How to get certain keys from a list of dictionaries? - list

I have a list of dictionaries that I need to extract certain keys from each of the dictionaries in the list.
The list of dictionaries looks like so:
[{u'api_detail_url': u'http://www.giantbomb.com/api/platform/3045-94/', u'abbreviation': u'PC', u'site_detail_url': u'http://www.giantbomb.com/pc/3045-94/', u'id': 94, u'name': u'PC'}, {u'api_detail_url': u'http://www.giantbomb.com/api/platform/3045-35/', u'abbreviation': u'PS3', u'site_detail_url': u'http://www.giantbomb.com/playstation-3/3045-35/', u'id': 35, u'name': u'PlayStation 3'}, {u'api_detail_url': u'http://www.giantbomb.com/api/platform/3045-20/', u'abbreviation': u'X360', u'site_detail_url': u'http://www.giantbomb.com/xbox-360/3045-20/', u'id': 20, u'name': u'Xbox 360'}, {u'api_detail_url': u'http://www.giantbomb.com/api/platform/3045-86/', u'abbreviation': u'XBGS', u'site_detail_url': u'http://www.giantbomb.com/xbox-360-games-store/3045-86/', u'id': 86, u'name': u'Xbox 360 Games Store'}]
How would I go about getting all the 'name' keys out of there?


The solution was simple:
for elem in list:
print elem['name']


To get the list of all names, you can use a list comprehension:
>>> L = [{u'api_detail_url': u'http://www.giantbomb.com/api/platform/3045-94/', u'abbreviation': u'PC', u'site_detail_url': u'http://www.giantbomb.com/pc/3045-94/', u'id': 94, u'name': u'PC'}, {u'api_detail_url': u'http://www.giantbomb.com/api/platform/3045-35/', u'abbreviation': u'PS3', u'site_detail_url': u'http://www.giantbomb.com/playstation-3/3045-35/', u'id': 35, u'name': u'PlayStation 3'}, {u'api_detail_url': u'http://www.giantbomb.com/api/platform/3045-20/', u'abbreviation': u'X360', u'site_detail_url': u'http://www.giantbomb.com/xbox-360/3045-20/', u'id': 20, u'name': u'Xbox 360'}, {u'api_detail_url': u'http://www.giantbomb.com/api/platform/3045-86/', u'abbreviation': u'XBGS', u'site_detail_url': u'http://www.giantbomb.com/xbox-360-games-store/3045-86/', u'id': 86, u'name': u'Xbox 360 Games Store'}]
>>> [D['name'] for D in L]
['PC', 'PlayStation 3', 'Xbox 360', 'Xbox 360 Games Store']
If name is not in every dictionary, you can filter the dictionaries:
>>> [D['name'] for D in L if 'name' in D]
['PC', 'PlayStation 3', 'Xbox 360', 'Xbox 360 Games Store']

Related

How to combine all arguments in two lists if the first element of each list is the same

setting = Subject.objects.annotate(A_setup=Count('id', filter=Q(type='A'), distinct=True) * Value(50),
B_setup=Count('id', filter=Q(type='B'), distinct=True) * Value(30),
C_setup=Count('id', filter=(~Q(type='A') & ~Q(type='B') & ~Q(type__isnull=True) & Q(id__in=workers.filter(worker=1).values('id')))) * Value(10)) \
.values('setting__user_id', 'A_setup', 'B_setup', 'C_setup')
setting = [{'setting__user_id': 4, 'A_setting': 50.0, 'B_setting': 120, 'C_setting': 10.0}, {'setting__user_id': 34, 'A_setting': 0.0, 'B_setting': 0, 'C_setting': 0.0}, {'setting__user_id': 33, 'A_setting': 0.0, 'B_setting': 150, 'C_setting': 0.0}, {'setting__user_id': 30, 'A_setting': 0.0, 'B_setting': 150, 'C_setting': 0.0}, {'setting__user_id': 74, 'A_setting': 50.0, 'B_setting': 120, 'C_setting': 10.0}]
uploader = Feedback.objects .values('uploader_id').distinct().values_list('uploader_id')
uploader = [{'uploader_id': 25}, {'uploader_id': 20}, {'uploader_id': 74}, {'uploader_id': 34}, {'uploader_id': 93}, {'uploader_id': 88}, {'uploader_id': 73}, {'uploader_id': 89}, {'uploader_id': 30}, {'uploader_id': 33}, {'uploader_id': 85}, {'uploader_id': 4}, {'uploader_id': 46}]
"setting" outputs only users who satisfy the conditions. But I need a list of all users. The "uploader" is a queryset containing all users. First, the entire list of users is printed, and if the user's id is included in the "setting", the setting value is output. The final result I want to achieve is as follows.
Desired Result: [['25', '0', '0', '0'], ['20', '0', '0', '0'], ['74', '50', '120', '10'], ['34', '0', '0', '0'], ['93', '0', '0', '0'], ['88', '0', '0', '0'], ['73', '0', '0', '0'], ['89', '0', '0', '0'], ['30', '0', '150', '0'], ['33', '0', '150', '0'], ['35', '0', '0', '0'], ['4', '50', '120', '10'], ['46', '0', '0', '0']]
sorry. Please check again. There are two querysets. I want to get the A_setup, B_setup, C_setup values ​​of setting if uploader id and uploader id of setting are the same after unfolding the uploader queryset, and adding 0 if there is no uploader id in setting.
How do I get the results I want?

In my opinion, it is better to change the data structure a little bit (into setting_new and uploader_ids below), and then use list comprehension:
from operator import itemgetter
# setting = [{'setting__user_id': 4, 'A_setting': 50.0, 'B_setting': 120, 'C_setting': 10.0}, ...
# uploader = [{'uploader_id': 25}, {'uploader_id': 20}, {'uploader_id': 74}, ...
setting_new = {dct['setting__user_id']: itemgetter('A_setting', 'B_setting', 'C_setting')(dct) for dct in setting}
uploader_ids = map(itemgetter('uploader_id'), uploader)
output = [[i, *setting_new.get(i, (0,0,0))] for i in uploader_ids]
print(output)
# [[25, 0, 0, 0], [20, 0, 0, 0], [74, 50.0, 120, 10.0], [34, 0.0, 0, 0.0], ...

How to convert orderdict into json in python?

How to convert below orderedict into regular json ? in python?
[OrderedDict([('ins_short_name', 'MI'), ('beneficiary', []),
('benefit', 65), ('pcp', []), ('benefit_rates', 216),
('added_dependent', []), ('removed_dependent', []), ('ins_name',
'Medical Insurance'), ('plan', {'carrier_logo':
'How to create a DateTime equal to 15 minutes ago?',
'plan_type': 'HMO', 'creation_time': '2019-02-11T06:21:21.743369Z',
'plan_info_details': '', 'rx_coverage': '11', 'id': 65, 'co_pay':
'11', 'contribution_interval': None, 'updation_time':
'2019-02-11T06:21:21.743808Z', 'benefit_display_name': 'Mi1 HMO',
'carrier': 1, 'status': False, 'carrier_name': 'NHP',
'rx_information': None, 'voluntary': False, 'deductible': '11`',
'hsa_qualified_wrap_plan': False, 'benefit': 65,
'terms_and_conditions': None, 'maximum_contribution': None,
'hsa_qualified_base_plan': False, 'primary_care_physician': False,
'plan_info': ''}), ('dependent', []), ('questions',
[OrderedDict([('question', 1), ('question_type', 'radio'),
('identifier', 'Q1'), ('ref', [Decimal('1.00')])]),
OrderedDict([('question', 4), ('question_type', 'plan'),
('identifier', 'Q4'), ('ref', [Decimal('216.00')])])])]),
OrderedDict([('ins_short_name', 'AI'), ('beneficiary',
[OrderedDict([('id', 365), ('first_name', 'rer'), ('last_name',
'ere'), ('relation', 'Spouse'), ('other_relation', None), ('_type',
'Primary'), ('percentage', '100'), ('benefit', 66), ('enrollment',
357), ('creation_time', '2019-02-14T12:04:00.676078Z'),
('updation_time', '2019-02-14T12:04:33.475164Z')])]), ('benefit', 66),
('pcp', []), ('benefit_rates', None), ('added_dependent', []),
('removed_dependent', []), ('ins_name', 'Ancillary Insurance'),
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'How to create a DateTime equal to 15 minutes ago?',
'plan_type': 'Other', 'creation_time': '2019-02-11T06:24:32.322178Z',
'plan_info_details': '', 'rx_coverage': '', 'id': 66, 'co_pay': '',
'contribution_interval': None, 'updation_time':
'2019-02-11T06:24:32.322541Z', 'benefit_display_name': 'Ai name',
'carrier': 1, 'status': False, 'carrier_name': 'NHP',
'rx_information': None, 'voluntary': True, 'deductible': '',
'hsa_qualified_wrap_plan': False, 'benefit': 66,
'terms_and_conditions': None, 'maximum_contribution': None,
'hsa_qualified_base_plan': False, 'primary_care_physician': False,
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('identifier', 'Q12'), ('ref', [Decimal('10.00')])])])])]

python one liner for creating dictionary from list

I am learning dictionary comprehension, and wrote the following code.
The output of the list 'lines' looks like this:
[['Color', 'Blue', 'Model', 'Ford'], ['Color', 'Green', 'Model', 'Honder'], ['Color', 'Pink', 'Model', 'peugeot']]
'
#!/Library/Frameworks/Python.framework/Versions/2.7/bin/python
import pprint
d={}
FILE='File.txt'
with open(FILE, 'r') as Data:
lines = [line.split() for line in Data ]
#print lines
for x in lines:
d[x[0]] = x[1]
d[x[2]] = x[3]
pprint.pprint(d)
Basically i am trying to figure out how i can convert the above for loop into a single line.
So far i tried the below code:
e = {x[0]:x[1] for x in lines}
But that would only give me the very last entry of the list.

Here's a clean solution using the third form of the dict constructor:
>>> from itertools import izip
>>> l=[['Color', 'Blue', 'Model', 'Ford'], ['Color', 'Green', 'Model', 'Honder'], ['Color', 'Pink', 'Model', 'peugeot']]
>>> [dict(izip(d[::2], d[1::2])) for d in l]
[{'Color': 'Blue', 'Model': 'Ford'}, {'Color': 'Green', 'Model': 'Honder'}, {'Color': 'Pink', 'Model': 'peugeot'}]
>>>

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doc={
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'pdpData.ageGroup': 'Adults-Women',
'pdpData.articleAttributes.Body Shape ID': 'Shape ID 424,Shape ID 333,Shape ID 324,Shape ID 443',
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'pdpData.articleAttributes.Fabric': 'Polyester',
'pdpData.articleAttributes.Fabric 2': 'NA',
'pdpData.articleAttributes.Fabric 3': 'NA',
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'pdpData.articleAttributes.Length': 'Long',
'pdpData.articleAttributes.Occasion': 'Casual',
'pdpData.articleAttributes.Pattern': 'Printed',
'pdpData.articleAttributes.Print / Pattern Type': 'Others',
'pdpData.articleAttributes.Surface Styling / Features': 'NA',
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'pdpData.articleAttributes.Waist Rise': 'Mid',
'pdpData.articleNumber': 'P700418XL-Red-1193441',
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'pdpData.articleType.isJewellery': False,
'pdpData.articleType.isLarge': False,
'pdpData.articleType.isReturnable': True,
'pdpData.articleType.isTryAndBuyEnabled': True,
'pdpData.articleType.pickupEnabled': True,
'pdpData.articleType.socialSharingEnabled': True,
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'pdpData.codEnabled': 'Y',
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'pdpData.colour2': 'NA',
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'pdpData.crossLinks': [
{
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{
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'pdpData.discountData.discountRuleHistoryId': 1548747L,
'pdpData.discountData.discountRuleId': 912089L,
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'pdpData.discountData.discountText.text': '(50% OFF)',
'pdpData.discountData.discountToolTipText.hasFreeItem': False,
'pdpData.discountData.discountToolTipText.text': 'Buy this item and get <em>50% </em> off',
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'pdpData.discountData.fundingPercentage': 60L,
'pdpData.discountData.icon': 'Flat_Cart_Icon',
'pdpData.discountData.id': 'Flat_Cart_P',
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'pdpData.masterCategory.isJewellery': False,
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'pdpData.masterCategory.isReturnable': True,
'pdpData.masterCategory.isTryAndBuyEnabled': True,
'pdpData.masterCategory.pickupEnabled': True,
'pdpData.masterCategory.socialSharingEnabled': True,
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'pdpData.navigationId': 0L,
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'pdpData.productDescriptors.style_note.descriptorType': 'style_note',
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'pdpData.styleImages.back.imageType': 'back',
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'pdpData.styleImages.default.resolutionFormula': 'h_($height),q_($qualityPercentage),w_($width)/v1/assets/images/1193441/2016/1/27/11453879129257-Trend-Arrest-Women-Trousers-8751453879128667-1.jpg',
'pdpData.styleImages.default.resolutions.1080X1440': 'http://assets.myntassets.com/h_1440,q_95,w_1080/v1/assets/images/1193441/2016/1/27/11453879129257-Trend-Arrest-Women-Trousers-8751453879128667-1.jpg',
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{
'active': True,
'allSize': '28',
'available': True,
'id': 9677369,
'inventoryCount': 27,
'name': 'Size',
'skuAvailabilityDetailMap': {
'21': {
'availableCount': 27,
'availableInWarehouses': '28',
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'sellerid': 21,
'sellername': 'Health & Happiness Pvt Ltd',
'storeid': 1,
'supplyType': 'ON_HAND',
},
},
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'taxEntry': {'skuId': 9677369, 'taxRate': 5.25},
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'unifiedSizeValue': '28',
'value': 'S',
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},
{
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'available': True,
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'name': 'Size',
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'21': {
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'sellerid': 21,
'sellername': 'Health & Happiness Pvt Ltd',
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'supplyType': 'JUST_IN_TIME',
},
},
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'value': 'M',
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},
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},
},
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'unifiedSizeValue': '32',
'value': 'L',
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},
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'allSize': '34',
'available': True,
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'21': {
'availableCount': 1,
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'leadTime': 0,
'sellerid': 21,
'sellername': 'Health & Happiness Pvt Ltd',
'storeid': 1,
'supplyType': 'ON_HAND',
},
},
'skuId': 9677378,
'taxEntry': {'skuId': 9677378, 'taxRate': 5.25},
'unifiedSize': '34',
'unifiedSizeValue': '34',
'value': 'XL',
'warehouseIdToItemCountMap': {},
},
],
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'pdpData.subCategory.filterOrder': 0L,
'pdpData.subCategory.id': 29L,
'pdpData.subCategory.isExchangeable': True,
'pdpData.subCategory.isFragile': False,
'pdpData.subCategory.isHazmat': False,
'pdpData.subCategory.isJewellery': False,
'pdpData.subCategory.isLarge': False,
'pdpData.subCategory.isReturnable': True,
'pdpData.subCategory.isTryAndBuyEnabled': True,
'pdpData.subCategory.pickupEnabled': True,
'pdpData.subCategory.socialSharingEnabled': True,
'pdpData.subCategory.typeCode': '',
'pdpData.subCategory.typeName': 'Bottomwear',
'pdpData.usage': 'Casual',
'pdpData.variantName': 'Printed Palazzo Pants',
'pdpData.vat': 5.5,
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'pdpData.weight': '0',
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the code which I am trying
res = es.index(index = INDEX_NAME, doc_type=TYPE_NAME, id=i, body = doc)
error is as shown below
raise HTTP_EXCEPTIONS.get(status_code, TransportError)(status_code, error_message, additional_info)
elasticsearch.exceptions.RequestError: TransportError(400, u'mapper_parsing_exception', u'failed to parse')

How to add target line in google column chart?

How to add the target line in google column chart like this.

If you'd like to combine the columnchart and linechart, use ComboChart. Documentation and examples are here :
https://developers.google.com/chart/interactive/docs/gallery/combochart
basically, have the data point for the line chart as one of the columns in the DataTable and specify this column to be the "series" = "line", whereas the other columns are visualized in a ColumnChart.

You can use a Stepped Area series to achieve this. It's a little awkward but works well.
var data = google.visualization.arrayToDataTable([
['Month', 'Bolivia', 'Ecuador', 'Madagascar', 'Papua New Guinea', 'Rwanda', ''],
['2004/05', 165, 938, 522, 998, 450, 250],
['2005/06', 135, 1120, 599, 1268, 288, 250],
['2006/07', 157, 1167, 587, 807, 397, 250],
['2007/08', 139, 1110, 615, 968, 215, 250],
['2008/09', 136, 691, 629, 1026, 366, 250]
]);
var options = {
seriesType: "line",
series: {5: {
type: "steppedArea",
color: '#FF0000',
visibleInLegend: false,
areaOpacity: 0}
}
};
var chart = new google.visualization.LineChart(document.getElementById('chart_div'));
chart.draw(data, options);
Example
Stepped Area Google Chart Example

To avoid the ugly outline, just use: enableInteractivity: false

To make the steppedArea #Ryan suggested above a litte bit less awkward, you can setup a second (right) axis and set the base line to the value you want for the target line. The second axis will be setup for the seppedArea data. This avoids the uggly outline effect when you hover the pointer over the chart and under the line. Do something like this in the options:
var options = {
seriesType: "line",
series: {5: {
type: "steppedArea",
color: '#FF0000',
visibleInLegend: false,
areaOpacity: 0,
targetAxisIndex: 1 } //tell the series values to be shown in axe 1 bellow
},
vAxes: [ //each object in this array refers to one axe setup
{}, //axe 0 without any special configurations
{
ticks: [250], //use this if you want to show the target value
baseline: 250 //this shifts the base line to 250
}
]
};