Read input file word by word [closed] - c++

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I will first off say that yes, this is a homework assignment, but my teacher is really not too clear on how to do things.
I'm asked to, in c++, Write a function that will pass words from a file one at a time. The function will calculate the word length and then print out TO SCREEN the word and its length on its own line.
The main will open your input file, read it word by word in a loop and then pass the word into your function for it to be printed.
I know how to open a file using fstream and all that, read it word by word, but not in a loop or a function by the void readfile () one. My problem here is putting everything together.
This is my program to open a file, get the length and display it in a parallel array
//declare parallel arrays
string words [MAXSIZE];
//open files
outputFile.open("output.txt");
inputFile.open ("/Users/cathiedeane/Documents/CIS 22A/Lab 4/Lab 4 Part 2/lab4.txt");
//inputvalidation
while (!inputFile.eof())
{
for(int i = 0; i < MAXSIZE; ++i)
{
outputFile << words[i] << " " << endl;
inputFile >> words[i];
}
inputFile.close();
}
for (int i= 0; i <= MAXSIZE; i++)
{ cout << words[i] << ":" << words[i].size()<< endl;
outputFile << endl;
}
//close outputfile
outputFile.close();
return 0;
}

Answer 1

So basically your assignment is :
function read_word
/* what you have to work on */
end
function read_file_word_by_word
open file
while not end_of_file
word = read_word
print word, word_length
end
close file
end
To read a word, you need to define what it is. Usually it's a bunch of letters, delimited by other characters that are not letters (whitespace, commas, etc.).
You could read the file character by character and store them when they are letters until you encounter some other kind of character. What you have stored is a word, and you can get its length quite easily.
Tip: http://www.cplusplus.com/reference/istream/istream/get/ allows you to read a single character from a file.

Answer 2

#include <fstream>
#include <iostream>
#include <string>
using namespace std;
void func(const string& word)
{
//set field width
cout.width(30);
cout << left << word << " " << word.size() << endl;
}
int main(int argc, char* argv[])
{
ifstream ifs("F:\\tmp\\test.txt");
if(ifs.fail())
{
cout << "fail to open file" << endl;
return -1;
}
_Ctypevec ct = _Getctype();
for(char ch = 0; ch < SCHAR_MAX; ch++)
{
//set all punctuations as field separator of extraction
if(ispunct(ch))
{
(const_cast<short*>(ct._Table))[ch] = ctype<char>::space;
}
}
//change the default locale object of ifstream
ifs.imbue(locale(ifs.getloc(), new ctype<char>(ct._Table)));
string word;
while(ifs >> word)
{
func(word);
}
ifs.close();
}

Answer 3

You'll obviously want to separate each word in to its own string index to store them in your array. To separate each word, establish a break point like char break = ' '; Then, while your IOStream is reading the file, just add the words to the index using an iterator (i++)

Answer 4

Now that some time has passed since you asked the question, I would like to add that this could be answered in a quite small amount of code:
#include <iostream>
#include <string>
#include <fstream>
using namespace std;
void printString( const string & str ) { // ignore the & for now, you'll get to it later.
cout << str << " : " << str.size() << endl;
}
int main() {
ifstream fin("your-file-name.txt");
if (!fin) {
cout << "Could not open file" << endl;
return 1;
}
string word; // You only need one word at a time.
while( fin >> word ) {
printString(word);
}
fin.close();
}
A small note on fin >> word, this expression returns true for as long as there was a word read into the string. It will also skip any whitespace (tab, space and newline) by default.