get string array from text list c++ - c++

Question

my text file was like
123456123456
Jason
uk
012456788
1000
456789456789
david
uk
012456788
1000
i'm trying to get the data from a text file and save it into arrays
however when i want to store the data from the text file into array it loop non-stop.
what should i do ?
the problem exiting in looping or the method i get the data from text file ?
code:
#include <iostream>
#include <fstream>
using namespace std;
typedef struct {
char acc_no[12];
char name[30];
char address[50];
char phone_no[12];
double balance;
} ACCOUNT;
//function prototype
void menu();
void read_data(ACCOUNT record[]);
int main() {
ACCOUNT record[31]; //Define array 'record' which have maximum size of 30
read_data(record);
}
//--------------------------------------------------------------------
void read_data(ACCOUNT record[]) {
ifstream openfile("list.txt"); //open text file
if (!openfile) {
cout << "Error opening input file\n";
return 0;
} else {
int loop = -1; //size of array
cout << "--------------Data From File--------------"<<endl;
while (!openfile.eof()) {
if (openfile.peek() == '\n')
openfile.ignore(256, '\n');
openfile.getline(record[++loop].acc_no, 12);
openfile.getline(record[loop].name, 30);
openfile.getline(record[loop].address, 50);
openfile.getline(record[loop].phone_no, 12);
openfile >> record[loop].balance;
}
openfile.close(); //close text file
for (int i = 0; i <= loop + 1; i++) {
cout << "Account " << endl;
cout << "Account No. : " << record[i].acc_no << endl;
cout << "Name : " << record[i].name << endl;
cout << "Address : " << record[i].address << endl;
cout << "Phone Number : " << record[i].phone_no << endl;
cout << "Balance : " << record[i].balance << endl;
}
}
}

Answer 1

UPDATE:
The OP didn't properly cite the correct format in his data file. This answer is only valid up until the last iteration.
Don't use .eof() - that's more applicable to when you want to open the file and read it by characters.
A better way would be to use the insertion operator >> as follows:
#define ARR_SIZE 31
ACCOUNT temp;
ACCOUNT record[ARR_SIZE];
int i=0;
while(i < ARR_SIZE) {
openfile >> temp.acc_no >> temp.name >> temp.address >> temp.phone_no >> temp.balance;
record[i] = temp;
i++;
}
Of course, even better is to use std::string to hold the values from the input file, in addition to using std::vectors instead of arrays.