Cannot Get C++ Function to Use String from User - c++

Please help.
I have this program from here that calls a function in a header file.
#include <iostream>
#include "md5.h"
#include <string>
using namespace std;
int main(){
string x;
char* v_MD5String;
MD5 md5 ;
v_MD5String = "Hello World";
x = puts(md5.digestString(v_MD5String));
cout << x;
return 0;}
The function called:
char* digestString( char *string ){
Init() ;
Update( (unsigned char*)string, strlen(string) ) ;
Final() ;
return digestChars ;}
The above works, however when I use input from the user it compiles, but the run crashes without any errors.
In the program, this is changed:
v_MD5String = "Hello World";
to this:
cin >> v_MD5String;
What should I do to get this to work?
Thanks.

So, if I understand correctly, you have the following function declared in a header file which you cannot modify:
char* digestString( char *string );
You should first know that this is questionable coding style. The function takes a char * rather than a char const *, which implies that the passed data is changed, yet it also returns something. I had to dig around in the implementation posted on the page you linked to find out that string is really an input parameter, so that the author just forgot about using const and the data is not going to be changed anyway.
(The data not going to be modified is at least my assumption upon superficial code analysis and some compile tests. You should ask the author to be really sure!)
If you use this function in C++, your first task should be to provide a safer, easy-to-understand wrapper function which uses real C++ strings (the std::string class), not C strings (which happen to be completely unencapsulated pointers to characters in memory, which is fine in the C world but not in C++). You already use one std::string in your program. That's good. Now use it more:
std::string SafeDigestString(MD5 &md5, std::string const &input)
{
// the input of digestString will never be modified:
return md5.digestString(const_cast<char *>(input.c_str()));
}
Both the const & and the parameter name make it clear that we are dealing with input.
Note that I used a const_cast<char *> to pass the std::string's C-compatible data representation, which is char const *, to the digestString function. This is one of the rare cases where a const_cast is appropriate; it's also a typical one, namely making up for shortcomings with regards to const declarations in other code you have to use. If all functions in the MD5 class correctly declared their input parameters const, then no const_cast would be needed.
Also note that I just prepend every std identifier with std::, rather than having using namespace std. This is often the better, simpler, more consistent choice.
Now that we have our safe C++ mechanism in place, main becomes drastically simpler:
int main()
{
MD5 md5;
std::string result = SafeDigestString(md5, "Hello World");
std::cout << result << "\n";
}
We have laid the base to implement user input, which is best done with the std::getline function:
int main()
{
MD5 md5;
std::string input;
std::getline(std::cin, input);
std::string result = SafeDigestString(md5, input);
std::cout << result << "\n";
}

Related

Extracting and Creating separate txt files for each line of the source file [duplicate]

This question already has answers here:
Easiest way to convert int to string in C++
(30 answers)
Closed 7 years ago.
I was wondering if there was an alternative to itoa() for converting an integer to a string because when I run it in visual Studio I get warnings, and when I try to build my program under Linux, I get a compilation error.
In C++11 you can use std::to_string:
#include <string>
std::string s = std::to_string(5);
If you're working with prior to C++11, you could use C++ streams:
#include <sstream>
int i = 5;
std::string s;
std::stringstream out;
out << i;
s = out.str();
Taken from http://notfaq.wordpress.com/2006/08/30/c-convert-int-to-string/
boost::lexical_cast works pretty well.
#include <boost/lexical_cast.hpp>
int main(int argc, char** argv) {
std::string foo = boost::lexical_cast<std::string>(argc);
}
Archeology
itoa was a non-standard helper function designed to complement the atoi standard function, and probably hiding a sprintf (Most its features can be implemented in terms of sprintf): http://www.cplusplus.com/reference/clibrary/cstdlib/itoa.html
The C Way
Use sprintf. Or snprintf. Or whatever tool you find.
Despite the fact some functions are not in the standard, as rightly mentioned by "onebyone" in one of his comments, most compiler will offer you an alternative (e.g. Visual C++ has its own _snprintf you can typedef to snprintf if you need it).
The C++ way.
Use the C++ streams (in the current case std::stringstream (or even the deprecated std::strstream, as proposed by Herb Sutter in one of his books, because it's somewhat faster).
Conclusion
You're in C++, which means that you can choose the way you want it:
The faster way (i.e. the C way), but you should be sure the code is a bottleneck in your application (premature optimizations are evil, etc.) and that your code is safely encapsulated to avoid risking buffer overruns.
The safer way (i.e., the C++ way), if you know this part of the code is not critical, so better be sure this part of the code won't break at random moments because someone mistook a size or a pointer (which happens in real life, like... yesterday, on my computer, because someone thought it "cool" to use the faster way without really needing it).
Try sprintf():
char str[12];
int num = 3;
sprintf(str, "%d", num); // str now contains "3"
sprintf() is like printf() but outputs to a string.
Also, as Parappa mentioned in the comments, you might want to use snprintf() to stop a buffer overflow from occuring (where the number you're converting doesn't fit the size of your string.) It works like this:
snprintf(str, sizeof(str), "%d", num);
Behind the scenes, lexical_cast does this:
std::stringstream str;
str << myint;
std::string result;
str >> result;
If you don't want to "drag in" boost for this, then using the above is a good solution.
We can define our own iota function in c++ as:
string itoa(int a)
{
string ss=""; //create empty string
while(a)
{
int x=a%10;
a/=10;
char i='0';
i=i+x;
ss=i+ss; //append new character at the front of the string!
}
return ss;
}
Don't forget to #include <string>.
С++11 finally resolves this providing std::to_string.
Also boost::lexical_cast is handy tool for older compilers.
I use these templates
template <typename T> string toStr(T tmp)
{
ostringstream out;
out << tmp;
return out.str();
}
template <typename T> T strTo(string tmp)
{
T output;
istringstream in(tmp);
in >> output;
return output;
}
Try Boost.Format or FastFormat, both high-quality C++ libraries:
int i = 10;
std::string result;
WIth Boost.Format
result = str(boost::format("%1%", i));
or FastFormat
fastformat::fmt(result, "{0}", i);
fastformat::write(result, i);
Obviously they both do a lot more than a simple conversion of a single integer
You can actually convert anything to a string with one cleverly written template function. This code example uses a loop to create subdirectories in a Win-32 system. The string concatenation operator, operator+, is used to concatenate a root with a suffix to generate directory names. The suffix is created by converting the loop control variable, i, to a C++ string, using the template function, and concatenating that with another string.
//Mark Renslow, Globe University, Minnesota School of Business, Utah Career College
//C++ instructor and Network Dean of Information Technology
#include <cstdlib>
#include <iostream>
#include <string>
#include <sstream> // string stream
#include <direct.h>
using namespace std;
string intToString(int x)
{
/**************************************/
/* This function is similar to itoa() */
/* "integer to alpha", a non-standard */
/* C language function. It takes an */
/* integer as input and as output, */
/* returns a C++ string. */
/* itoa() returned a C-string (null- */
/* terminated) */
/* This function is not needed because*/
/* the following template function */
/* does it all */
/**************************************/
string r;
stringstream s;
s << x;
r = s.str();
return r;
}
template <class T>
string toString( T argument)
{
/**************************************/
/* This template shows the power of */
/* C++ templates. This function will */
/* convert anything to a string! */
/* Precondition: */
/* operator<< is defined for type T */
/**************************************/
string r;
stringstream s;
s << argument;
r = s.str();
return r;
}
int main( )
{
string s;
cout << "What directory would you like me to make?";
cin >> s;
try
{
mkdir(s.c_str());
}
catch (exception& e)
{
cerr << e.what( ) << endl;
}
chdir(s.c_str());
//Using a loop and string concatenation to make several sub-directories
for(int i = 0; i < 10; i++)
{
s = "Dir_";
s = s + toString(i);
mkdir(s.c_str());
}
system("PAUSE");
return EXIT_SUCCESS;
}
Allocate a string of sufficient length, then use snprintf.
int number = 123;
stringstream = s;
s << number;
cout << ss.str() << endl;
I wrote this thread-safe function some time ago, and am very happy with the results and feel the algorithm is lightweight and lean, with performance that is about 3X the standard MSVC _itoa() function.
Here's the link. Optimal Base-10 only itoa() function? Performance is at least 10X that of sprintf(). The benchmark is also the function's QA test, as follows.
start = clock();
for (int i = LONG_MIN; i < LONG_MAX; i++) {
if (i != atoi(_i32toa(buff, (int32_t)i))) {
printf("\nError for %i", i);
}
if (!i) printf("\nAt zero");
}
printf("\nElapsed time was %f milliseconds", (double)clock() - (double)(start));
There are some silly suggestions made about using the caller's storage that would leave the result floating somewhere in a buffer in the caller's address space. Ignore them. The code I listed works perfectly, as the benchmark/QA code demonstrates.
I believe this code is lean enough to use in an embedded environment. YMMV, of course.
The best answer, IMO, is the function provided here:
http://www.jb.man.ac.uk/~slowe/cpp/itoa.html
It mimics the non-ANSI function provided by many libs.
char* itoa(int value, char* result, int base);
It's also lightning fast and optimizes well under -O3, and the reason you're not using c++ string_format() ... or sprintf is that they are too slow, right?
If you are interested in fast as well as safe integer to string conversion method and not limited to the standard library, I can recommend the format_int method from the {fmt} library:
fmt::format_int(42).str(); // convert to std::string
fmt::format_int(42).c_str(); // convert and get as a C string
// (mind the lifetime, same as std::string::c_str())
According to the integer to string conversion benchmarks from Boost Karma, this method several times faster than glibc's sprintf or std::stringstream. It is even faster than Boost Karma's own int_generator as was confirm by an independent benchmark.
Disclaimer: I'm the author of this library.
Note that all of the stringstream methods may involve locking around the use of the locale object for formatting. This may be something to be wary of if you're using this conversion from multiple threads...
See here for more. Convert a number to a string with specified length in C++
On Windows CE derived platforms, there are no iostreams by default. The way to go there is preferaby with the _itoa<> family, usually _itow<> (since most string stuff are Unicode there anyway).
Most of the above suggestions technically aren't C++, they're C solutions.
Look into the use of std::stringstream.

How can I return a string value from a function in C++

#include <iostream>
#include <string>
using namespace std;
std::string dispCard(int card)
{
string textCard = "help";
//cout << textCard;
system("pause");
return textCard;
}
int main()
{
// Using this area to test functions for now
cout << dispCard(14);
return 0;
}
Uncommenting the cout line actually does display the value. But I cannot return the value in the string.
Honestly, I have no idea why this isn't working. I initially just wanted to use "char" but that doesn't work for some reason.
Visual Studio didn't like:
char test;
test = "help";
It underlined the "=".
For now, I just want to return a string value from a function. There's more that I need it to do, but this is the main issue right now.
Uncommenting the cout line actually does display the string. But not returning the string.
Your program both prints and returns the string, printing it again in main. The only problems I can see with your program are:
You are using system("pause") for no reason.
You are not consistent with the use of either the std:: prefix or importing the namespace. On this regard I highly suggest the std:: prefix.
You are not using the function argument.
I initially just wanted to use "char" but that doesn't work for some reason.
Well, char, as the name suggests, can only store 1 characters. In:
char test = "help";
you are trying to assign 5 characters (4 + \0) to an objects who's size can only store 1. That's the reason why your compiler complained.
I think you need to pass an int to your function and get it back in string form. To do this conversion you need something like this:
std::ostringstream stm;
stm << yourIntValue;
std::string s(stm.str());
or this:
char bf[100];
sprintf(bf, "%d", yourIntValue);
std::string s(bf);
If you put this snippet in a function then you can also accept an int parameter, convert it to a std::string and return the std::string as others have shown.
What you need to do is to declare return type of function as std::string and then return either a string object, something that can implicitly be converted to string object or something that explicitly constructs string object.
Example:
std::string foo(){
return "idkfa"; //return C-style string -> implicitly convertible to string
return {"idkfa"}; // direct initialization of returning std::string
return std::string("idkfa"); //return explicitly constructed std::string object
}
Also note that C-style strings are of type char* (C-style strings are basically an array of chars, with last element being \0, that is 0).
Your code works perfectly fine, though the the system("pause") is totally redundant and pointless and should be removed. It may in fact be confusing you.

C++: How to build Strings / char*

I'm new to C++. I want to make a char*, but I don't know how.
In Java is it just this:
int player = 0;
int cpu = 0;
String s = "You: " + player + " CPU: " + cpu;
How can I do this? I need a char*.
I'm focusing on pasting the integer after the string.
You almost certainly don't want to deal with char * if you can help it - you need the C++ std::string class:
#include <string>
..
string name = "fred";
or the related stringstream class:
#include <sstream>
#include <string>
#include <iostream>
using namespace std;
int main() {
int player = 0;
int cpu = 0;
ostringstream os;
os << "You: " << player << " CPU: " << cpu;
string s = os.str();
cout << s << endl;
}
if you really need a character pointer (and you haven't said why you think you do), you can get one from a string by using its c_str() member function.
All this should be covered by any introductory C++ text book. If you haven't already bought one, get Accelerated C++. You cannot learn C++ from internet resources alone.
If you're working with C++, just use std::string. If you're working with char*, you probably want to work with C directly. In case of C, you can use the sprintf function:
char* s = // initialized properly
sprintf( s, "You: %d CPU: %d", player, cpu );
Just call s.c_str( );.Here you you can see more.
PS. You can use strcpy to copy the content to new variable and then you will be able to change it.
char * means "pointer to a character".
You can create a pointer to a 'string' like this:
char* myString = "My long string";
Alternatively you can use std::string:
std::string myStdString("Another long string");
const char* myStdString.c_str();
Notice the const at the beginning of the last example. This means you can't change the chars that are pointed to. You can do the same with the first example:
const char* = "My long string";
Consider using stringstreams:
#include <iostream>
#include <sstream>
using namespace std;
int main ()
{
int i = 10;
stringstream t;
t << "test " << i;
cout << t.str();
}
It probably would have been for the best if C++ had overloaded the "+" operator like you show. Sadly, they didn't (you can though, if you want to).
There are basicly three methods for converting integer variables to strings in C++; two inherited from C and one new one for C++.
The itoa() routine. This is actually non-standard, but most compilers have it. The nice thing about it is that it returns a pointer to the string, so it can be used in functional-style programming.
sprintf(). The second holdover from C, this routine takes a destination string, a format string, and a list of parameters. How many parameters there are, and how they are interpreted depend on how the "format" string parses. This makes sprintf both immensely powerful and immensely dangerous. If you use this approach, I can pretty much guarantee you will have crash bugs your first few tries.
std::ostringstream. The C++ way. This has pretty much all the power of sprintf(), but is much safer. The drawback here is that you have to declare it, and it is not a string, so you still have to convert it to one when you are done. That means at least three lines of code are required to do anything with an ostringstream. It is also really ugly, particularly if you try any special formatting.

Alternative to itoa() for converting integer to string C++? [duplicate]

This question already has answers here:
Easiest way to convert int to string in C++
(30 answers)
Closed 7 years ago.
I was wondering if there was an alternative to itoa() for converting an integer to a string because when I run it in visual Studio I get warnings, and when I try to build my program under Linux, I get a compilation error.
In C++11 you can use std::to_string:
#include <string>
std::string s = std::to_string(5);
If you're working with prior to C++11, you could use C++ streams:
#include <sstream>
int i = 5;
std::string s;
std::stringstream out;
out << i;
s = out.str();
Taken from http://notfaq.wordpress.com/2006/08/30/c-convert-int-to-string/
boost::lexical_cast works pretty well.
#include <boost/lexical_cast.hpp>
int main(int argc, char** argv) {
std::string foo = boost::lexical_cast<std::string>(argc);
}
Archeology
itoa was a non-standard helper function designed to complement the atoi standard function, and probably hiding a sprintf (Most its features can be implemented in terms of sprintf): http://www.cplusplus.com/reference/clibrary/cstdlib/itoa.html
The C Way
Use sprintf. Or snprintf. Or whatever tool you find.
Despite the fact some functions are not in the standard, as rightly mentioned by "onebyone" in one of his comments, most compiler will offer you an alternative (e.g. Visual C++ has its own _snprintf you can typedef to snprintf if you need it).
The C++ way.
Use the C++ streams (in the current case std::stringstream (or even the deprecated std::strstream, as proposed by Herb Sutter in one of his books, because it's somewhat faster).
Conclusion
You're in C++, which means that you can choose the way you want it:
The faster way (i.e. the C way), but you should be sure the code is a bottleneck in your application (premature optimizations are evil, etc.) and that your code is safely encapsulated to avoid risking buffer overruns.
The safer way (i.e., the C++ way), if you know this part of the code is not critical, so better be sure this part of the code won't break at random moments because someone mistook a size or a pointer (which happens in real life, like... yesterday, on my computer, because someone thought it "cool" to use the faster way without really needing it).
Try sprintf():
char str[12];
int num = 3;
sprintf(str, "%d", num); // str now contains "3"
sprintf() is like printf() but outputs to a string.
Also, as Parappa mentioned in the comments, you might want to use snprintf() to stop a buffer overflow from occuring (where the number you're converting doesn't fit the size of your string.) It works like this:
snprintf(str, sizeof(str), "%d", num);
Behind the scenes, lexical_cast does this:
std::stringstream str;
str << myint;
std::string result;
str >> result;
If you don't want to "drag in" boost for this, then using the above is a good solution.
We can define our own iota function in c++ as:
string itoa(int a)
{
string ss=""; //create empty string
while(a)
{
int x=a%10;
a/=10;
char i='0';
i=i+x;
ss=i+ss; //append new character at the front of the string!
}
return ss;
}
Don't forget to #include <string>.
С++11 finally resolves this providing std::to_string.
Also boost::lexical_cast is handy tool for older compilers.
I use these templates
template <typename T> string toStr(T tmp)
{
ostringstream out;
out << tmp;
return out.str();
}
template <typename T> T strTo(string tmp)
{
T output;
istringstream in(tmp);
in >> output;
return output;
}
Try Boost.Format or FastFormat, both high-quality C++ libraries:
int i = 10;
std::string result;
WIth Boost.Format
result = str(boost::format("%1%", i));
or FastFormat
fastformat::fmt(result, "{0}", i);
fastformat::write(result, i);
Obviously they both do a lot more than a simple conversion of a single integer
You can actually convert anything to a string with one cleverly written template function. This code example uses a loop to create subdirectories in a Win-32 system. The string concatenation operator, operator+, is used to concatenate a root with a suffix to generate directory names. The suffix is created by converting the loop control variable, i, to a C++ string, using the template function, and concatenating that with another string.
//Mark Renslow, Globe University, Minnesota School of Business, Utah Career College
//C++ instructor and Network Dean of Information Technology
#include <cstdlib>
#include <iostream>
#include <string>
#include <sstream> // string stream
#include <direct.h>
using namespace std;
string intToString(int x)
{
/**************************************/
/* This function is similar to itoa() */
/* "integer to alpha", a non-standard */
/* C language function. It takes an */
/* integer as input and as output, */
/* returns a C++ string. */
/* itoa() returned a C-string (null- */
/* terminated) */
/* This function is not needed because*/
/* the following template function */
/* does it all */
/**************************************/
string r;
stringstream s;
s << x;
r = s.str();
return r;
}
template <class T>
string toString( T argument)
{
/**************************************/
/* This template shows the power of */
/* C++ templates. This function will */
/* convert anything to a string! */
/* Precondition: */
/* operator<< is defined for type T */
/**************************************/
string r;
stringstream s;
s << argument;
r = s.str();
return r;
}
int main( )
{
string s;
cout << "What directory would you like me to make?";
cin >> s;
try
{
mkdir(s.c_str());
}
catch (exception& e)
{
cerr << e.what( ) << endl;
}
chdir(s.c_str());
//Using a loop and string concatenation to make several sub-directories
for(int i = 0; i < 10; i++)
{
s = "Dir_";
s = s + toString(i);
mkdir(s.c_str());
}
system("PAUSE");
return EXIT_SUCCESS;
}
Allocate a string of sufficient length, then use snprintf.
int number = 123;
stringstream = s;
s << number;
cout << ss.str() << endl;
I wrote this thread-safe function some time ago, and am very happy with the results and feel the algorithm is lightweight and lean, with performance that is about 3X the standard MSVC _itoa() function.
Here's the link. Optimal Base-10 only itoa() function? Performance is at least 10X that of sprintf(). The benchmark is also the function's QA test, as follows.
start = clock();
for (int i = LONG_MIN; i < LONG_MAX; i++) {
if (i != atoi(_i32toa(buff, (int32_t)i))) {
printf("\nError for %i", i);
}
if (!i) printf("\nAt zero");
}
printf("\nElapsed time was %f milliseconds", (double)clock() - (double)(start));
There are some silly suggestions made about using the caller's storage that would leave the result floating somewhere in a buffer in the caller's address space. Ignore them. The code I listed works perfectly, as the benchmark/QA code demonstrates.
I believe this code is lean enough to use in an embedded environment. YMMV, of course.
The best answer, IMO, is the function provided here:
http://www.jb.man.ac.uk/~slowe/cpp/itoa.html
It mimics the non-ANSI function provided by many libs.
char* itoa(int value, char* result, int base);
It's also lightning fast and optimizes well under -O3, and the reason you're not using c++ string_format() ... or sprintf is that they are too slow, right?
If you are interested in fast as well as safe integer to string conversion method and not limited to the standard library, I can recommend the format_int method from the {fmt} library:
fmt::format_int(42).str(); // convert to std::string
fmt::format_int(42).c_str(); // convert and get as a C string
// (mind the lifetime, same as std::string::c_str())
According to the integer to string conversion benchmarks from Boost Karma, this method several times faster than glibc's sprintf or std::stringstream. It is even faster than Boost Karma's own int_generator as was confirm by an independent benchmark.
Disclaimer: I'm the author of this library.
Note that all of the stringstream methods may involve locking around the use of the locale object for formatting. This may be something to be wary of if you're using this conversion from multiple threads...
See here for more. Convert a number to a string with specified length in C++
On Windows CE derived platforms, there are no iostreams by default. The way to go there is preferaby with the _itoa<> family, usually _itow<> (since most string stuff are Unicode there anyway).
Most of the above suggestions technically aren't C++, they're C solutions.
Look into the use of std::stringstream.

Making a method template - C++

Below code is used to get a std::string representation from ASCII code.
string Helpers::GetStringFromASCII(const int asciiCode) const
{
return string(1,char(asciiCode));
}
It works well. But in my application, I know the ASCII codes at compile time. So I will be calling it like
string str = GetStringFromASCII(175) // I know 175 at compile time
Question
Is there any way to make the GetStringFromASCII method a template so that the processing happens at compile time and I can avoid calling the function each time at runtime.
Any thoughts?
This kind of template meta programming works well when you're dealing with primitive data types like ints and floats. If you necessarily need a string object, you can't avoid calling the std::string constructor and there's no way that call can happen at compile time. Also, I don't think you can drag the cast to char to compile time either, which, in all, means that templates cannot help you here.
Instead of feeding an int constant to a string conversion function, use a string constant directly:
string str("\xAF"); // 0xAF = 175
By the way, except for heavy performance needs in a loop, trading code readability for some CPU cycles is rarely money effective overall.
Why are you even bothering with a helper function?
string s( 1, char(175) );
That's all you need and it's the quickest you're going to get.
How about something like this:
#include <iostream>
#include <string>
using namespace std;
template <int asciiCode>
inline string const &getStringFromASCII()
{
static string s(1,char(asciiCode));
return s;
}
int main(int, char const**) {
cout << getStringFromASCII<65>() << endl;
}
EDIT: returns a ref now