I'm trying to match and exclude specific words using regex. I'm essentially trying to match all strings in a 24 hour with an option of an am or pm. However I would like to excludes string that begin with 2014 or 2013. For example:
Input:
11 45 pm
12 34 am
1230pm
2013pm
12 pm
12p
2014 pm
Desired output:
11 45 pm
12 34 am
1230pm
12 pm
I would like to only use one regex to match this. I know how to accomplish this task with two regex's.
I'm using the following command:
grep -E '^(?!2014)(?!2013)([01]?[0-9]|2[0-3])( )?[0-5][0-9]?\s?(am|pm)?' output.txt
with no success. Any suggestions? Thanks!
You can use a pattern like:
^((?:0?[0-9]|1[012])\s?(?:[0-5][0-9])?\s?[ap]m)
Here, I've assumed that either am or pm is present at the end of statement.
This works too:
[0-9]{1,2}\s*[0-9]{1,2}(?<!2013)(?<!2014)\s*(am|pm)
Related
I have the following regex that I have been working on:
^(\d\d)\s(Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)\s(\d{4})?$
I am trying to grab the date from an email header that is formatted like so:
"Mon, 18 Nov 2019 09:19:17 -0700 (MST)"
and I want the result to be:
18 Nov 2019
It seems that the \s for whitespace could be the culprit, but I have yet to find another forum result that grabs dates with whitespace instead of "-" or "/".
Does anyone have any suggestions for getting this working to extract as described above? Thanks in advance.
The problem is that you have added the "^" and "$" symbol on the start and end of the regex.
"^n": The ^n quantifier matches any string with n at the beginning of it.
"n$": The n$ quantifier matches any string with n at the end of it.
Since the text is not start with 2 digit (\d\d) and end with 2 digit (\d{4}). You will not get any result from this regex.
You can simply remove those two symbol or use the following code to achieve that.
/(\d{2}\s(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)\s\d{4})/.exec("Mon, 18 Nov 2019 09:19:17 -0700 (MST)")[1]
I have paragraphs like below
Dec 27 09:00:06 test event[1] number one
Dec 30 02:00:06 here is event[22] Feb 01 04:36:11 helloworld2
Dec 07 04:00:11 Now is event{3} Jan 01 04:36:11 Helloworld
Jan 02 23:00:11 helloworld evnt{45}
Feb 12 04:36:11 mesg10 Feb 13 04:36:11 mesg11 Feb 14 04:36:11 testmesg12
I want to capture the time stamp and message that occurred on that time stamp
Im using pythex.org to test the python regex (?P\w{3}\s\w{2}\s\w{2}:\w{2}:\w{2})\b(?P.*)
but this is only working for line separated and fails on paragraph having multiple(1+) Timestamps and message on same line. For example in above paragraphs I cannot capture Timestamp and message on Feb 12 04:36:11 mesg10 Feb 13 04:36:11 mesg11 Feb 14 04:36:11 testmesg12
Here is a 2.x Python solution which uses findall to find multiple matches in each line of your log file:
import re
p_str = '\w{3}\s\d{2}\s\d{2}:\d{2}:\d{2}\s(.*?)(?=\w{3}\s\d{2}\s\d{2}:\d{2}:\d{2}\s|$)'
pattern = re.compile(p_str, re.IGNORECASE)
log_str = 'Feb 12 04:36:11 mesg10 Feb 13 04:36:11 mesg11 Feb 14 04:36:11 testmesg12'
match = pattern.findall(log_str)
print match
['mesg10 ', 'mesg11 ', 'testmesg12']
Demo
The challenge here is in formulating a pattern which will work. I went the route of matching a timestamp, and then using a lookahead to know when to stop matching. We stop matching when we either see another timestamp, or we see the end of the line. Note that matching the next timestamp won't work here, because we need that to be the start of the next match as the regex works its way across the line.
Explore the demo to see the code in action.
I'm struggling in creating a regex that given this string:
20 - 29 APR 2017, 9 nights
returns two groups, first:
20 APR 2017
and second:
29 APR 2017
You can try this regex:
(\d+)\s*-\s*(\d+)\s*([a-zA-Z]+)\s*(\d+).*
And replace by:
$1 $3 $4\n$2 $3 $4
Regex Demo
I have following strings:
Emini Mar 15 ME
Emini ICE MAR 15 RTA
Emini ABC Apr 15 RTA
and use pattern:
[\S]*(Jan|Feb|Mar|Apr|May|Jin|Jul|Aug|Sep|Oct|Nov|Dec)+(\s+\d{1,2})
How to create short pattern instead ...(Jan|JAN|jan|Feb|FEB|feb...) etc.
Thanks in advance
Just add case-insensitive modifier i
(?i)\S*(Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)+(\s+\d{1,2})
Given the following string "Mon Feb 01 02:42:27 +0000 2013", what should the regex be to get the following "Feb 01 2013".
The following regex "\w{3}\s\w{3}\s\d{1,2}" will yield "Mon Feb 01". How do I write a regex to ignore the day (Mon) and the time and secs ?
I had asked a related question in an earlier post, which was kindly answered by the community - unable to parse whitespace in regex
This could work :
(Mon|Tue|Wed|Thu|Fri|Sat|Sun) [a-zA-Z]{3} ([0-9]{2}) ([0-9]{2})\:([0-9]{2})\:([0-9]{2}) \+([0-9]{4}) ([0-9]{4})