Copy Dynamic Struct Array into another C++ - c++

Question

I'm not that good in English, that's why my Question is probably wrong. But I have a problem and I don't know how to solve it or if it's even possible to do.
I have 2 Structs defined:
typedef struct
{
UINT16 ScriptNumber;
std::string ScriptText;
} StepStruct;
typedef struct
{
std::string SequenceName;
std::string DisplayName;
StepStruct SequenceSteps;
} SequenceStruct;
As you can see, the first Struct is a Member of the second struct. So I want both structs to by dynamical. So I created 2 Dynamic Arrays from the Type StepStruct and 1 dynamic Array from the Type SequenceStruct.
The two dynamical Arrays for of the Type StepStructs are defined as follows:
StepStruct gsFirstSkript[] =
{
{ 1 , "SkriptText One"},
{ 2 , "SkriptText Two"},
{ 45, "SkriptText Three"}
}
StepStruct gsSecondSkript[] =
{
{ 48, "SkriptText One"},
{ 2 , "SkriptText Two"},
{ 45, "SkriptText Three"}
}
Those to Structs are of the Type StepStruct. Now I want to do the Same with a SequenceStruct Type, but I want to assign the two Arrays I already have to it under the Struct Member SequenceSteps. I mean this as follows:
SequenceStruct gsSequenceList[] =
{
{ "FirstScript", "Test One", gsFirstSkript},
{ "SecondScript", "Test Two", gsSecondSkript}
}
If I now want to Read the Member gsSequenceList, I can not access any information under the SequenceSteps Index of it! What means, that the Data is not copied! I tried it with Pointers
but had no success.
UINT16 lTestVal = gsSequenceList[0].SequenceSteps[2].ScriptNumber;
So Can I mangage that this works, and lTestVal contains the Value 45?

Answer 1

typedef struct
{
std::string SequenceName;
std::string DisplayName;
StepStruct* SequenceSteps;
} SequenceStruct;
This will allow the code to compile and the test fragment you've shown will work.
However this will not copy the data. If you change gsFristSkript it will change in gsSequenceList as well. If you want to make a copy of the data you can either do that explicitly, have a constructor or just use vector<>.
Here's the solution with vector:
#include <vector>
...
typedef struct{
std::string SequenceName;
std::string DisplayName;
vector<StepStruct> SequenceSteps;
} SequenceStruct;
vector<StepStruct> gsFirstSkript =
{
{ 1 , "SkriptText One"},
{ 2 , "SkriptText Two"},
{ 45, "SkriptText Three"}
}
vector<StepStruct> gsSecondSkript =
{
{ 48, "SkriptText One"},
{ 2 , "SkriptText Two"},
{ 45, "SkriptText Three"}
}
SequenceStruct gsSequenceList[] =
{
{ "FirstScript", "Test One", gsFirstSkript},
{ "SecondScript", "Test Two", gsSecondSkript}
}