Cut it short I have a model called Page and a field called "parent" that links to itself, I want to write if the nav.parent has a parent called home then do this but for some reason it doesn't work.
{% if nav.parent == "home" %}
The problem is of course that Django doesn't know which field to use when comparing, unless you tell it. Since "home" is in the title field, you need to actually specify that field:
{% if nav.parent.title == "home" %}
You can't do this in the template.
You have 2 options as a solution to your problem:
The bad one: pass the variables in the context from the view.
The best: create a custom tag which will receive nav as a parameter and find its parent:
https://docs.djangoproject.com/en/dev/howto/custom-template-tags/
Related
I've built a site where I can create new posts (essays) by the admin panel. The output is visible to users. But when I place some HTML as content in the form it doesn't render itself on the page.
example:
Output on the page (with marked unrendered HTML):
I would like to know how to fix it and also, how to name the topic I want to know ( I couldn't find anything related to my problem, probably because I don't know how to express it).
Additionally, I just start to wonder if there is one more problem nested inside. How to link CSS from the static folder having this HTML mentioned above?
Django offer the autoescape template in the builtins tags
{% autoescape off %}
{{ myhtml }}
{% endautoescape %}
But your logic seems wrong, you don't need to create a new page with the doctype, just create a base template and use the block content tag to insert your article.
In your base template replace the description and title of your page by variables that will be populated by the article data.
You need to learn the basic of Django https://docs.djangoproject.com/en/4.1/ trust me you won't regret it !
So if I want a user's name to link to it's profile, I want the link to contain the user's first name and last name in GET form...Do I just hard-code this into the link, or is there a more elegant way of coding this? Here is hard-coded:
<p>
<li role="presentation" class="active">{{ user.fname }}
</li>
</p>
Yes, the more elegant way would be to set up a route that takes, for example, the user's ID (pk) and use either a DetailView set up for the User model or a function view that accepts the ID and retrieves the relevant user. Passing in the first and last name directly means you need to query on both of them (after pulling them out of the querystring) rather than simply querying on the ID as it's passed to you (after the framework politely checks its type, provided you've set up the route correctly).
So your route would look something like url(r'^profile/(?P<pk>\d+)/$', ProfileView.as_view(), name='profile') and your template tag would look something like {% url 'profile' user.id %}.
I've started using Django and am going right to generic views. Great architecture! Well, the documents are great, but for the absolute beginner it is a bit like unix docs, where they make the most sense when you already know what you're doing. I've looked about and cannot find this specifically, which is, how do you set up an object_list template so that you can click on an entry in the rendered screen and get the object_detail?
The following is working. The reason I'm asking is to see if I am taking a reasonable route or is there some better, more Djangoish way to do this?
I've got a model which has a unicode defined so that I can identify my database entries in a human readable form. I want to click on a link in the object_list generated page to get to the object_detail page. I understand that a good way to do this is to create a system where the url for the detail looks like http://www.example.com/xxx/5/ which would call up the detail page for row 5 in the database. So, I just came up with the following, and my question is am I on the right track?
I made a template page for the list view that contains the following:
<ul>
{% for aninpatient in object_list %}
<li><a href='/inpatient-detail/{{ aninpatient.id }}/'>{{ aninpatient }}</a></li>
{% endfor %}
</ul>
Here, object_list comes from the list_detail.object_list generic view. The for loop steps through the object list object_list. In each line I create an anchor in html that references the desired href, "/inpatient-detail/nn/", where nn is the id field of each of the rows in the database table. The displayed link is the unicode string which is therefore a clickable link. I've set up templates and this works just fine.
So, am I going in the right direction? It looks like it will be straightforward to extend this to be able to put edit and delete links in the template as well.
Is there a generic view that takes advantage of the model to create the detail page? I used ModelForm helper from django.forms to make the form object, which was great for creating the input form (with automatic validation! wow that was cool!), so is there something like that for creating the detail view page?
Steve
If you're on django < 1.3 then what you are doing is basically perfect. Those generic views are quite good for quickly creating pages. If you're on django 1.3 you'll want to use the class based generic views. Once you get a handle on those they are are crazy good.
Only note I have is that you should use {% url %} tags in your templates instead of hardcoding urls. In your urls.conf file(s) define named urls like:
url('inpatient-detail/(?P<inpatient_id>\d+)/$', 'your_view', name='inpatient_detail')
and in your template (for django < 1.3):
...
In 1.3 a new url tag is available that improves life even more.
I want to do the following:
Having a model (p.e. a model which handles data about photographic reports) create a section which has a preview of an specific flickr album. The URL will be provided by an URLField (until the first save the preview will not be available).
After the first save, it'll show previews of all the images inside that album, and make them selectable (through jQuery for example). Then again, when the images are selected and the object is saved (I think I can use django signals for this) it will notify a specific user telling him a selection has been made.
Is there any plugins available, or any easy way to implement this in django-admin?
Update: 22 days and no anwers... does that mean it can't be done in django-admin?
I personally can't think of any easy way to implement this in the Django admin, simply because I doubt many people who've done it have thought to open source it. I can imagine that it would be very specific to a certain user's / programmer's needs.
In any case, if you wanted to solve this issue, I'd say that your best bet would be overriding the Django admin templates in your django/contrib/admin/templates/admin folder. I believe you'd be best off by editing change_form.html.
My basic approach would be this:
Check the name of the model using opts.verbose_name. For example, if you wanted to do this processing for a model whose verbose name is "Gallery", you would do
{% ifequal opts.verbose_name "Gallery" %}
<!-- neat gallery view -->
{% else %}
<!-- regular form -->
{% endifequal %}
Make a custom template tag that will display the gallery view / form given the object_id and the type of object. This way you can replace the <!-- neat gallery view --> with a {% show_gallery object_id %}. See the Django Docs for more info on creating custom template tags. It's pretty straightforward.
Add whatever Javascript or custom stuff in your template tag template. What you choose to do is up to you.
Sorry you haven't gotten many more answers to your question. Hope this helps!
I use django-paginaton app and I'm very glad to use it. Now I need feature, that I don't know how to implement. I have list of elements, that paginated by django's paginator. I have one element with specified id, that I should show, but I don't know what page contains it. I need mechanism jump to the page, that contains my element.
I think it's a good idea if django-pagination will support this transparently and automatically. For example, I set special context variable page_by_id to X and if page is None, it will be defined to the value, that contains my X element.
What do you think about this mechanism?
May be there is another clean way to do this?
This is for continue of this questions:
Django pagination and "current page"
Django Pagination - Redirecting to the page an object is on
At least, I wrote patch for django-pagination that provide 2 features:
Get number of page by id of element inside paginated list;
Possibility to rename default parameter 'page' to another value for
using it inside template;
This works transparently by adding 2
optional parameters in autopaginate templatetag:
{% autopaginate object_list paginated_by orphans page_by_id parameter_name %}