Some other guy asked a similar question earlier which got a lot of down votes, and I was interested in solving it. I came to a similar issue and would like some help with it.
Take into consideration this wall of text:
__don't__ and __do it__
__yellow__
__green__ and __purple__
I would like to select all the area within the underscores __'s
I attempted the following regex:
/__[!-~]+__/g which worked great on most things. I would like to add the ability to have spaces within the underscores. __do it__ will not be encapsulated in the search because it includes a space which was ruled out by the regex. I attempted the following:
/__[ -~]+__/g
It didn't work as planned, and selected everything from the very first __ to the very last. I was wondering how to tell the regex it has reached the end of a search once it sees a space after a __.
Here is the regex you could play around with below:
http://regexr.com/39br7
I tried using __[^ ]/g at the end but It didn't seem to help.
You could simply use the below regex,
__[^_]*__
DEMO
__(.*?)__
This seems to work.Look at the demo.
http://regex101.com/r/lJ1jB1/1
Related
I am at the beginning of learning Regex, and I use every opportunity to understand how it's working. Currently I am trying to extract dates from a text file (which is in fact a vnt-file type from my mobile phone). It looks like following:
BEGIN:VNOTE
VERSION:1.1
BODY;ENCODING=QUOTED-PRINTABLE;CHARSET=UTF-8:18.07.=0A14.08.=0A15.09.=0A15.10.=
=0A13.11.=0A13.12.=0A12.01.=0A03.02. Grippe=0A06.03.=0A04.04.2015=0A0=
5.05.2015=0A03.06.2015=0A03.07.2015=0A02.08.2015=0A30.08.2015=0A28.09=
17.11.2017=0A
DCREATED:20171118T095601
X-IRMC-LUID:150
END:VNOTE
I want to extract all dates, so that the final list is like that:
18.07.
14.08.
15.09.
15.10.
and so on. If the date has also a year, it should also be displayed.
I almost found out how to detect the dates by the following regex:
.+(\d\d\.\d\d\.(2015|2016|2017)?).+
But it only detect very few of the dates. The result is this:
BEGIN:VNOTE
VERSION:1.1
15.10.
04.04.2015
30.08.2015
24.01.2016
DCREATED:20171118T075601
X-IRMC-LUID:150
END:VNOTE
Then I tried to add a question mark which makes the .+ not greedy, as far as I read in tutorials. Then the regex looks like:
.+?(\d\d\.\d\d\.(2015|2016|2017)?).+?
But the result is still not what I am looking for:
BEGIN:VNOTE
VERSION:1.1
21.03.20.04.18.05.18.06.18.07.14.08.15.09.15.10.
13.11.13.12.12.01.03.02.06.03.04.04.20150A0=
03.06.201503.07.201502.08.201530.08.20150A28.09=
28.10.201525.11.201528.12.201524.01.20160A
DCREATED:20171118T075601
X-IRMC-LUID:150
END:VNOTE
For someone who is familiar with regex I am pretty sure this is very easy to solve, but I don't get it. It's very confusing when you are new to regex. I tried to find a hint in some tutorials or stackoverflow posts, but all I found is this: Notepad++ how to extract only the text field which is needed?
But it doesn't work for me. I assume it might have something to do with the fact that my text file is not one single line.
I have my example on regex101 too.
I would be very thankful if maybe someone can give me a hint what else I can try.
Edit: I would like to detect the dates with the regex and as a result have a list with only the dates (maybe it is called substitute?)
Edit 2: Sorry for not mentioning it earlier: I just want to use the regex in e.g. Notepad++ or an online regex test website. Just to get the result of the dates and save the result in a new txt-file. I don't want to use the regex in an programming language. My apologies for not being precisely before.
Edit 3: The result should be a list with the dates, and each date in a new line:
I want to extract all dates, so that the final list is like that:
18.07.
14.08.
15.09.
15.10.
I suggest this pattern:
(?:.*?|\G)(\d\d\.\d\d\.(?:\d{4})?)
This makes use of the \G flag that, in this case, allows for multiple matches from the very start of the match without letting any single unmatched character in the text, thus allowing the removal of all but what's wanted.
If you want to remove the extra matches as well, add |.* at the end:
(?:.*?|\G)(\d\d\.\d\d\.(?:\d{4})?)|.*
regex101 demo
In N++, make sure the options underlined are selected, and that the cursor is at the beginning. In the picture below, I replaced then undid the replacement, only to show that matches were identified (16 replacements).
You can try using the following pattern:
\d{2}\.\d{2}\.(?:\d{4})?
This will match day.month dates of the form 18.07., but it also allows such a date to be followed by a four digit year, e.g. 18.07.2017. While it would be nice to make the pattern more restrictive, to avoid false fire matches, I do not see anything obvious which can be added to the above pattern. Follow the demo link below to see the pattern in action.
Demo
I run a small forum that has an issue with people using parentheses to bracket statements. They do it to signify they are talking about Jews. I guess it is called echoes or something. So they will put a name like (((Prominent Person))) like that in the middle of a conversation.
I have recently been trying to combat this without just banning people that can't behave. I have a decent word filter but it doesn't block that. I recently installed something that allows me to use regex to strip things out but I am having trouble finding the proper string that doesn't break everything else.
"/\W{3}(.*)\W{3}/","$1"
The first is the matching string and the comma separates what is left. This string works, it strips the parentheses out and leaves everything else alone. The problem is that the string is too broad. It also strips out any [ brackets as well which breaks all of the bbcode in a post. Any post that has any number of at least 3 brackets will be broken after that.
I have been playing with different strings on regex101 but not finding the best solution. I need any time that ((( or ))) is seen to strip out those and replace it with nothing, like it never happened. It has to be exactly three and only ((( and not the other brackets it could trigger on.
Does anyone have a good solution?
\({3}(.*)\){3}
https://regex101.com/r/wD5TMb/1
So in your format probably: "/\({3}(.*)\){3}/","$1"
I'm writing a simple bot that broadcasts messages to clients based on messages from a server. This will be done in JavaScript but I am trying to understand Regex. I've been Googling for the past hour and I've come so close but I am simply unable to solve this one.
Basically I need to retrieve everything between the second / and the first [. It sounds really simple but I cannot figure out how to do this.
Here's some sample code:
192.168.1.1:33291/76561198014386231/testName joined [linux/76561198014386231]
Here's the Regex I've come up with:
\/(.*?)\[
I've found lots of similar questions here on StackOverflow but most of them seem specific to a particular language or end up being too complex and I'm unable to whittle down the query.
I know this is a simple one, but I am totally stumped.
Instead of .*?. Then you could match everything but a forward slash by doing [^\/]*.
([^\/]*)\s*\[
Live preview
If it needs to be after the second slash. As in the contents between the second slash and the square bracket can contain slashes. Then you could do:
(?:.*?\/){2}(.*)\s*\[
Live preview
Remove the \s* if you want to. I'm just assuming you don't care about that whitespace.
I am trying to write a function which removes websites from a piece of text. I have:
removeWebsites<- function(text){
text = gsub("(http://|https://|www.)[[:alnum:]~!#$%&+-=?,:/;._]*",'',text)
return(text)
}
This handles a large set of the problem, but not a popular one, i.e something of the form xyz.com
I do not wish to add .com at the end of the above regex, as it limits the scope of that regex. However I tried writing some more regexex like:
gsub("[[:alnum:]~!#$%&+-=?,:/;._]*.com",'',testset[10])
This worked, but it also modified email ids of the form abc#xyz.com to abc#. I don't want this, so I modified it to
gsub("*((^#)[[:alnum:]~!#$%&+-=?,:/;._]*).com",'\\1',testset[10])
This left the email ids alone but stopped recognising websites of the form xyz.com
I understand that I need some sort of a set difference here, of the form of what was explained here but I was not able to implement it (mainly because I was not able to completely understand it). Any idea on how I go about solving my problem?
Edit: I tried negative lookaheads:
gsub("[[:alnum:]~!#$%&+-=?,:/;._](?!#)[^(?!.*#)]*.com",'',testset[10])
I got a 'invalid regex' error. I believe a little help in correcting may get this to work...
I can't believe it. There actually is a simple solution to it.
gsub(" ([[:alnum:]~!#$%&+-=?,:/;._]+)((.com)|(.net)|(.org)|(.info))",' ',text)
This works by:
Start with a space.
Put all sorts of things, except an '#' in.
end with a .com/net/org/info/
Please do look into breaking it! I'm sure there will be cases that will break this as well.
your lookarounds look a bit funny to me: you cant look behind inside a character class and why are you looking ahead? A look behind is imho more appropriate.
I think the following expression should work, although i didn't test it:
gsub("*((?<!#)[[:alnum:]~!#$%&+-=?,:/;._]*).com",'\\1',testset[10])
also note that lookbehinds must have a fixed length, so no multipliers are allowed
I have written this regex that works, but honestly, it’s like 75% guesswork.
The goal is this: I have lots of imports in Xcode, like so:
#import <UIKit/UIKit.h>
#import "NSString+MultilineFontSize.h"
and I only want to return the categories that contain +. There are also lots of lines of code throughout the source which include + in other contexts.
Right now, this returns all of the proper lines throughout the Xcode project. But if there is one thing I’ve learned from googling and searching Stack Overflow for regex tutorials, it is that there are LOTS of different ways to do things. I’d love to see all of the different ways you guys can come up with that make it either more efficient or more bulletproof regarding potential spoofs or misses.
^\#import+.[\"]*+.(?:(?!\+).)*+.*[\"]
Thanks in advance for all of your help.
Update
Also I suppose I’ll accept the answer of whoever does this with the shortest string, without missing any possible spoofs. But again, thanks to everyone who participates in this learning experience.
Resources from answers
This is an awesome resource for practicing regex from Dan Rasmussen: RegExr
The first thing I notice is that your + characters are misplaced: t+. matches t one or more times, followed by a single character .. I'm assuming you wanted to match the end of import, followed by one or more of any character: import.+
Secondly, # doesn't need to be escaped.
Here's what I came up with: ^#import\s+(.*\+.*)$
\s+ matches one or more whitespace character, so you're guaranteed that the line actually starts with #import and not #importbutnotreally or anything else.
I'm not familiar with xcode syntax, but the following part of the expression, (.*\+.*), simply matches any string with a + character somewhere in it. This means invalid imports may be matched, but I'm working under the assumption your trying to match valid code. If not, this will need to be modified to validate the importer syntax as well.
P.S. To test your expression, try RegExr. You can hover over characters to check what they do.
sed 's:^#import \(.*[+].*\):\1:' FILE
will display
"NSString+MultilineFontSize.h"
for your sample.