I have a complete HTML document string from a web page containing this BASE tag:
<BASE href="http://whatreallyhappened.com/">
In Delphi XE2, I use this regular expression with the whole HTML document as subject to get the URL from the BASE tag between the double quotes:
BaseURL := TRegEx.Match(HTMLDocStr, '(?<=<base(\s)href=").*(?=")', [roIgnoreCase]).Value;
This works, but only if there is only ONE space character in the subject between BASE and href.
I tried to add a quantifier to the space part in the regex (\s), but it did not work.
So how can I make this regex match the URL even if there are several spaces between BASE and href?
You're making this far too complicated by using lookaround. If you want to extract only part of the regex match, simply add a capturing group. Then you can use the text matched by the capturing group instead of the overall match. In most cases you'll also get much better performance this way.
To find the base tag in a file and extract its URL you can use the regex <base[^>]+href=["']([^"']*)["']. Call TRegex.Match() to get a TMatch. This has a Groups property that you can use to retrieve group 1 if a match was found.
With lookaround
You can use different ways to try using quantifiers like these:
(?<=<BASE)\s+href=".*(?=")
(?<=<BASE)\s{0,30}href=".*(?=")
Working demo
Without lookaround
By the way, if you want just to get the content within href there is no need of lookaround you just can use:
<BASE\s+href="(.*?)"
Working demo
EDIT: after reading your comments I figured out a workaround (ugly but could work). You can try using something like this:
((?<=<BASE\shref=")|(?<=<BASE\s\shref=")|(?<=<BASE\s\s\shref=")).*(?=")
^---notice \s ^---notice \s\s ^---notice \s\s\s
I know that this is horrible, but if none of above work you can try with that.
Related
i'm trying to write a regex that matches most cases of HTML elements, like for example:
<script></script>
I would like to make an exception for the following HTML tag specifically:
<b>
Which I don't want to capture. Is there a way to do it without using negative lookahead/lookbehind?
At the moment i have something like this:
((\%3C)|<)[^<b]((\%2F)|\/)*[^<\/b][a-z0-9\%\=\'\(\)\ ]+((\%3E)|>)
https://regex101.com/r/ZxkVMJ/2
It does work, but beside
<b>
it also doesn't capture all 1 character tags
(like <a> for example)
as well as longer tags that start with b, like for example
<balloon>
Thank you for any help
As a disclaimer, if you have the availability of any kind of XML/HTML parser, you should really use that for your current problem. If you are forced to use regex here, then consider this pattern:
<([^b][^>]*|b[^>]+)>.*?<\/\1>
This matches an HTML tag which either starts with a letter other than b, or a tag which does start with b, but then is followed by one or more other characters (thus ruling out <b>). Here is a working demo:
Demo
Consider the following input string (part of css file):
url('data:image/png;base64,iVBORw0KGgoAAAAN...');
url(example.png);
The objective is to take the url part using regex and do something with it. So the first part is easy:
url\(['"]?(.+?)['"]?\)
Basically, it takes contents from inside url(...) with optional quotes symbols. Using this regexp I get the following matches:
data:image/png;base64,iVBORw0KGgoAAAAN...
example.png
So far so good. Now I want to exclude the urls which include 'data:image' in their text. I think negative lookahead is the proper tool for that but using it like this:
url\(['"]?(?!data:image)(.+?)['"]?\)
gives me the following result for the first url:
'data:image/png;base64,iVBORw0KGgoAAAAN...
Not only it doesn't exclude this match, but the matched string itself now includes quote character at the beginning. If I use + instead of first ? like this:
url\(['"]+(?!data:image)(.+?)['"]?\)
it works as expected, url is not matched. But this doesn't allow the optional quote in url (since + is 1 or more). How should I change the regex to exclude given url?
You can use negative lookahead like this:
url\((['"]?)((?:(?!data:image).)+?)\1?\)
RegEx Demo
In one of my XML file I need to find and replace some opening tags names using regex and Notepad++. Also I need to leave unchanged every text between them.
Example:
<uri>http://domain-name.com/41874_01_home_big.jpg</image_big>
I need to change into:
<image_big>http://domain-name.com/41874_01_home_big.jpg</image_big>
For some reasons I can't just change uri tag, cause there are others closing tags like /image_small in the document (opened with uri of course).
I tried to change it like:
<uri>.*?</image_big>
But I don't know with what I should replace it.
I tried with:
<image_big>\1</image_big>
but result is:
<image_big></image_big>
without any text inside.
I need your help. I'm not good with regex.
Just put .*? inside a capturing group.
<uri>(.*?)<\/image_big>
Then replace the match with <image_big>\1</image_big> or <image_big>$1</image_big>
Your regex <uri>.*?</image_big> matches correctly but in-order to fetch all the characters which are matched by .*? pattern, you must need to put that pattern inside a capturing group. So that we could back-reference it for later use.
DEMO
Find:<uri>(.*?)</image_big>
Replace:<image_big>\1</image_big> or <image_big>$1</image_big>
See demo.
https://www.regex101.com/r/rK5lU1/19
I have a load of links that look like this:
Taboola - Content you may like
I want to delete the entire ICON and ADD_DATE attributes and their values.
I'm using sublime with a regex find/replace but I'm not sure how to write the regex to grab everything in between ICON=" AND "
Any help would be appreciated!
This should work (escaping quotes as necessary):
ICON="[^"]*"
The reason ICON=\"(.*)" won't work is that regex can 'be greedy' in what it takes. This means that if it can match more of the string to satisfy the pattern it will.
You can either specify a non greedy search, such as ICON=".*?" or explicitly declare matches on atoms that are not quotes as in the above answer.
im looking to use a regular expression to parse a URL to get a specific section of the url and nothing if I cannot find the pattern.
A url example is
/te/file/value/jifle?uil=testing-cdas-feaw:jilk:&jklfe=https://value-value.jifels/temp.html/topic?id=e997aad4-92e0-j30e-a3c8-jfkaliejs5#c452fds-634d-f424fds-cdsa&bf_action=jildape
I wish to get the bolded text in it.
Currently im using the regex "d=([^#]*)" but the problem is im also running across urls of this pattern:
and im getting the bold section of it
/te/file/value/jifle?uil=testing-cdas-feaw:jilk:&jklfe=https://value-value.jifels/temp.html/topic?id=e997aad4-92e0-j30e-a3c8-jfkaliejs5&bf_action=jildape
I would prefer it have no matches of this url because it doesnt contain the #
Regexes are not a magic tool that you should always use just because the problem involves a string. In this case, your language probably has a tool to break apart URLs for you. In PHP, this is parse_url(). In Perl, it's the URI::URL module.
You should almost always prefer an existing, well-tested solution to a common problem like this rather than writing your own.
So you want to match the value of the id parameter, but only if it has a trailing section containing a '#' symbol (without matching the '#' or what's after it)?
Not knowing the specifics of what style of regexes you're using, how about something like:
id=([^#&]*)#
regex = "id=([\\w-])+?#"
This will grab everything that is character class[a-zA-Z_0-9-] between 'id=' and '#' assuming everything between 'id=' and '#' is in that character class(i.e. if an '&' is in there, the regex will fail).
id=
-Self explanatory, this looks for the exact match of 'id='
([\\w-])
-This defines and character class and groups it. The \w is an escaped \w. '\w' is a predefined character class from java that is equal to [a-zA-Z_0-9]. I added '-' to this class because of the assumed pattern from your examples.
+?
-This is a reluctant quantifier that looks for the shortest possible match of the regex.
#
-The end of the regex, the last character we are looking for to match the pattern.
If you are looking to grab every character between 'id=' and the first '#' following it, the following will work and it uses the same logic as above, but replaces the character class [\\w-] with ., which matches anything.
regex = "id=(.+?)#"