I am new to regular expressions.
I have many irregularly numbered ascii files with no extension: g000554, g000556, g000558, g000561, g000563 ... g001979 etc
I would like to type a regex at the terminal (or in a short script) to add a .dat to all of these files.
So I would like to change them to become: g000554.dat, g000556.dat, g000558.dat, g000561.dat, g000563.dat ... g001979.dat etc
p.s. Sorry I should have provided more info: by terminal I meant a mac terminal and I cannot use the 'rename' command.
I think you're using a linux system. So i provide a bash solution. It works only if your files starts with g and there is no other files in that directory except the files you want to rename.
for i in g*; do mv "$i" "$i.dat"; done
The below would add .dat extension to all the files present in the current directory,
for i in *; do mv "$i" "$i.dat"; done
Related
I have a list of files that a date has been added to the end.
ex: Chorus Left Octave (consolidated) (2020_10_14 20_27_18 UTC). The files will end with .wav or .mp3
I want to leave the (consolidated) but take out the date. I have come up with the regex and tested with regexr.com. It does format the text correctly there.
The regex is: /(\([0-9]+(.*)(?=.wav|.mp3))+/g
Now, I am trying to actually rename the files. In my terminal I have cd'ed into the folder with the files. Based on other answers here I have tried:
rename -n '/(\([0-9]+(.*)(?=.wav|.mp3))+/g' *.wav|*.mp3 - using rename installed with homebrew
sed '/(\([0-9]+(.*))+/g' *.wav|*.mp3
for f in *.wav|*.mp3; do mv "$f" "${f/(\([0-9]+(.*)(?=.wav|.mp3))+/g}” done
The first two do not throw any errors, but do not do any renames (I know that the -n after rename just prints out the files that will be changed, it doesn't actually change the files)
The last one starts a bash session.
I'd rather use the rename or sed, seems simpler to me. But, what am I doing wrong?.
In plain bash:
#!/bin/bash
pat='([0-9][0-9][0-9][0-9]_[0-9][0-9]_[0-9][0-9] [0-9][0-9]_[0-9][0-9]_[0-9][0-9] UTC)'
for f in *.mp3 *.wav; do echo mv "$f" "${f/$pat}"; done
Remove the echo preceding the mv after making sure it will work as intended. You may also consider adding the -i option to the mv in order to avoid clobbering an existing file unintentionally.
I am working with a bunch of txt files(thousands) on my project. Each txt file has 'csv' information on it. The problem is that each txt file has a random name and I cannot create a code for loading them in my project due to it. So, I want to rename them in a particular pattern to make easier the loading of the files in my work. I will use C++ for accomplish this task.
I put all the txt files in a folder but I cannot see a way of renaming them using C++. How can I do this? is there a way to do it? Can someone help me?
You can use std::filesystem::directory_iterator and std::filesystem::rename (c++17), as documented here.
Disclaimer
This answer validity is based on a comment where the author precised they were not bound to the C++ language (it may be worth editing the question, the C++ tag, and the OS). This solution may work for UNIX systems supporting bash, that is most Linux distributions and all releases of Apple's macOS prior to macOS Catalina (correct me if I'm wrong).
Bash command line
Using the following bash command should rename all the files in a folder with increasing numbers, that is:
toto.csv -> 1.csv
titi.csv -> 2.csv etc
It assumes the ordering is not important.
a=1; for i in *; do mv -n "$i" "$a.csv" ; let "a +=1"; done
To test it, you can prepare a test folder by opening a terminal and typing:
mkdir test
cd test
touch toto.csv titi.csv tata.csv
ls
Output:
tata.csv titi.csv toto.csv
Then you can run the following command:
a=1; for i in *; do mv -n "$i" "$a.csv" ; let "a +=1"; done
ls
Output:
1.csv 2.csv 3.csv
Explication:
a=1 declare a variable
for i in *; begin to iterate over all files in the folder
do mv will move (rename) a file of the list (that is, the variable $i) to a new name called a.csv
and we increment the counter a, and close the loop.
the option -n will make sure no file gets overwritten by the command mv
I assumed there was no specific criterion to rename the files. If there is a specific structure (pattern) in the renaming, the bash command can probably accommodate it, but the question should then give more details about these requirements :)
I have a file containing various paths such as:
/home/user/Desktop/Bash/file1.txt
/home/user/Desktop/Bash/file2.txt
/home/user/Desktop/Bash/file3.txt
/home/user/Desktop/Bash/moreFiles/anotherFile.txt
/home/user/Desktop/text/prettyFile.txt
And I receive a input from user that contains the directory, such as:
/home/user/Desktop/Bash/
And I usually save this expression into regex to find all the files in the directory by grep. However, if the folder has more folders, it includes them as well, but I want to only include the files in the directory that was entered by the user. My desired output is should be this:
/home/user/Desktop/Bash/file1.txt
/home/user/Desktop/Bash/file2.txt
/home/user/Desktop/Bash/file3.txt
But it keeps including
/home/user/Desktop/Bash/moreFiles/anotherFile.txt
which I don't want and I need to do it inside a bash script.
You can use this grep command to get just the files directly under given path skipping sub-directories:
s='/home/user/Desktop/Bash/'
grep -E "$s[^/]+/?$" file
/home/user/Desktop/Bash/file1.txt
/home/user/Desktop/Bash/file2.txt
/home/user/Desktop/Bash/file3.txt
How can I rename many files. Remove the digits at the beginning.
I have a Mac. All the files are in the same folder.
The pattern is:
1, 2 or 3 digits - any name.php
With Regular Expression, I think it would be:
\d*-(.*).php
For example:
1-marketing.php
2-3D.php
3-without.php
I want to remove the numbers and the dash at the beginning.
In the example it would be:
marketing.php
3D.php
without.php
What I have explored two ways:
Select the files > ctrl click > rename items. This is a fantastic method to change the name of files. But I think it cannot be used in this case. If I understand, it does not support Regex. Am I right?
Terminal. I am not very familiar with terminal. I tried mv 1-marketing.php marketing.php It works for 1 file, but how can I do the same for many? I am new with the terminal. If it can be done, please explain the basic.
Open the terminal app in Mac OS X and navigate to the folder containing the .php files
cd /my/path/to-php-files/
and run the below command on the command-line.
for file in *.php; do mv -v "$file" "${file#*-}"; done
The bash parameter expansion syntax ${file#*-} removes the characters before - from the beginning, so ideally 3-number-without.php becomes number-without.php
(or) use the perl rename utility not available by default in Mac OS, you can download and install it with homebrew 🍺:
brew install rename
and do
rename -n 's/^(\d+)-(.*)/$2/' *.php
The -n is just for a dry-run to see how the files are to be renamed, remove it as
rename 's/^(\d+)-(.*)/$2/' *.php
for the actual renaming.
I am trying to take a text file that contains a list of files and copy them all to a directory. Within this directory, they will have unique directory names. An example of text file the structure can be seen below:
/data/isip/data/tuh_eeg/v0.6.0/edf/001/00000003/s01_2011_11_01/a_.edf
/data/isip/data/tuh_eeg/v0.6.0/edf/001/00000003/s01_2011_11_01/a_1.edf
/data/isip/data/tuh_eeg/v0.6.0/edf/001/00000003/s02_2011_11_11/a_.edf
/data/isip/data/tuh_eeg/v0.6.0/edf/001/00000003/s02_2011_11_11/a_1.edf
/data/isip/data/tuh_eeg/v0.6.0/edf/001/00000005/s01_2009_02_13/a_.edf
/data/isip/data/tuh_eeg/v0.6.0/edf/001/00000005/s02_2010_10_02/a_.edf
/data/isip/data/tuh_eeg/v0.6.0/edf/001/00000005/s03_2010_10_02/a_.edf
/data/isip/data/tuh_eeg/v0.6.0/edf/001/00000005/s04_2010_10_03/a_.edf
/data/isip/data/tuh_eeg/v0.6.0/edf/001/00000005/s04_2010_10_03/a_1.edf
/data/isip/data/tuh_eeg/v0.6.0/edf/001/00000005/s04_2010_10_03/a_2.edf
/data/isip/data/tuh_eeg/v0.6.0/edf/001/00000005/s04_2010_10_03/a_3.edf
/data/isip/data/tuh_eeg/v0.6.0/edf/001/00000005/s04_2010_10_03/a_4.edf
I need a shell command or an EMACS macro to go through this list and copy them all to unique directories within the current working directory. The unique directory will depend on the file; for example, for the first two files, the directory would be
/001/00000003/s01_2011_11_01/
I have tried doing this using an EMACS macro, but I was not able to get it to work. A shell command or EMACs macro would work.
Something as simple as:
cat list | sed "s/^.*edf\/\(.*\)\/\(.*\)$/mkdir -p root_dir\/\1 \&\& cp \0 root_dir\/\1\/\2/" | sh
If on OSX - install gnu-sed and use gsed instead of sed. Run command without | sh to see what it'll do. Make sure to tweak root_dir, of course.