:20140821T160519Z
ORGANIZER;CN=Test:mailto:me#example.com
UID:ExampleUID1
The organizer is there in some cases, and is not a static value. How can I do this while keeping the DTSTAMP string intact? Finding DTSTAMP:[A-Za-z0-9_]*$\r\nUID: finds the entries, but I can't find out what to replace with. Using
DTSTAMP:^([A-Za-z0-9_])*$\r\nORGANIZER;CN=Test:mailto:me#example.com\r\nUID:
or any variation thereof injects the actual regex text (^[A-Za-z0-9_]*$.) into the results.
Replace this pattern:
^(DTSTAMP:.+)$
With this replacement string:
\1\r\nORGANIZER;CN=Test:mailto:me#example.com
You have to check the Regular expression mode (obviously), and uncheck the . matches newline option.
For some additional security, you also cound use this pattern:
^(DTSTAMP:.+)$(?!\r\nORGANIZER)
This won't insert an ORGANIZER field if one already exists just below the DTSTAMP field.
Also, if your iCal file is in UNIX newline format, replace every \r\n with \n.
You can use this regex:
(DTSTAMP.*)
Working demo
Check the substitution section:
Related
I have a project that demands extracting data from XML files (values inside the <Number>... </Number> tag), however, in my regular expression, I haven't been able to extract lines that had multiple data separated by a newline, see the below example:
As you can see above, I couldn't replicate the multiple lines detection by my regular expression.
If you are using a script somewhere, your first plan should be to use a XML parser. Almost every language has one and it should be far more accurate compared to using regex. However, if you just want to use regex to search for strings inside npp, then you can use \s+ to capture multiple new lines:
<Number>(\d+\s)+<\/Number>
https://regex101.com/r/MwvBxz/1
I'm not sure I fully understand what you are trying to do so if this doesn't do it then let me know what you are going for.
You can use this find+replace combo to remove everything which is not a digit in between the <Number> tag:
Find:
.*?<Number>(.*?)<\/Number>.*
Replace:
$1
finally i was able to find the right regular expression, I'll leave it below if anyone needs it:
<Type>\d</Type>\n<Number>(\d+\n)+(\d+</Number>)
Explanation:
\d: Shortcut for digits, same as [1-9]
\n: Newline.
+: Find the previous element 1 to many times.
Have a good day everybody,
After giving it some more thought I decided to write a second answer.
You can make use of look arounds:
(?<=<Number>)[\d\s]+(?=<\/Number>)
https://regex101.com/r/FiaTKD/1
Doing a find and replace in VsCode on a large amount of files. I'm looking to replace all spaces after a set of quotes, but only on a specific line.
I can very easily find all spaces using \s+, but I don't understand how to capture only the spaces after a specific string(one specific line). I've tried positive look behinds, but I can only get it to match the first space, but I need to match all spaces on that line.
Example code:
variable = "01 - Testing this thing"
I need to find and replace all the spaces between the quotation marks with underscores, but I can't get any regex to match all the spaces between the quotes. I might want to replace the dash(-) as well, but the spaces are more important and I'm struggling to figure it out.
Here is a pretty good workflow.
Open a Search Editor (from the Command Palette or set a keybinding to it).
Use this regex (?<=variable = ")[^"]*.
That will find all matches in all files in your workspace or whatever folders you designate in the file to include filter. I suggest setting the context lines option to 0.
Ctrl+Shift+L to select all your matches. The matches are the 01 - Testing this thing part.
Now do a regular find in that search editor tab - with the Find in Selection option enabled.
Simply doing a find of and replaceAll with _ will make all those changes (in the Search Editor only).
To apply those changes to all the files with your initial search results, use the extension search-editor-apply-changes Apply Search Editor Changes... command.
Then you can check to see if the changes were as you expected and save all. It will open all affected files so you can inspect them.
Seems like a few steps but notice the first regex can be very simple. And then you are doing a simple find/replace in just those selections. Demo:
You search for a string that matches, it has A space between the quotes. Replace with what is before and after the space but the space is now an underscore. You have to apply this as often as the max number od spaces in a string. It can't be done in 1 regex search-replace.
In the Search Bar
Find Regex:
(variable = "[^" ]*) ([^"]*")
Replace:
$1_$2
Then apply Replace All (button) and Refresh (button) until no more searches found.
I am facing a problem whereby I am given a string that contains a path to a file and the file's name and I only want to extract the path (without the file's name)
For example, I will receive something like
C:\Users\OopsD\Projects\test.acdbd
and from that string I want to extract only
C:\Users\OopsD\Projects
I was trying to create a RegEx to match a backslash followed by a word, followed by a dot followed by another word - this is to match the
\test.acdbd
part and replace it with empty string so that the final result is
C:\Users\OopsD\Projects
Can anyone, familiar with RegEx, help me on this one? Also, I will be using regular expressions quite a lot in the future. Is there a (free) program I can download to create regular expressions?
Are you really sure you need to be using Regex for such as simple task? How about this:
Dim file As New IO.FileInfo(" C:\Users\OopsD\Projects\test.acdbd")
MsgBox(file.Directory.FullName)
Regarding the free program on Regex, I would definitely recommend http://www.gskinner.com/RegExr/ - using it all the time. But you always have to consider alternatives, before going the Regex way.
The regex that you are looking for is as below:
[^/]+$
where,
^ (caret):Matches at the start of the string the regex pattern is applied to. Matches a position rather than a character. Most regex flavors have an option to make the caret match after line breaks (i.e. at the start of a line in a file) as well.
$ (dollar):Matches at the end of the string the regex pattern is applied to. Matches a position rather than a character. Most regex flavors have an option to make the dollar match before line breaks (i.e. at the end of a line in a file) as well. Also matches before the very last line break if the string ends with a line break.
+ (plus):Repeats the previous item once or more. Greedy, so as many items as possible will be matched before trying permutations with less matches of the preceding item, up to the point where the preceding item is matched only once.
More reference can be found out at this link.
Many Regex softwares and tools are out there. Some of them are:
www.gskinner.com/RegExr/
www.txt2re.com
Rubular- It is not just for Ruby.
How can I use regex to find all text before the text "All text before this line will be included"?
I have includes some sample text below for example
This can include deleting, updating, or adding records to your database, which would then be reflex.
All text before this line will be included
You can make this a bit more sophisticated by encrypting the random number and then verifying that it is still a number when it is decrypted. Alternatively, you can pass a value and a key instead.
Starting with an explanation... skip to end for quick answers
To match upto a specific piece of text, and confirm it's there but not include it with the match, you can use a positive lookahead, using notation (?=regex)
This confirms that 'regex' exists at that position, but matches the start position only, not the contents of it.
So, this gives us the expression:
.*?(?=All text before this line will be included)
Where . is any character, and *? is a lazy match (consumes least amount possible, compared to regular * which consumes most amount possible).
However, in almost all regex flavours . will exclude newline, so we need to explicitly use a flag to include newlines.
The flag to use is s, (which stands for "Single-line mode", although it is also referred to as "DOTALL" mode in some flavours).
And this can be implemented in various ways, including...
Globally, for /-based regexes:
/regex/s
Inline, global for the regex:
(?s)regex
Inline, applies only to bracketed part:
(?s:reg)ex
And as a function argument (depends on which language you're doing the regex with).
So, probably the regex you want is this:
(?s).*?(?=All text before this line will be included)
However, there are some caveats:
Firstly, not all regex flavours support lazy quantifiers - you might have to use just .*, (or potentially use more complex logic depending on precise requirements if "All text before..." can appear multiple times).
Secondly, not all regex flavours support lookaheads, so you will instead need to use captured groups to get the text you want to match.
Finally, you can't always specify flags, such as the s above, so may need to either match "anything or newline" (.|\n) or maybe [\s\S] (whitespace and not whitespace) to get the equivalent matching.
If you're limited by all of these (I think the XML implementation is), then you'll have to do:
([\s\S]*)All text before this line will be included
And then extract the first sub-group from the match result.
(.*?)All text before this line will be included
Depending on what particular regular expression framework you're using, you may need to include a flag to indicate that . can match newline characters as well.
The first (and only) subgroup will include the matched text. How you extract that will again depend on what language and regular expression framework you're using.
If you want to include the "All text before this line..." text, then the entire match is what you want.
This should do it:
<?php
$str = "This can include deleting, updating, or adding records to your database, which would then be reflex.
All text before this line will be included
You can make this a bit more sophisticated by encrypting the random number and then verifying that it is still a number when it is decrypted. Alternatively, you can pass a value and a key instead.";
echo preg_filter("/(.*?)All text before this line will be included.*/s","\\1",$str);
?>
Returns:
This can include deleting, updating, or adding records to your database, which would then be reflex.
I've hit a wall. Does anybody know a good text editor that has search and replace like Notepad++ but can also do multi-line regex search and replace? Basically, I am trying to find something that can match a regex like:
search oldlog\(.*\n\s+([\r\n.]*)\);replace newlog\(\1\)
Any ideas?
Notepad++ can now handle multi line regular expressions (just update to the latest version - feature was introduced around March '12).
I needed to remove all onmouseout and onmouseover statements from an HTML document and I needed to create a non-greedy multi line match.
onmouseover=.?\s*".*?"
Make sure you check the: [ ] . matches newline checkbox if you want to use the multi line match capability.
EditPad Pro has better regex capabilities than any other editor I've ever used.
Also, I suspect you have an error in your regex — [\r\n.] will match only carriage returns, newlines, and full stops. If you're trying to match any character (i.e. "dot operator plus CR and LF), try [\s\S] instead.
My personal recommendation is IDM Computing's UltraEdit (www.ultraedit.com) - it can do regular expressions (both search and replace) with Perl, Unix and UltraEdit syntax. Multi-line matching is one of the capabilities in Perl regex mode in it.
It also has other nice search capabilities (e.g search in specific character column range, search in multiple files, search history, search favorites, etc...)
(source: ultraedit.com)
The Zeus editor can do multi-line search and replace.
I use Eclipse, which is free and that you may already have if you are a developer. '\R' acts as platform independent line delimiter. Here is an example of multi-line search:
search:
\bibitem.(\R.)?\R?{([^{])}$\R^([^\].[^}]$\R.$\R.)
and replace:
\defcitealias{$2}{$3}
I'm pretty sure Notepad++ can do that now via the TextFX plugin (which is included by default). Hit Control-R in Notepad++ and have a play.
TextPad has good Regex search and replace capabilities; I've used it for a while and am pretty happy with it.
From the Features:
Powerful search/replace engine using
UNIX-style regular expressions, with
the power of editor macros. Sets of
files in a directory tree can be
searched, and text can be replaced in
all open documents at once.
For more options than you could possibly need, check out "Notepad++ Alternatives" at AlternativeTo.net.
you can use Python Script plugin for Multiline Regular Expression search and replace!
- http://npppythonscript.sourceforge.net/docs/latest/scintilla.html?highlight=pymlreplace#Editor.pymlreplace
# This example replaces any <br/> that is followed by another on the next line (with optional spaces in between), with a single one
editor.pymlreplace(r"<br/>\s*\r\n\s*<br/>", "<br/>\r\n")
I use Notepad++ all the time but it's Regex has alway been a bit lacking.
Sublime Text is what you want.
EditPlus does a good job at search/replace using regex (including multiline)
You could use Visual Studio. Download Express for free if you don't have a copy.
VS's regex is non-standard, so you'd have to use \n:b+[\r\n] instead.
The latest version of UltraEdit has multiline find and replace w/ regex support.
Or if you're OK with using a more specialized regular expression tool for this, there's Regex Hero. It has the side benefit of being able to do everything on the fly. In other words, you don't have to click a button to test your regular expression because it's automatically tested after every keypress.
Personally, I'd use UltraEdit if I'm looking to replace text in multiple files. That way I can just select the files to replace as a batch and click Replace. But if I'm working with a single text file and I'm in need of writing a more complex regular expression then I'd paste it into Regex Hero and work with it there. That's because Regex Hero can save time when you see everything happen in real-time.
ED for windows has two versions of regex, three sorts of cut and paste (selection, lines or blocks, AND you can shift from one to the next (unlike ultra edit, which is clunky at best) with just a mouse click while you are highlighting -- no need to pull down a menu. The sheer speed of getting the job done is incredible, like reading on a Kindle, you don't have to think about it.
You can use a recent version of Notepad++ (Mine is 6.2.2).
No need to use the option ". match newline" as suggested in another answer. Instead, use the adequate regular expression with ^ for "begin of line" and $ for "end of line". Then use \r\n after the $ for a "new line" in a dos file (or just \n in a unix file as the carriage return is mainly used for dos/windows text file):
Ex.: to remove all lines starting with tags OBJE after a line starting with a tag UID (from a gedcom file - used in genealogy), I did use the following search regex:
^UID (.*)$\r\n^(OBJE (.*)$\r\n)+
And the following replace value:
UID \1\r\n
This is matching lines like this:
UID 4FBB852FB485B2A64DE276675D57A1BA
OBJE #M4#
OBJE #M3#
OBJE #M2#
OBJE #M1#
and the output of the replacement is
UID 4FBB852FB485B2A64DE276675D57A1BA
550 instances have been replaced in less than 1 sec. Notepad++ is really efficient!
Otherwise, to validate a Regular expression I like to use the .Net RegEx Tester (http://regexhero.net/tester/). It's really great to write and test on the fly a Reg Ex...
PS.: Also, you can use [\s\S] in your regex to match any character including new lines. So, if you look for any block of "multi-line" text starting with "xxx" and ending with "abc", the following Regex will be fine:^xxx[\s\S]*?abc$ where "*?" is to match as less as possible between xxx and abc !!!