how to trim trailing spaces after all delimiter in a text file - regex

Question

Need help to remove trailing spaces after all delimiter in a text file
I have Text file with below data.
eg.
ADDRESS_ID| COUNTRY_TP_CD| RESIDENCE_TP_CD| PROV_STATE_TP_CD|ADDR_LINE_ONE|P_ADDR_LINE_ONE
885637959852960985.0| 76.0|||169 Park lane||Scottish||lane||KU|||||||2013-09-19 14:48:49.609000|
I want to remove spaces after the delimiter and the first letter of the word.
Any regex or unix script that can do the same. Looking for output as below:
ADDRESS_ID|COUNTRY_TP_CD|RESIDENCE_TP_CD|PROV_STATE_TP_CD|ADDR_LINE_ONE|P_ADDR_LINE_ONE
885637959852960985.0|76.0|||169 Park lane||Scottish||lane||KU||||||2013-09-19 14:48:49.609000|
Any help will be appreciated.

Answer 1

awk 'BEGIN{FS=OFS="|"} {for (i=1;i<=NF;i++) gsub(/^[[:space:]]+|[[:space:]]+$/,"",$i)} 1' file

Answer 2

Using a perl one-liner to remove the spacing around every field. Assumes no embedded delimiters:
perl -i -lpe 's/\s*([^|]*?)\s*/$1/g' file.txt
Switches:
-i: Edit <> files in place (makes backup if extension supplied)
-l: Enable line ending processing
-p: Creates a while(<>){...; print} loop for each “line” in your input file.
-e: Tells perl to execute the code on command line.

Answer 3

The below perl code would remove the spaces which are present at the start of a line or the spaces after to the delimiter | ,
$ perl -pe 's/(?<=\|) +|^ +//g' file
ADDRESS_ID|COUNTRY_TP_CD|RESIDENCE_TP_CD|PROV_STATE_TP_CD|ADDR_LINE_ONE|P_ADDR_LINE_ONE
885637959852960985.0|76.0|||169 Park lane||Scottish||lane||KU|||||||2013-09-19 14:48:49.609000|
To save the changes made to that file,
perl -i -pe 's/(?<=\|) +|^ +//g' file

Answer 4

sed 's/\ //g' input.txt > output.txt

Answer 5

With sed:
sed -r -e 's/(^|\|)\s+/\1/g' -e 's/\s+$//' filename
In the first expression:
(^|\|) matches the beginning of the line or a | character, and saves this in capture group 1.
\s+ matches a sequence of whitespace characters after that.
The replacement \1 substitutes capture group 1, so this deletes the whitespace at the beginning of the line and after the delimiter.
The g modifier makes it operate on all the matches in the line.
In the second expression:
\s+ again matches a sequence of whitespace
$ matches the end of the line
The replacement replaces the whole thing with an empty string, this removing trailing spaces.

Answer 6

for posix sed (for GNU sed add --posix)
sed 's/^[[:space:]]//;s/|[[:space:]]/|/g' YourFile
use 2 substitution (there are no OR (|) in sed regex posix version)
Remove starting space by replacing space at start( ^[[:space:]]*) by nothing
Replace any sequence pipe than any space (|[[:space:]]*) by pipe
[[:space:]] could be replace by a single space char if text only have space (ASCII 32) char