Class keyword followed by two words ?! cpp [closed] - c++

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I encountered this code:
NAMESPACE_NCO_BEGIN
class NCO_VIEWS_DECLSPEC MyView:
public CWnd
{
};
NAMESPACE_NCO_END
What does the NCO_VIEWS_DECLSPEC mean?
MyView is class name.
If possible try to explain NAMESPACE_NCO_BEGIN and NAMESPACE_NCO_END.

All three are macros. Somewhere in the code, possibly in some included header file, there must be #defines for them. NCO_VIEWS_DECLSPEC most certainly translates to some compiler-specific class attribute, e.g. __declspec( dllexport) for Microsoft Visual C++. Look here for a detailed example: Using dllimport and dllexport in C++ Classes

Related

namespace std has no member any_of [closed]

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I'm trying to see if string contains number. As I was searching on this site, i saw implementation by saying std::any_of(password.begin(), password.end(), ::isdigit) and it is supposed to return boolean value, true or false.
However, visual studio keeps saying thath namespace std has no memeber any_of.
std::any_of resides in the <algorithm> header which you need to include:
#include <algorithm>
Reference

What is the use function in c++? [closed]

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I'm currently reading a c++ book and one of the function is
void fp(char v[]){
for(char* p = v; *p!=0;p++) use(*p);
}
I wrote this into my editor and compiled it. I also included the headers
#include <iostream>
#include <string.h>
But my terminal returns the following message:
use of undeclared identifier 'use'
I also google it and its nowhere to be found online, the function doesn't exist.
That's because there is no such standard library function.
The author is either using pseudo-code here, or has defined this function somewhere else in the book.

Base class and templates [closed]

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Can I write code like this (tried it and doesn't compile in VS2015):
template<class BaseClassT>
class DerivedClass : public BaseClassT
{
...
};
and then use it like:
class BaseClass
{
};
DeriveClass<BaseClass> c;
if not possible, is there a way to implement the same idea?
Yes, you may use a template argument as base, and it compiles in MSVS if you fix the typo.
(Note that this is not the CRTP, despite what you may have heard.)

Can't call a static function [closed]

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I declare in a header traductionCSV.h the function
static QVector<struct variableDurSupervision>
listVariableDurSupervison(std::string fichierCSV);
I write it in my cpp, then I want to use it in another file supervision.cpp, so I call it like this :
remplirDurCellule(
traductionCSV::listVariableDurSupervison(
"../../FichierCSV/ListeVariableSupervision.csv"
)
);
But it won't work, I got this error :
undefined reference to traductionCSV::listVariableDurSupervison(std::string)
I properly include all the file, so I don't understand.
Thank you.
You are probably missing the class name when you are defining it in cpp. It should be like :
QVector<struct variableDurSupervision> traductionCSV::listVariableDurSupervison(std::string fichierCSV)
{
...
}
This rule applies both to static and non-static functions of a class.

C-style static array as a member of a template class - won't compile [closed]

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I was practising using C++ templates (sounds way better than "playing around") by coding something that would basically be my own implementation of std::array when I stumbled across an odd compilation failure. I reduced the problem into the following class, which fails to compile on gcc version 4.9.0:
template <typename TestType>
class TestClass
{
TestType[10] data;
};
What am I doing wrong here?
The array part of the type should go after the identifier:
TestType data[10];