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I'm a CS Student working on a code to implement but having hard time running it.
Can you please help me out in running this L1 Parsing Table.
May be i'm doing some stupid syntax mistake.
I'll be very thankful to your replies.
Cheers!
#include <iostream.h>
#include <conio.h>
#include <string.h>
#include <stdio.h>
#include <stdlib.h>
void main()
{
clrscr();
int i=0,j=0,k=0,m=0,n=0,o=0,o1=0,var=0,l=0,f=0,c=0,f1=0;
char str[30],str1[40]="E",temp[20],temp1[20],temp2[20],tt[20],t3[20];
strcpy(temp1,'\0');
strcpy(temp2,'\0');
char t[10];
char array[6][5][10] = {
"NT", "<id>","+","*",";",
"E", "Te","Error","Error","Error",
"e", "Error","+Te","Error","\0",
"T", "Vt","Error","Error","Error",
"t", "Error","\0","*Vt","\0",
"V", "<id>","Error","Error","Error"
};
cout << "\n\tLL(1) PARSER TABLE \n";
for(i=0;i<6;i++)
{
for(j=0;j<5;j++)
{
cout.setf(ios::right);
cout.width(10);
cout<<array[i][j];
}
cout<<endl;
}
cout << endl;
cout << "\n\tENTER THE STRING :";
gets(str);
if(str[strlen(str)-1] != ';')
{
cout << "END OF STRING MARKER SHOULD BE ';'";
getch();
exit(1);
}
cout << "\n\tCHECKING VALIDATION OF THE STRING ";
cout <<"\n\t" << str1;
i=0;
while(i<strlen(str))
{
again:
if(str[i] == ' ' && i<strlen(str))
{
cout << "\n\tSPACES IS NOT ALLOWED IN SOURSE STRING ";
getch();
exit(1);
}
temp[k]=str[i];
temp[k+1]='\0';
f1=0;
again1:
if(i>=strlen(str))
{
getch();
exit(1);
}
for(int l=1;l<=4;l++)
{
if(strcmp(temp,array[0][l])==0)
{
f1=1;
m=0,o=0,var=0,o1=0;
strcpy(temp1,'\0');
strcpy(temp2,'\0');
int len=strlen(str1);
while(m<strlen(str1) && m<strlen(str))
{
if(str1[m]==str[m])
{
var=m+1;
temp2[o1]=str1[m];
m++;
o1++;
}
else
{
if((m+1)<strlen(str1))
{
m++;
temp1[o]=str1[m];
o++;
}
else
m++;
}
}
temp2[o1] = '\0';
temp1[o] = '\0';
t[0] = str1[var];
t[1] = '\0';
for(n=1;n<=5;n++)
{
if(strcmp(array[n][0],t)==0)
break;
}
strcpy(str1,temp2);
strcat(str1,array[n][l]);
strcat(str1,temp1);
cout << "\n\t" <<str1;
getch();
if(strcmp(array[n][l],'\0')==0)
{
if(i==(strlen(str)-1))
{
int len=strlen(str1);
str1[len-1]='\0';
cout << "\n\t"<<str1;
cout << "\n\n\tENTERED STRING IS VALID";
getch();
exit(1);
}
strcpy(temp1,'\0');
strcpy(temp2,'\0');
strcpy(t,'\0');
goto again1;
}
if(strcmp(array[n][l],"Error")==0)
{
cout << "\n\tERROR IN YOUR SOURCE STRING";
getch();
exit(1);
}
strcpy(tt,'\0');
strcpy(tt,array[n][l]);
strcpy(t3,'\0');
f=0;
for(c=0;c<strlen(tt);c++)
{
t3[c]=tt[c];
t3[c+1]='\0';
if(strcmp(t3,temp)==0)
{
f=0;
break;
}
else
f=1;
}
if(f==0)
{
strcpy(temp,'\0');
strcpy(temp1,'\0');
strcpy(temp2,'\0');
strcpy(t,'\0');
i++;
k=0;
goto again;
}
else
{
strcpy(temp1,'\0');
strcpy(temp2,'\0');
strcpy(t,'\0');
goto again1;
}
}
}
i++;
k++;
}
if(f1==0)
cout << "\nENTERED STRING IS INVALID";
else
cout << "\n\n\tENTERED STRING IS VALID";
getch();
}
OUTPUT
LL(1) PARSER TABLE
NT <id> + * ;
E Te Error Error Error
e Error +Te Error
T Vt Error Error Error
t Error *Vt
V <id> Error Error Error
ENTER THE STRING :<id>+<id>*<id>;
CHECKING VALIDATION OF THE STRING
E
Te
Vte
<id>te
<id>e
<id>+Te
<id>+Vte
<id>+<id>te
<id>+<id>*Vte
<id>+<id>*<id>te
<id>+<id>*<id>e
<id>+<id>*<id>
ENTERED STRING IS VALID
[/Code]
So, you want a code inspection / code review. Here it goes:
C++ vs. C
Your program looks like it is C, but your question tag says C++. So, I'll view it from the C++ perspective.
Switch your header files to C++:
#include <iostream>
#include <string>
#include <cstdlib>
Note there is no ".h" suffix in the header names.
Console I/O
The conio.h header file is compiler specific. You didn't mention which compiler you are using, so many of us can't load your source and help you.
The clrscr() function is not necessary and often times, clearing the screen erases information that you may need later. BTW, it is not portable because not all platforms have screens.
void main
The main function returns int, always.
Variable Names
The C++ language specification allows for at least 32 characters in an identifier. More characters are allowed but only the first 32 are used to determine duplicates.
So use them. Single letters only reduce your typing time. Descriptive names allow other people, and you, to easily understand how your code is working. Do you know what all of those variable are used for, without reading any other documentation?
Style -- one declaration per line
Declare one variable per line. Easier to maintain, easier to read.
Spaces?
Spaces cost very little build time and don't effect execution speed. They add clarity, use them.
The general rules are one space between variables and operators; one space after a comma.
Character Arrays
Don't use them, the cause problems. Since your question is tagged C++, use std::string instead.
strcpy for one character
Don't use strcpy for one character, just assign it directly:
temp1[0] = '\0';
By the way, strcpy is dangerous, use strncpy instead; notice the letter 'n'.
Const
Use it. Things that don't change should be declared as const to prevent mistakes and allowing the compiler to find this mistakes. Also, character constants (a.k.a. literals) are constant and can't be changed.
Mapping Tables
Three dimensions? Really?
How about something easier to understand, such as a table of structures:
struct Token_Entry
{
const char * token_text;
unsigned int token_ID;
};
const Token_Entry token_table[] =
{
{TOKEN_NT, "NT"},
{TOKEN_ID, "<id>"},
{TOKEN_PLUS, "+"},
// ...
};
const unsigned int Number_Of_Token_Entries =
sizeof(token_table) / sizeof(token_table[0]);
Avoid gets, it's dangerous.
The gets reads input regardless of quantity. If you allocate 5 slots and the User types 10 letters, you will overrun your buffer. Very bad.
Use fgets if you must or switch to C++ and use getline(std::string).
Avoid the exit function
The proper technique is to use return in the main function. This allows proper clean up of variables. The exit function is a little bit more dangerous.
No Gotos and labels
Read up on loops in your favorite, correct, C++ text. Expecially the break and continue keywords.
One assignment per line
Carriage returns, linefeeds and newlines are free, use them. One assignment per line. It slows down the compilation process by either microseconds or nanoseconds; in otherwords, the time required to process line ending characters is negligible.
Use parenthesis
Grouping logical statements with parenthesis may not be necessary if you have memorized the precedence table, but they make the code more readable:
while ((m < strlen(str1)) && (m < strlen(str)))
Compute constants once
For example, the length of the string will not change during your analyzing loops. So store it into a constant variable:
const unsigned int length_str1 = str1.length(); // Since you will be using std::string.
const unsigned int length_str = strlen(str); // Or if you insist on C-style strings.
while ((m < length_str1) && (m < length_str))
Unsigned vs. signed integers
One of my pet peeves. Use int (a.k.a. signed int) if the value can be negative; otherwise use unsigned int. For example, a text length can't be negative. What does a string of length -5 look like?
Comment your code
Tell the reader what you are doing and why. Don't talk about assigning variables. For example, why is k incremented at the end of the loop? Why are you setting temp to null in one section but not the other. What is the f1 variable used for? Set verbosity = maximum.
Use a debugger
Since you didn't comment the code, used single letter variable names, your code will take a lot of time to understand. You can help out by using a debugger. A debugger allows you to execute lines one at a time (a.k.a. single stepping), and print out or display the values in your variables. A lot faster than the ancient art of adding print statements for your variables at different locations in your code.
Also, using a debugger is a faster method to test and evaluate your program than posting it on the web, especially here.
Related
I am new to programming and I want to get an unlimited input of numbers from user, and I need to compare each number to 4 or 7; if the number is 4 or 7, I will increase counter.
The issue is that the if condition if(arr[i]!='4' || arr[i]!='7') is executed even if the number is 4 or 7.
I tried to implement another if by comparing ASCII code >>> if(arr[i]!=0x34 || arr[i]!=0x37) but this solution also doesn't work.
Can you help me to find the issue?
#include <iostream>
#include <string>
#include <string.h>
using namespace std;
int main()
{
int counter=0;
char arr[]={};
cin >> arr;
for (int i=0 ; i<strlen(arr)-1 ; i++)
{
if(arr[i]!='4' || arr[i]!='7')
{
cout << "NO" << endl;
counter=0;
break;
}else
counter++;
}
cout << counter << endl;
if(counter==4 || counter==7)
cout << "YES" << endl;
}
Your program has undefined behavior, because this
char arr[]={};
creates an array of length zero. This is not even allowed in standard C++. If your compiler didn't complain about it, then that is because it is using a non-standard language extension.
In any case, the array has length zero. You then try to write to it with
cin >> arr;
which causes the array to be accessed out-of-bounds, no matter how long the given input is. This will cause undefined behavior and you will not have any guarantee whatsoever on how the program will behave.
Never use char arrays to store strings, especially not user input. Use std::string instead:
std::string arr;
cin >> arr;
Then instead of strlen(arr) you should use arr.size().
I am pretty sure you have further logic errors in your program (see question comments). But before you fix the program logic, you should make sure that you are writing a valid program in the first place.
This is my first time asking something on stackoverflow, so I'm sorry if I fail in any aspect of building the topic etc...
So I'm a newbie at C++, I'm still at the beginning. I'm using a guide someone recommended me, and I'm stuck in a exercise which is about char and strings.
It's the following: They ask me to create a function that says the number of times that a certain word was repeated on a string.
I'll leave my code below for someone who can help me, if possible dont give me an obvious response like the code and then I just copy paste it. If you can just give me some hints on how to do it, I want to try to solve it on my own. Have a good night everyone.
#include <iostream>
#include <string.h>
#define MAX 50
using namespace std;
int times_occ(string s, string k) {
int count = 0, i = 0;
char word[sizeof(s)];
// while (s[i] == k[i])
// {
// i++;
// if (s[i] == '\0')
// {
// break;
// }
// }
for (i = 0; i <= sizeof(s); i++) {
if (s[i] == ' ' || s[i] == '\0') {
break;
}
word[i] = s[i];
}
word[i] = '\0';
for (i = 0; i <= sizeof(k); i++) {
if (word) {
if (k[i] == word[a]) {
a++;
count++;
}
}
}
cout << word << endl;
cout << count << endl; // this was supposed to count the number of times
// certain word was said in a string.
return count;
}
int main() {
char phrase[MAX];
char phrase1[MAX];
cin.getline(phrase, MAX);
cin.getline(phrase, MAX);
times_occ(phrase, phrase1);
}
Okay, first of all, the way you've used sizeof isn't really valid.
sizeof won't tell you the length of a string. For that, you want std::string::size() instead.
In this case, std::string is an object of some class, and sizeof will tell you the size of an object of that class. Every object of that type will yield the same size, regardless of the length of the string.
For example, consider code like this:
std::string foo("123456789");
std::string bar("12345");
std::cout << sizeof(foo) << "\t" << foo.size() << "\n";
std::cout << sizeof(bar) << "\t" << bar.size() << "\n";
When I run this, I get output like this:
8 9
8 5
So on this implementation, sizeof(string) is always 8, but some_string.size() tells us the actual length of the string.
So, that should at least be enough to get you started moving in a useful direction.
As #JerryCoffin mentioned, your word array has an invalid size. But - I want to make a more fundamental point:
Your code has two loops and a bunch of variables with arbitrary names. How should I know what's the difference between s and k? I even get k and i mixed up in the sense of forgetting that k is a string, not an integer. That kind of code difficult to read, and to debug. And we are a bit lazy and don't like debugging other people's code...
I suggest that you:
Have a very clear idea what your loops do, or what the different parts of your function do.
Create small self-contained functions - no more than one loop each please! - for each of those parts.
Use meaningful names for each function's parameters and for the local variables.
And then, if your program doesn't work - try debugging one function at a time.
So I am still new to C++, and I'm trying to make a program that has the user input a string, and then my functions return the string in reverse case, all lower case, and then all uppercase. Instead I just keep receiving the first letter of the string back, always uppercase. Not sure what I am doing wrong. Any suggestions?
#include <iostream>
#include <string>
#include <cstring>
using namespace std;
char answer[255] = "";
int max = strlen(answer);
void reverse() {
for (int i = 0; i < max; i++) {
if (islower(answer[i])) {
isupper(answer[i]);
}
else if (isupper(answer[i])) {
islower(answer[i]);
}
else if (isspace(answer[i])) {
isspace(answer[i]);
}
}
cout << answer[max];
}
void lower() {
for (int i = 0; i < max; i++) {
if (isupper(answer[i])) {
islower(answer[i]);
}
else {
answer[i] = answer[i];
}
}
cout << answer[max];
}
void upper() {
for (int i = 0; i < max; i++) {
if (islower(answer[i])) {
isupper(answer[i]);
}
else {
answer[i] = answer[i];
}
}
cout << answer[max];
}
int main() {
cout << "Please enter a word, or a series of words: " << endl;
cin >> answer[max];
reverse();
lower();
upper();
system("pause");
return 0;
}
islower(char) is just a built in function to check if the char is in lowercase or not. Same goes with isupper. It does not change the case of the character.
In order to convert to lowercase/uppercase, use tolower/toupper. This would return the character in the converted case. But, it is important that you need to assign the returned value to the character itself.
Refer to this answer for some more clarity related to islower, isupper, tolower and toupper.
And now coming to the point why it's printing just the 1st character: As #user4581301 has mentioned in his comment,
"cin >> answer[max]; will read exactly one character because answer[max] is exactly one character, the first character. In C++ you have to do things in order. For example, int max = strlen(answer); will provide an answer based on what is in that string at that time. Since the string was initialized one line earlier and contains an empty string, max will be 0."
Hence your cin should be cin >> answer. BUT, this will accept the 1st word of your sentence. In order to accept all the words including the spaces, use getline() instead. And for using this, answer should be declared as string answer instead of a char array.
This is how you accept a full sentence: getline(cin,answer);
And your variable max will give an error in a few compilers as being ambiguous. This is because of the using namespace std;. to avoid this, rename max to something else, like maxlen.
And finding the length of answer: It would be better if you call answer.length() after accepting the string from user rather than doing it globally.
Your working code should look something like this:
#include <iostream>
#include <string>
#include <cstring>
using namespace std;
string answer;
int maxlen;
void reverse() {
for (int i = 0; i < maxlen; i++) {
if (islower(answer[i])) {
answer[i] = toupper(answer[i]);
}
else if (isupper(answer[i])) {
answer[i] = tolower(answer[i]);
}
else if (isspace(answer[i])) {
answer[i]=' ';
}
}
cout << "Reversed string: " + answer << endl;
}
void lower() {
for (int i = 0; i < maxlen; i++) {
if (isupper(answer[i])) {
answer[i] = tolower(answer[i]);
}
else {
answer[i] = answer[i];
}
}
cout << "Lower case string: " + answer << endl;
}
void upper() {
for (int i = 0; i < maxlen; i++) {
if (islower(answer[i])) {
answer[i] = toupper(answer[i]);
}
else {
answer[i] = answer[i];
}
}
cout << "Upper case string: " + answer << endl;
}
int main() {
cout << "Please enter a word, or a series of words: " << endl;
getline(cin,answer);
cout << "Original string: " + answer << endl;
maxlen = answer.length();
reverse();
lower();
upper();
return 0;
}
With the output:
Please enter a word, or a series of words:
ReVeRsAl UPPER aNd lower
Original string: ReVeRsAl UPPER aNd lower
Reversed string: rEvErSaL upper AnD LOWER
Lower case string: reversal upper and lower
Upper case string: REVERSAL UPPER AND LOWER
cin >> answer[max];
will read exactly one character because answer[max] is exactly one character, the character in the array at position max.
max is 0 because you have to do things in order. For example,
int max = strlen(answer);
will provide the length of answer at that time this line is reached. Since the string was initialized one line earlier
char answer[255] = "";
and contains an empty string, max will be 0. This means answer[max] is answer[0] Nothing in the code ever changes max, so it will remain 0.
OK, say we change things a little and rather than reading into a single character, we read into answer as a string. You will need to
cin.getline(answer, sizeof(answer));
because
cin >> answer;
will read one whitespace-delimited token. One word. Your stated goal is to read more than one word. istream::getline will read everything it finds into the first parameter up to the end of the line or it finds the number of characters specified in the second parameter minus 1 (in order to reserve space for the string's null terminator). sizeof(answer) is literally the size of the answer array in bytes. We're operating in byte-sized characters so the count of characters and number of bytes are the same. Extra care must be taken if multibyte characters are being used.
This seems like a good place to recommend using std::string and std::getline instead. They make a large number of problems, such as the maximum number of characters that can be read, vanish for the vast majority of cases.
I'm not going to use them here, though because the assignment likely has a "No strings" policy.
So now that we have cin.getline(answer, sizeof(answer)); reading the user's input we can work on getting the size for max. We could strlen, but we could also use istream::gcount to get the number of characters read by getline.
main now looks something like
int main() {
cout << "Please enter a word, or a series of words: " << endl;
cin.getline(answer, sizeof(answer));
max = cin.gcount();
reverse();
lower();
upper();
system("pause");
return 0;
}
Whole bunch of stuff can go wrong at this point.
using namespace std; can wreak havoc on the max because of possible collisions with std::max. In general, avoid using namespace std; The few letters it saves you from typing often are recovered by the time wasted debugging the weird errors it can introduce.
isupper(answer[i]); doesn't do anything useful as others have noted in the comments. You want
answer[i] = toupper(static_cast<unsigned char>(answer[i]));
See Do I need to cast to unsigned char before calling toupper(), tolower(), et al.? for why that insane-and-pointless-looking cast may be necessary. Thank you HolyBlackCat for bringing that to my attention.
Self assignments like
answer[i] = answer[i];
are pointless for reasons that should be obvious once you stop and think about it.
Likewise
else if (isspace(answer[i])) {
isspace(answer[i]);
}
May not be particularly useful. If answer[i] is a space, set it to a space? It's already a space. What it would do is replace other forms of whitespace, tabs and carriage returns, with a space. Newline has already been picked off by getline. Also probably needs a cast similar to the one used in the toupper example above. I'm still reading up on that.
As hinted at above,
cout << answer[max];
is not effective. It prints out one character, and if max has been fixed, answer[max] will be the terminating null. Instead print out the whole array.
cout << answer;
General suggestions:
Don't write much code at a time. Write a few lines, a function at the most, before compiling and testing. If you had tested
int main() {
cout << "Please enter a word, or a series of words: " << endl;
cin >> answer[max];
cout << answer;
}
You would have immediately seen data was not being read correctly. and fixed it before proceeding. By allowing errors to build up, you make it harder to find any one bug. You may correctly fix a bug only to find the fix undone or concealed by another bug.
Avoid using global variables. Try to place variables in the smallest possible scope. In this case, move answer and max into main and pass them to the other functions as parameters. This makes it a lot easier to keep track of who set what variable and when. It also helps prevent accidental Variable Shadowing.
this is my first SO post.
I am very new to programming, and with C++ I thought I might try and make a program that allows the user to submits a block of text (max 500 characters), allows them to enter a 4 letter word and the program return with the amount of times it picks that word up in the text.
I am using X-code and it keeps making a green breakpoint and pausing the program at the 'for' loop function. my code is shown below:
#include <iostream>
#include <string>
#include <math.h>
#define SPACE ' '(char)
using namespace std;
//Submit text (maximum 500 characters) and store in variable
string text;
string textQuery(string msgText) {
do {
cout << msgText << endl;
getline(cin, text); } while (text.size() > 500);
return text;
}
//Query word to search for and store as variable
string word;
string wordQuery(string msgWord) {
cout << msgWord << endl;
cin >> word;
return word;
}
//Using loop, run through the text to identify the word
int counter = 0;
bool debugCheck = false;
int searchWord() {
for (int i = 0; i < text.size(); i++) {
char ch_1 = text.at(i);
char ch_2 = text.at(i + 1);
char ch_3 = text.at(i + 2);
char ch_4 = text.at(i + 3);
cout << i;
if(ch_1 == word.at(0) &&
ch_2 == word.at(1) &&
ch_3 == word.at(2) &&
ch_4 == word.at(3) )
{
counter++;
debugCheck = true;
}
}
return counter;
}
//cout the result
int main() {
string textUserSubmit = textQuery("Please submit text (max 500 characters): ");
string wordUserSubmit = wordQuery("Please select a word to search for: ");
int counterResponse = searchWord();
cout << debugCheck << endl;
cout << "The number of times is: " << counterResponse << endl;
return 0;
}
I get the error at the for loop. Any other advice about how i can make my program work for different words, multiple lengths of words and also how i can highlight the words in text would be helpful.
I really would appreciate if someone could aid me with my problem. Thanks!
I get the error at the for loop.
You should describe the error you get. I happen to have access to Xcode so I can run your code and see what happens, but you should try to spare that of people from whom you want help.
In this case you should describe how the debugger stops the program at the line:
char ch_4 = text.at(i + 3);
includes the message: "Thread 1: signal SIGABRT" and the console output shows
libc++abi.dylib: terminating with uncaught exception of type std::out_of_range: basic_string
Your problem is this: the for loop checks to make sure that i is in the correct range for the string text before using it as an index, but then you also use i+1, i+2, and i+3 as indices without checking that those values are also valid.
Fix that check and the program appears to run fine (given correct input).
Some miscellaneous comments.
Use more consistent indentation. It makes the program easier to read and follow. Here's how I would indent it (using the tool clang-format).
#define SPACE ' '(char) looks like a bad idea, even if you're not using it.
using namespace std; is usually frowned on, though as long as you don't put it in headers it usually won't cause too much trouble. I still could though, and because you probably won't understand the resulting error message you may want to avoid it anyway. If you really don't like writing std:: everywhere then use more limited applications such as using std::string; and using std::cout;.
global variables should be avoided, and you can do so here by simply passing textUserSubmit and wordUserSubmit to searchWord().
there's really no need to make sure text is less than or equal to 500 characters in length. You're using std::string, so it can hold much longer input.
You never check how long word is even though your code requires it to be at least 4 characters long. Fortunately you're using at() to index into it so you don't get undefined behavior, but you should still check. I'd remove the check in textQuery and add one to wordQuery.
The first line contains an integer n (1 ≤ n ≤ 100). Each of the following n lines contains one word. All the words consist of lowercase Latin letters and possess the lengths of from 1 to 100 characters.
(Source: http://codeforces.com/problemset/problem/71/A)
How would you get input from the user given n? I tried using a while loop but it doesn't work:
#include <iostream>
using namespace std;
int main()
{
int n;
cin>>n;
int i;
while (i<=n) {
cin>>i ;
i++;
}
}
You probably meant to have something like:
#include <iostream>
int main() {
int n;
cin>>n;
int theInputNumbers[n];
for(int i = 0; i<n; ++i) {
cin >> theInputNumbers[i];
}
}
Your loop is really quite far off of what you need. What you wrote is extremely wrong such that I cannot provide advice other than to learn the basics of loops, variables, and input. The assistance you need is beyond the scope of a simple question/answer, you should consider buying a book and working through it cover to cover. Consider reading Programming Principles and Practice Using C++
Here is a working example of something approximating your question's requirements. I leave file input and output as an exercise up to you. I also make use of C++11's front and back std::string members. You would have to access via array index in older versions.
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
int main(){
int totalWords;
cin >> totalWords;
stringstream finalOutput;
for (int i = 0; i < totalWords; ++i){
string word;
cin >> word;
if (word.length() > 10){
finalOutput << word.front() << (word.length() - 2) << word.back();
}else{
finalOutput << word;
}
finalOutput << endl;
}
cout << endl << "_____________" << endl << "Output:" << endl;
cout << finalOutput.str() << endl;
}
With that said, let me give you some advice:
Name your variables meaningfully. "int i" in a for loop like I have above is a common idiom, the "i" stands for index. But typically you want to avoid using i for anything else. Instead of n, call it totalWords or something similar.
Also, ensure all variables are initialized before accessing them. When you first enter your while loop i has no defined value. This means it could contain anything, and, indeed, your program could do anything as it is undefined behavior.
And as an aside: Why are you reading into an integer i in your example? Why are you then incrementing it? What is the purpose of that? If you read in input from the user, they could type 0, then you increment by 1 setting it to 1... The next iteration maybe they'll type -1 and you'll increment it by 1 and set it to 0... Then they could type in 10001451 and you increment by 1 and set it to 10001452... Do you see the problem with the logic here?
It seems like you are trying to use i as a counter for the total number of iterations. If you are doing this, do not also read input into i from the user. That completely undermines the purpose. Use a separate variable as in my example.