I have a tons of files and I want to convert them to other format using command prompt.
After exporting each of converted files program needs to name it.
I have a txt-documnet, that contains a list of future file-names.
So, I really need to name exported files one by one using first string name, then second string name, then third and so on.
EXAMPLE I have files to import in the directory
00001.umg
00002.umg
00003.umg
00004.umg
00005.umg
00006.umg
00007.umg
(and so on)
I have a txt document looking like this
Great name.brt
Wonderful.brt
Most beautiful.brt
Beautiful File.brt
Random File.brt
Define.brt
Excellent file.brt
...
(and so on)
So, after convertion I need to have exported files named like string in txt document in proper direction. First file must take first TXT string name, second - second string.....
Thank you!
Related
I'm trying to process a file in a Kettle transformation. The targeted file has a static name, let's say TARGETED.LOG and it's in a subdirectory which contains a date component (variable) in his name. So, the whole path name will be something like:
c:\username\kettleworkspace\report_[DDMMYYYY]\TARGETED.LOG.
Any advice?
Use the Get File Names step with the include subfolders option, and drop the resulting list of files in your Text File Input with the Accept filenames from previous step option.
Of course between these two step you would probably want to add some Filter step.
I trying to merge a large data set in gams. The file should consist of multiple gdx files with several names. The programme merges the files as I would like them to however: it replaces the names of the file to be merged with File_1, File_2, File_3 and so on. I would like to see the name of the gdx file in the merged file (and so far the script I wrote worked fine).
I'm receiving the following error for each line:
***Filename cannot be used as a valid UEL
Existing name: ImpactYesPGTNoLDViolation-D1-PG10-LDI-LDE0.001-LB0.0045-PDC0-D10
Replaced with File_1
Why does this happen? Could it be that the existing name is too long? I tried finding out more about this error but so far have not found any information on it. And is there anyway to fix it? I need the information of the existing name in order to further process the output.
You are right. This name is too long to be used as UEL (aka label). You can only use up to 63 characters. You can read more about this and other limitations for UELs here
I want to extract dates from the suffixes of files in a particular folder. The contents of such a folder look something like:
Packed_Folder_1_2016.06.10
Packed_Folder_1_2016.08.06
Packed_Folder_1_2015.09.03
packed_Folder_1_2015.01.08
... (so on and so forth, always in the same path just different suffixes)
There is no pattern to the dates. I need to make a VS form (2013) to read the name of the files and store the date differences.
Notice how the filenames always follow a pattern? It's always Packed_Folder_1_####.##.##, where the last part is a date.
So what you want to do is list the file names in the folder, and try to find a file that matches the pattern. You could use a regular expression to match the filename (it would be something like R"(Packed_Folder_1_\d{4}\.\d{2}\.\d{2})").
You are talking about Forms, so I am assuming you are able to use Visual C++. If that is the case, you can check FileSystemWatcher Class.
You instantiated it with a given path ( file or directory ), and it will trigger events based on some changes on the target (simple change, creation, rename - you can select which one). You could then update your reference, in case its change suits your needs.
How could I possible open a symbolic link and get the content of the file instead of the file it is pointing to?
By doing:
with open('/home/symlink.txt', 'rb') as f:
data=f.read()
If the symbolic link points to /foo/faa.txt, the variable data will contain the content of faa.txt. This is a big security and file problem from my server because I'm generating zip archives.
If for example, a folder contains multiple symbolic links with different names to avoid duplicating files, the zip archive will contain multiple files instead of multiple symbolic links!
I hope to be clear enough!
An extra explanation:
The point of this is to allow downloading symlinks in a django server. The way of returning files is the following one:
response = HttpResponse()
response.write(data))
return response
This means that data must contain the content that the user will download. I can not just give it a path. So what I need to do is to give it a symbolic link. The problem is that reading a symbolic link makes python read the content where it is pointing to instead of its real content. In a few words, the user downloads the real file instead of the symbolic link!
A possible solution to this would be to get the path where the symlink points to, and then generate the link in the buffer. Is this possible?
It looks like there are 2 questions here: How can you read a symlink from the filesystem, and how can you store this in a .zip file such that it will be recreated when you unzip it.
Reading a symlink
The contents of a symlink are defined here:
http://man7.org/linux/man-pages/man7/symlink.7.html
A symbolic link is a special type of file whose contents are a string that is the pathname of another file, the file to which the link refers
You can read that path by using os.readlink (https://docs.python.org/2/library/os.html#os.readlink) - this is analogous to C's readlink function.
It's also important to note that these symlinks aren't distinguished by their content or file attributes, but by the fact that the file entry on disk points to a string rather than a file object:
In other words, a symbolic link is a pointer to another name, and not to an underlying object.
This means that there isn't really a "file" you could store in the ZIP. So how do the existing zip & unzip utilities do it?
Storing a symlink in a zip file
The spec for the ZIP format is here: https://pkware.cachefly.net/webdocs/casestudies/APPNOTE.TXT
Note that section 4.5.7 (defining UNIX Extra Field) says:
The variable length data field will contain file type specific data. Currently the only values allowed are the original "linked to" file names for hard or symbolic links, and the major and minor device node numbers for character and block device nodes. [...] Link files will have the name of the original file stored.
This means that to store a symlink, all you need to do is add the UNIX extra field block to the data you are writing (these appear to live immediately after the filename is written, and you need to set the extra field length accordingly), and populate its "Variable length data field" with the path you get from readlink. The content you store for the node will be empty.
If you're using a library to generate the zip data (recommended!), it will probably have an abstraction available for that. If not, I'd suggest you put in a feature request!
Of course, most existing zip and unzip utilities follow the same definition, which is why you are able to zip and unzip symbolic links as if they were regular files.
I have source and target in an informatica powercenter developer. I heed some other header name to be imported in the target file automatically without any manual entry. How can I import customized headers to informatica target.
What have you tried?
You can use a header command in the session configuration for the target, I haven't used it, and couldn't find any documentation on it (i.e. what is possible and how, whether parameters can be used or not, etc.). I did test using (on Windows) an ECHO command to output its text to the header row, but it didn't seem to recognize parameters.
Or you can try to include the header as the first data output row. That means your output will have to be all string types and length restrictions may compound the issue.
Or you can try using two mappings, one that truncates the files and writes the header and one which outputs the data specifying append in the session. You may need two target definitions pointing to the same files. I don't know if the second mapping would attempt to load the existing data (i.e. typecheck), in which case it might throw an error if it didn't match.
Other options may be possible, we don't do much with flat files.
The logic is,
In session command, there is an option called user defined headers. Type echo followed by column name separated by comma delimited
echo A, B, C