Is there any way for Visual Studio IDE to automatically create (autocomplete) the bare codebase for a new class' parent class' virtual methods (ie. all parent members are virtual rval foo(x) = 0;) without using a class wizard?
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Suppose a C++ method overrides a base class's method, then how to jump to the definition/declaration of the base method from the source of method? (e.g. pop up a window to show a list of base methods that it overrides)
How to Skip class from unittest in visual studio 2019
ClienteRepositoryTests extends RepositoryTestBase.
RepositoryTestBase is a base for all unittests. I'd like that RepositoryTest dont show in Test Explorer
Make the base class abstract.
Both XUnit and MSTest (and probably other frameworks) use reflection to find correctly decorated methods (or types) and have to instantiate them in order to run the tests. If your class is abstract, the method will still exist on the derived type (still decorated as a test method), but the base class cannot be instantiated.
In Visual Studio 2013 when I go to Class View, then search for a class, then expand "Derived Types" folder it shows me only the classes derived from this class in the current project, but not the whole solution. Is there a way to find all the derived classes in the solution in Visual Studio 2013 or perhaps some plugins? The language in focus is C++ (unmanaged).
I have the same question. So far I am making do with a regular expression that matches part of the declaration of the derived class:
:\s*(public|private|protected)?\s+ClassName
For example when searching for all classes derived from class A in the following:
class B : public A {};
The regular expression tries to match the : public A. Note this will not work when A is not first base class in the list of base classes. Also does not work for indirect descendants.
Using C++11 is it possible to specify class special member functions as defaulted and deleted?
I'm using Visual Studio 2012 version 11.0 and trying to set some class constructor as defaulted. Need to say this is abstract class and IDE underscores this code part as wrong. Also when I modify this class not to be abstract, the situation is the same.
class IProgressObserver {
public:
IProgressObserver() =default;
virtual ~IProgressObserver(){}
virtual void reportProgress(void* reporter,
std::int32_t done,
std::int32_t total) = 0;
};
You can default special member functions in C++11, but VS11 does not support that.
Support has been added in VS12 (2013) -- but not for move constructors / assignment-operators.
See MSDN: Support For C++11 Features
Any convenient method to know if a method is virtual in visual studio without deeply checking its base classes.
I suggest to use the override specifier on any virtual method. It is supported in visual studio since VS2010. It helps you to avoid errors (such as misspelling an override or wrong parameter types) and clearly marks every virtual function as such.