Xslt url condition - xslt

Question

I want to know if there's any url logic if url contains /market/3. like:
<xsl:variable name="cultureRequest" select="concat('http://',MAIN_URL)" />
<xsl:if test="contains($cultureRequest, '/market/3')" >
</xsl:if>

Answer 1

well, there's any way to check if url contains /market/3/ for example?
As I said in the comments, yes, that's possible. As long as the URL is a string. But you have to be aware that this does not mean that XSLT treats this string as an URL. It still thinks of it as a string.
For example, your code snippet works with the following input:
<?xml version="1.0" encoding="UTF-8"?>
<MAIN_URL>www.main-url.com/market/3/xs.htm</MAIN_URL>
Then, you could apply a stylesheet like the one below. It outputs a yes element if the contains function returns true.
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:output method="xml" encoding="UTF-8" indent="yes" />
<xsl:template match="/">
<xsl:variable name="cultureRequest" select="concat('http://',MAIN_URL)" />
<xsl:if test="contains($cultureRequest, '/market/3')" >
<yes>!</yes>
</xsl:if>
</xsl:template>
</xsl:transform>
XML Output
The URL contains /market/3, so the output is:
<?xml version="1.0" encoding="UTF-8"?>
<yes>!</yes>
Note: There are two things I did not understand about your question and that I tried to ask about in the comments:
I am not sure why you concatenate the URL to http;// before handing
it to contains.
Why do you refer to "url logic"?