I can't get the regExp syntax into my head, so if would like to ask a simple question here.
I have emailaddresses
name1 < somename1#domain1.com>, name2 < somename2#domain2.com>
I would like to keep name1, name2 but remove the rest
What expression to use?
Basically I want to use a RegExp for
while (to != '')
{
var indexOne = to.indexOf('<');
var indexTwo = to.indexOf('>');
if ((indexOne > 0) && (indexTwo > indexOne))
{
to = to.substr(0, indexOne - 1) + to.substr(indexTwo, to.length - indexTwo - 1);
}
else break;
}
How about this
var s = "name1 < somename1#domain1.com>, name2 < somename2#domain2.com>, name3 < somename3#domain3.com>";
var p = /\s?<(.*?)>/g
console.log(s.replace(p, '')); // name1, name2, name3
Working jsBin
Related
I need Regex which matches when my string does not start with "MY" and "BY".
I have tried something like:
r = /^my&&^by/
but it doesn't work for me
eg
mycountry = false ; byyou = false ; xyz = true ;
You could test if the string does not start with by or my, case insensitive.
var r = /^(?!by|my)/i;
console.log(r.test('My try'));
console.log(r.test('Banana'));
without !
var r = /^([^bm][^y]|[bm][^y]|[^bm][y])/i;
console.log(r.test('My try'));
console.log(r.test('Banana'));
console.log(r.test('xyz'));
if you are only concerned with only specific text at the start of the string than you can use latest js string method .startsWith
let str = "mylove";
if(str.startsWith('my') || str.startsWith('by')) {
// handle this case
}
Try This(Regex is NOT case sensitive):
var r = /^([^bm][y])/i; //remove 'i' for case sensitive("by" or "my")
console.log('mycountry = '+r.test('mycountry'));
console.log('byyou= '+r.test('byyou'));
console.log('xyz= '+r.test('xyz'));
console.log('Mycountry = '+r.test('Mycountry '));
console.log('Byyou= '+r.test('Byyou'));
console.log('MYcountry = '+r.test('MYcountry '));
console.log('BYyou= '+r.test('BYyou'));
I try to come up with regular expression patter that fulfills such requirements.
it is US phone number format wit 3 groups
I have input strings like this
(999) 98__-9999 here there is extra _ at the end of second section which I want to delete
(999) 9_8_-9999 here there is extra _ at the end of second section I want to delete
(999) 9_-9999 here if second group length is < 3 and ends with _ there should be added _ to pad second group to 9__ (3 characters)
(999) 98-9999 here if second group length is equal to 3 or it ends with digit there shouldn't be any modifications
To sum up:
If secondGroup.length > 3 && secondGroup.lastCharacter == '_' I want to remove this last character
else if secondGroup.length < 3 && secondGroup.lastCharacter == '_' I wan to append "_" (or pad wit underscore to have 3 characters in total)
else leave second group as in the input string.
The same should be applied to first group. The difference are the different delimiters i.e. (xxx) in first group and \sxxx- in second group
Here is my Swift code I have used to achieve it in brute force way by manually manipulating the string: (length 4 instead of 3 takes into account first delimiter like ( or \s. )
var componentText = ""
let idx1 = newText.index(of: "(")
let idx2 = newText.index(of: ")")
if let idx1 = idx1, let idx2 = idx2 {
var component0 = newText[..<idx1]
var component1 = newText[idx1..<idx2]
if component1.count > 4 && component1.last == "_" {
component1.popLast()
} else if component1.count < 4 && component1.last == "_" {
component1.append("_")
}
componentText += "\(component0)\(component1))"
} else {
componentText = newText
}
let idx3 = newText.index(of: " ")
let idx4 = newText.index(of: "-")
if let idx2 = idx2, let idx3 = idx3, let idx4 = idx4 {
var component2 = newText[idx2..<idx3]
component2.popFirst()
var component3 = newText[idx3..<idx4]
var component4 = newText[idx4...]
if component3.count > 4 && component3.last == "_" {
component3.popLast()
} else if component3.count < 4 && component3.last == "_" {
component3.append("_")
}
componentText += "\(component2) \(component3)-\(component4)"
} else {
componentText = newText
}
newText = componentText != "" ? componentText : newText
I think that using regular expression this code could be more flexible and much shorter.
I Have many links like these:
router.use('/foo' , require('./foo'));
router.use('/foo/1' , require('./foo'));
router.use('/foo/2' , require('./foo'));
router.use('/foo/1/1' , require('./foo'));
router.use('/foo/2/3/4/.../n' , require('./foo'));
Is there any way to write a regex that match and separate them by / delimiter? like this:
//for example for /foo/2/3/4/.../n url.
var first_var = req.param[0]; // 2
var last_var = req.param[req.param.length-1]; // n
i already write one for match. not separate:
router.use('/foo/*' , require('./foo'));
As you are trying to do this in regex, this regex will work for you. Let me know, if I've missed some case.
([^\/]+)
const regex = /([^\/]+)/g;
const str = `/foo/2/3/4/5/n`;
let m;
m = str.match(regex);
for(var i = 0; i< 5; i++) {
if(i === 0)
continue;
console.log(`Parameter ${i} = ${m[i]}`);
}
Using JavaScript & regex I want to split a string on every %20 that is not within quotes, example:
Here%20is%20"a%20statement%20"%20for%20Testing%20"%20The%20Values%20"
//easy to read version: Here is "a statement " for Testing " The Values "
______________ ______________
would return
{"Here","is","a statement ","for","Testing"," The Values "}
but it seems my regex are no longer strong enough to build the expression. Thanks for any help!
A way using the replace method, but without using the replacement result. The idea is to use a closure to fill the result variable at each occurence:
var txt = 'Here%20is%20"a%20statement%20"%20for%20Testing%20"%20The%20Values%20"';
var result = Array();
txt.replace(/%20/g, ' ').replace(/"([^"]+)"|\S+/g, function (m,g1) {
result.push( (g1==undefined)? m : g1); });
console.log(result);
Just try with:
var input = 'Here%20is%20"a%20statement%20"%20for%20Testing%20"%20The%20Values%20"',
tmp = input.replace(/%20/g, ' ').split('"'),
output = []
;
for (var i = 0; i < tmp.length; i++) {
var part = tmp[i].trim();
if (!part) continue;
if (i % 2 == 0) {
output = output.concat(part.split(' '));
} else {
output.push(part);
}
}
Output:
["Here", "is", "a statement", "for", "Testing", "The Values"]
I have a django project and I have a method that return the salary for the employee, the salary is being returned as a number like 5432 and i want to display it as five thousand four hundred and thirty two. I tried to use humanize but it works for only small digits any clue??
regards,
Here's some Javascript that you can use, courtesy of About.com's Banking page:
<script type="text/javascript">
// Convert numbers to words
// copyright 25th July 2006, by Stephen Chapman http://javascript.about.com
// permission to use this Javascript on your web page is granted
// provided that all of the code (including this copyright notice) is
// used exactly as shown (you can change the numbering system if you wish)
// American Numbering System
var th = ['','thousand','million', 'billion','trillion'];
// uncomment this line for English Number System
// var th = ['','thousand','million', 'milliard','billion'];
var dg = ['zero','one','two','three','four', 'five','six','seven','eight','nine']; var tn = ['ten','eleven','twelve','thirteen', 'fourteen','fifteen','sixteen', 'seventeen','eighteen','nineteen']; var tw = ['twenty','thirty','forty','fifty', 'sixty','seventy','eighty','ninety']; function toWords(s){s = s.toString(); s = s.replace(/[\, ]/g,''); if (s != String(parseFloat(s))) return 'not a number'; var x = s.indexOf('.'); if (x == -1) x = s.length; if (x > 15) return 'too big'; var n = s.split(''); var str = ''; var sk = 0; for (var i=0; i < x; i++) {if ((x-i)%3==2) {if (n[i] == '1') {str += tn[Number(n[i+1])] + ' '; i++; sk=1;} else if (n[i]!=0) {str += tw[n[i]-2] + ' ';sk=1;}} else if (n[i]!=0) {str += dg[n[i]] +' '; if ((x-i)%3==0) str += 'hundred ';sk=1;} if ((x-i)%3==1) {if (sk) str += th[(x-i-1)/3] + ' ';sk=0;}} if (x != s.length) {var y = s.length; str += 'point '; for (var i=x+1; i<y; i++) str += dg[n[i]] +' ';} return str.replace(/\s+/g,' ');}