This is my models.py:
def get_profileImage_file_path(instance, filename):
return os.path.join('%s/uploadedPhotos/profileImages' % instance.user_id, filename)
class UserExtended(models.Model):
user = models.OneToOneField(User)
profileImage = models.ImageField(upload_to=get_profileImage_file_path, default='/static/images/myProfileIcon.png')
Now, I want the default image (which is in my static folder) to save to the path given in the
get_profileImage_file_path
function. In my settings.py, I have defined media_root and media_URL as:
MEDIA_ROOT = '/home/username/Documents/aSa/userPhotos'
MEDIA_URL = '/media/'
For some reason, when I pass the user object in the template and in the template, if I do:
<img class='profilePic' src="{{ user.userextended.profileImage.url }}" height='120px' alt="" />
No image shows up and when I open up the 'inspect element' section in chrome, it gives a 404 error saying:
GET http://127.0.0.1:8000/home/username/Documents/djcode/aS/aSa/static/images/myProfileIcon.png 404 (NOT FOUND)
even though that is the correct file path to the image. (I'm also not sure why it's giving the entire file path, isn't it just supposed to start from /static/? Even when I 'view source', the entire url is there.) How do I make it so that the default image which is located in the static folder uploads to the path provided in the
get_profileImage_file_path
function?
In general we use the config as follows for media :
BASE_DIR = dirname(dirname(abspath(__file__)))
MEDIA_ROOT_DIR = 'media'
MEDIA_ROOT = normpath(join(BASE_DIR, MEDIA_ROOT_DIR))
MEDIA_URL = '/media/'
For, development purposes set :
DEBUG = True
And in urls.py add the following :
from django.conf import settings
from django.conf.urls.static import static
if settings.DEBUG:
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
urlpatterns += static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)
Upload the image again and validate the Image, it should work now.
Related
We have a django project in which we are storing images in the backend using image field.The image link is being stored on django admin site.However ,when I click on the link ,I get an error page.Here's my code.
models.py
images=models.ImageField(upload_to=upload_to,null=True)
def upload_to(instance, filename):
return 'images/{filename}'.format(filename=filename)
urls.py
urlpatterns = [
path('admin/', admin.site.urls),
path('app/',include('firstapp.urls')),
path('',include('firstapp.api.urls')),
]+ static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
settings.py
MEDIA_ROOT = os.path.join(os.path.dirname(BASE_DIR), 'media')
# URL used to access the media
MEDIA_URL = '/media/'
I have created a folder named media but the images are not being stored there.Please help.
You can try this way:
MEDIA_ROOT=os.path.join(BASE_DIR,'media') #Just add like this
Do pass directly to field instead of creating function of uploat_to.
images=models.ImageField(upload_to="images/",null=True)
Do above things and see if it solves.
Do reply if it is not solved.
From Python Doc. os.path.dirname(...)
Return the directory name of pathname path. This is the first element
of the pair returned by passing path to the function split().
os.path.join() takes first argument as full path becouse of this your MEDIA_ROOT is giving wrong path.
If you're using Django>=3.0 version then you can use pathlib like this
MEDIA_ROOT = BASE_DIR / 'media'
MEDIA_URL = '/media/'
I'm trying to use Django 2.0. I'm using the development 'runserver' right now, so please keep in mind that I'm not in production yet. I am familiar with the differences between the two with regard to static files.
I have a Blog Post model. In the admin, I want to be able to add an image to my model using ImageField. I'd like it to be optional, and provide a default image if none is added.
I am able to load images in admin. I am unable to render my image in my template. The console shows that Django is trying to GET my image, but my configurations have not worked so far.
Here's my model and relevant field:
from PIL import Image
class Post(models.Model):
....
thumbnail = models.ImageField(default='/img/default.png', upload_to='img', blank=True, null=True)
....
My model works well aside from the ImageField. My View works well, and I don't think there is any issue there.
Here is my urls.py
....
from django.conf.urls.static import static
from django.conf import settings
from django.contrib.staticfiles.urls import staticfiles_urlpatterns
from . import views
urlpatterns = [
....
path('posts/', views.PostListView.as_view(), name='post_list'),
path('post/<int:pk>/', views.PostDetailView.as_view(), name='post_detail'),
path('post/random/', views.random_post, name='random_post'),
]
urlpatterns += staticfiles_urlpatterns()
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
I'm not at all sure about how to handle static files vs. media files in my urls.py, especially with changes to Django in version 2.0.
Here's my relevant settings.
BASE_DIR = os.path.dirname(os.path.dirname(os.path.abspath(__file__)))
STATIC_URL = '/static/'
TEMPLATES = [
{
...
'OPTIONS': {
'context_processors': [
....
'django.contrib.messages.context_processors.media',
....
]
},
},
]
MEDIA_ROOT = os.path.join(BASE_DIR, 'media').replace('\\', '/')
MEDIA_URL = '/media/'
I am equally unsure of what to put in my settings.py concerning media. My static CSS files are working just fine. I have a logo image in my static files that is rendering in my base template.
Here is my template tag for the ImageField:
<img class="card-image mr-3" src="{{ post.thumbnail.url }}" alt="Generic placeholder image">
Lastly, my /static folder and my /media folder are in the same directory. These are both in my app directory, /blog.
Can anyone see any blaring errors here, or can they make suggestions? My issue is the default image is not loading. The default image IS in the correct directory /media/img/. The console warning says "Not Found: /media/img/default.png".
Thanks in advance. Any suggestions will be helpful.
Django ImageField for Admin Panel
There is important thing you have to define your MEDIA_URL in urls.py.
Without this definition framework doesn't gives to you permission to access image
Setting.py
MEDIA_URL = '/uploads/'
MEDIA_ROOT = os.path.join(BASE_DIR, 'uploads')
urls.py
if settings.DEBUG: # new
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
Models.py
class Product(models.Model):
title = models.CharField(max_length=150)
image=models.ImageField(blank=True,upload_to='images/')
def __str__(self):
return self.title
def image_tag(self):
return mark_safe('<img src="{}" height="50"/>'.format(self.image.url))
image_tag.short_description = 'Image'
Admin.py
class ProductAdmin(admin.ModelAdmin):
list_display = ['title','image_tag']
readonly_fields = ('image_tag',)
Printing the media root helped me solve this issue. Thanks Alasdair.
I don't think there was any issue with my model field above.
The urls.py code that I ended up using is directly from Django docs for Django 2.0 in handling static files https://docs.djangoproject.com/en/2.0/howto/static-files/.
The changes I made to Settings were done thanks to printing my MEDIA_ROOT in the console. I changed the syntax and the direction of a slash (blog\media). I also deleted the context processor shown above in my TEMPLATES options.
Here's what works for me:
models.py
thumbnail = models.ImageField(default='img/default.png', upload_to='img', blank=True, null=True)
urls.py
from django.conf.urls.static import static
from django.conf import settings
urlpatterns = [...] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
settings.py
MEDIA_ROOT = os.path.join(BASE_DIR, 'blog\media')
MEDIA_URL = '/media/'
print(MEDIA_ROOT)
Template tag
<img class="card-image mr-3" src="{{ post.thumbnail.url }}" alt="Generic placeholder image">
I am running on a local server and when I go to http://127.0.0.1:8000/media/ in my browser it says page not found.
Settings:
MEDIA_ROOT = os.path.join(BASE_DIR, 'media')
MEDIA_URL = '/media/'
STATIC_URL = '/static/'
Root URL:
from django.conf.urls import url, include
from django.contrib import admin
from django.conf import settings
from django.conf.urls.static import static
urlpatterns = [
url(r'^polls/', include('mysite.polls.urls')),
url(r'^admin/', admin.site.urls),
url(r'^submit/', include('mysite.uploads.urls')),
] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
Model for User Upload:
from django.db import models
class Document(models.Model):
description = models.CharField(max_length=255, blank=True)
document = models.FileField(upload_to='documents/')
uploaded_at = models.DateTimeField(auto_now_add=True)
Following the Django documentation:
Serving files uploaded by a user during development
During development, you can serve user-uploaded media files from MEDIA_ROOT using the django.contrib.staticfiles.views.serve() view.
This is not suitable for production use! For some common deployment strategies, see Deploying static files.
For example, if your MEDIA_URL is defined as /media/, you can do this by adding the following snippet to your urls.py:
from django.conf import settings
from django.conf.urls.static import static
urlpatterns = [
# ... the rest of your URLconf goes here ...
] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
https://docs.djangoproject.com/en/1.10/howto/static-files/
As pointed above in the comments by Alasdair, This is the normal behaviour of Django. If you visit the full file path like 127.0.0.1/media/file.jpg, Django will render the file instead of raising a 404 error.
Why is this happening?
If you look at the source of the view that serves the media/static files, you'll find these lines:
if os.path.isdir(fullpath):
if show_indexes:
return directory_index(newpath, fullpath)
raise Http404(_("Directory indexes are not allowed here."))
What it does is, it checks if the path requested is a directory or not. If yes, then it checks if the variable show_indexes is True, then it will return the index of the files inside the media directory. Since, show_indexes is False by default, it raises 404.
To set show_indexes to True, you can do this:
urlpatterns = [
# ... the rest of your URLconf goes here ...
] + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT, show_indexes=True)
This won't raise the 404 and will display a list of files inside media dir.
P.S.: I don't think displaying file indices is a good idea, unless, of course, that's something you really want. It puts server under extra load to generate the indices. And someone can download the files recursively using a program like wget etc. Even those files that are meant to be private.
image not found but the image exist at exact location .
print(profile.image.url)
#/media/app/images/my_image.png
prints the image location but when i used in my template , other column are
current but image is not found
profile = same_table.object.get(pk = 1)
setting:
MEDIA_URL = '/media/'
MEDIA_ROOT = os.path.join(MY_BASE_DIR , 'media')
my media location has no problem because when i upload image to server
it is working fine
Template:
<img src = "{{profile.image.url}}">
any idea what i messed ?
Using Django 1.10 with Python 3.4 in window 10
Add to end of your root urls config urls.py this:
from django.conf.urls.static import static
from django.conf import settings
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
I have problems showing images in my Django templates (I'm uploading the images from the admin application). I read the documentation and other posts about the upload_to and still couldn't figure it out. I tried this <img src="{{ a.image}}"/> in my template and then this <img src="{{MEDIA_URL}}{{ a.image}}"/> and same results. Here is my settings.py code :
MEDIA_ROOT = '/home/mohamed/code/eclipse workspace/skempi0/media'
MEDIA_URL = '/media/'
and finally, I tried the following in my models.py and I failed miserably:
image = models.ImageField(upload_to = "ads/")
image = models.ImageField(upload_to = ".")
and when I used image = models.ImageField(upload_to = MEDIA_URL) I got the following error
SuspiciousOperation at /admin/advertisments/banner/add/
Attempted access to '/media/cut.jpg' denied.
EDIT
Generated links are as follows :
<img src="./DSCN6671.JPG">
RE-EDIT
Here is my view:
def index(request):
spotlightAlbum = Album.objects.filter(spotlight = True)
spotlightSong = Song.objects.filter(spotlight = True).order_by('numberOfPlays')
homepage = Song.objects.filter(homepage = True).order_by('numberOfPlays')
ads = Banner.objects.all()
copyright = CopyrightPage.objects.get()
try:
user = User.objects.get(userSlug = "mohamed-turki")
playlists = UserPlaylist.objects.filter(owner = user.userFacebookId)
purchase = Purchase.objects.filter(userName = user.userFacebookId)
user.loginState = 1
user.save()
except:
user = None
playlists = None
context = {'copyright':copyright, 'ads':ads, 'spotlightSong':spotlightSong,'spotlightAlbum': spotlightAlbum, 'homepage':homepage, 'user':user, 'playlists':playlists, 'purchase':purchase }
return render_to_response('index.html',context,context_instance = RequestContext(request))
Could anybody tell me what am I doing wrong??
P.S I'm using Django 1.4
The path you provide in upload_to will be a relative path from the MEDIA_ROOT you set in your project's settings file (typically settings.py).
Your MEDIA_ROOT is where your uploaded media will be stored on disk while the MEDIA_URL is the URL from which Django will serve them.
So if your MEDIA_ROOT is /home/mohamed/code/eclipse workspace/skempi0/media and your model's image attribute is:
image = models.ImageField(upload_to = "ads/")
Then the final home on disk of your uploaded image will be /home/mohamed/code/eclipse workspace/skempi0/media/ads/whatever-you-named-your-file.ext and the URL it will be served from is /media/ads/whatever-you-named-your-file.ext
Setting your upload path to be settings.MEDIA_URL won't work because that's where the media is served FROM not where it is allowed to be stored on disk.
If you want to load your uploaded image in your templates just do this (replace whatever with the name of the variable sent from the view to the template that represents this object):
<img src="{{ whatever.image.url }}"/>
The image attribute on your model isn't actually an image, it's a Python class that represents an image. One of the methods on that ImageField class is .url() which constructs the path to the URL of the image taking into account how you set your MEDIA_URL in your project's settings. So the snippet above will generate HTML like this:
<img src="/media/ads/whatever-you-named-your-file.ext"/>
RequestContext() and settings.TEMPLATE_CONTEXT_PROCESSORS
Since the render_to_response() you are returning from your view is utilizing RequestContext() you need to make sure you have settings.TEMPLATE_CONTEXT_PROCESSORS set correctly. Check out the 1.4 docs for further clarification.
upload_to needs to be an absolute path to the directory, not the web url. So try this:
image = models.ImageField(upload_to = settings.MEDIA_ROOT)
in your templates, just use
<img src="{{ a.image.url }}">
First, I suggest to change the MEDIA_ROOT to be
MEDIA_ROOT = os.path.join(PROJECT_ROOT,'media')
this way you ensure the media directory path is right under your project root. Your MEDIA_URL is set up correctly, but it is not used when uploading a file. MEDIA_ROOT is.
Regarding the file upload, in your model set the field to be
image_field = models.ImageField('Image', upload_to='images/some_sub_folder')
Note that I didn't use neither a leading nor trailing forward slashes. The above will upload the image to PROJECT_ROOT/media/images/some_sub_folder/ with the filename and extension of the original file. Alternatively, you can alter the filename by using a callable - upload_to=filename_convetion - more info here.
In your template, you can access the image using
<img src="/media/{{ your_model.image_field }}" />
Hope this helps, cheers.
I know this question is old but I had the same problem and this solved in my case:
settings.py
import os
BASE_DIR = os.path.dirname(os.path.dirname(__file__))
PROJECT_DIR = os.path.dirname(__file__)
MEDIA_ROOT = os.path.join(PROJECT_DIR, "media")
MEDIA_URL = '/media/'
urls.py
Then, my urls.py was missing this line of code to discover the /media/ folder and show the content:
urlpatterns += staticfiles_urlpatterns()
urlpatterns = patterns('',
url(r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT}, name="media_url"),
) + urlpatterns
Hope it can help someone.