I have this simple line of code using regular expressions where I want to substitute pieces of strings with empty space:
newAddress = myAddress.replace(/^.*?(ramp|arterial|majorroad|street &|highway &|highway|street|street &|street & highway|arterial & street|street & arterial|majorroad &|majorroad & ramp|ramp & majorroad|major road|highway & majorroad)\,/gi, '');
but having in a variable this:
Highway & Contrada Torremuzza, 95121 Catania CT
why it didn't removed the "highway &" part?
It looks to me like you need neither the .* nor the comma. The .* will cause you to replace everything that precedes your string.
Try just this:
(ramp|arterial|majorroad|street &|highway &|highway|street|street &|street & highway|arterial & street|street & arterial|majorroad &|majorroad & ramp|ramp & majorroad|major road|highway & majorroad)
Or, if you're in a mood for fancy optimizations:
(?:majorroad & )?ramp|(?:major r|(?:(?:ramp|highway) & )?majorr)oad|(?:highway|majorroad|street) &|(?:arterial & )?street|(?:street & )?(?:arterial|highway)
Just kidding. In theory this is more efficient, but it's harder to maintain.
It is trying to match a comma as well, you need to make the comma optional or remove it in this case. Also unless you want to remove the preceding text as well remove the beginning of string ^ anchor and .*?
newAddress = myAddress.replace(/(ramp|arterial|majorroad|street &|highway &|highway|street|street &|street & highway|arterial & street|street & arterial|majorroad &|majorroad & ramp|ramp & majorroad|major road|highway & majorroad)/gi, '');
I think I just solved by myself with:
newAddress = myAddress.replace(/^.*?ramp|arterial|majorroad|street|highway| &|\,/gi, '');
shorter and more efficient...so at least it will match the word plus the &
Cheers,
Luigi
Related
I have a string right here :
const text = "12-100 12-199 12-300 12-999 12-666coucou 12-555 1-678 12c-666 plop12-100 12-199 12-300 12-999 12-666"
And 2 regex expressions :
const regex1 = /(?<=coucou).*(?=plop)/g
const regex2 = /\d{1,2}-\d{2,3}/g
I just want to match 12-555 & 1-678 with a single RegExp.
How Can I replace this .* in the first expression please?
Thank you in advance for your answers and explanations!
You can use
const regex = /(?<=coucou.*)\d{1,2}-\d{2,3}(?=.*plop)/g
See the regex demo.
JavaScript demo below:
const text = "12-100 12-199 12-300 12-999 12-666coucou 12-555 1-678 12c-666 plop12-100 12-199 12-300 12-999 12-666"
const regex = /(?<=coucou.*)\d{1,2}-\d{2,3}(?=.*plop)/g
console.log(text.match(regex));
I make a lot of changes on a original csv string. there is a lot of comma delimiter. I have to replace by a ";" either only the commas inside the expression || ....|| or only the commas outside this expression. i need to do this change in order to have different delimiter in the expression ||....|| compare to the rest of the string.
Example:
(.*)(?:\|\|)(?:.*)(,)(?:.*)\|\|
After I use
var regex = /myregex/g;
var str = str.replace(regex, ',')
thanks
You can use
const string = "aba,bjlj,alj,ljlj||name1,name2,name3||jflkj,glfgjlf,jflg,fjlfd||name1,name2||fd,sdfsfd,dfs||name1,name2,name3,name4,name5||";
console.log( string.replace(/\|{2}[\w\W]*?\|{2}/g, (x) => x.replace(/,/g, ';')) );
The regex is
/\|{2}.*?\|{2}/gs // matches any text between two double pipes
/\|{2}[\w\W]*?\|{2}/g // matches any text between two double pipes
/\|{2}.*?\|{2}/g // matches any text but line breaks between two double pipes
Note the . does not match line breaks without the s modifier flag.
The regex matches double pipe, then any zero or more chars, as few as possible up to the next double pipe.
Then, x, the whole match value, is passed as an argument to the anonymous callback function used as a replacement argument, and all commas are replaced with ; only inside the matches.
The "contrary" solution is to match and capture the strings between double pipes and only match commas in all other contexts so that you could keep the captures and replace those commas:
const string = "aba,bjlj,alj,ljlj||name1,name2,name3||jflkj,glfgjlf,jflg,fjlfd||name1,name2||fd,sdfsfd,dfs||name1,name2,name3,name4,name5||";
console.log( string.replace(/(\|{2}[\w\W]*?\|{2})|,/g, (x,y) => y || ';') );
Big Thanks.
I also find
var newStr = str.replace(/\|{2}.*?\|{2}/g, function(match) {
return match.replace(/,/g,";");
});
Do you think is it possible to do the contrary and change all the comma outside the occurence ||...|| ?
I have the following strings
/search?checkin=2018-10-25&checkout=2018-10-27&id=bandung-108001534490276290&page=1&room=1&sort=popularity&type=CITY
/search?checkin=2018-12-09&checkout=2018-12-13&id=singapore-108001534490299035&maxPrice=&minPrice=&room=1&type=REGION
/search?checkin=2018-10-22&checkout=2018-10-23&lat=-6.1176043&long=106.7767146&maxPrice=&minPrice=&room=1&type=COORDINATE
/search?page=1&room=1&type=POI&id=taman-mini-indonesia-indah-110001539700828313&checkin=2018-11-14&checkout=2018-11-16&sort=distance
i want to get all string starts from &id= until the first & so they will return
id=bandung-108001534490276290
id=singapore-108001534490299035
id=taman-mini-indonesia-indah-110001539700828313
When i tried this regex \&id=.*\& it doesn't match my requirement.
Hown do i resolve this?
I'd go with [?&](id=[^&]+).
[?&] - ? or &, because order of GET parameters is usually not guaranteed and you can get the id in the first place – something like /search?id=something-123456&checkin=2018-10-25&…
[^&]+ - at least one character that's not &
() marks a capturing group
Demo in JS:
const strings = [
"/search?checkin=2018-10-25&checkout=2018-10-27&id=bandung-108001534490276290&page=1&room=1&sort=popularity&type=CITY",
"/search?checkin=2018-12-09&checkout=2018-12-13&id=singapore-108001534490299035&maxPrice=&minPrice=&room=1&type=REGION",
"/search?checkin=2018-10-22&checkout=2018-10-23&lat=-6.1176043&long=106.7767146&maxPrice=&minPrice=&room=1&type=COORDINATE",
"/search?page=1&room=1&type=POI&id=taman-mini-indonesia-indah-110001539700828313&checkin=2018-11-14&checkout=2018-11-16&sort=distance]"
]
const regex = /[?&](id=[^&]+)/
strings.forEach(string => {
const match = regex.exec(string)
if (match) {
console.log(match[1])
}
})
Demo and explanation at Regex101: https://regex101.com/r/FBeNDN/1/
Positive Lookahead (?=)
Try a positive lookahead:
/&id=.+?(?=&)|&id=.+?$/gm
This part: (?=&) means: if an & is found, then everything before it is a match.
The alternation:| (it's an OR logic gate) is an update in regards to a comment from Nick concerning that if the parameter ended with an &id=...
It's the same match but instead of looking for a & it will look for the end of the line $. Note that the multi-line flag is used to make $ represent EOL.
Demo
var str = `/search?checkin=2018-10-25&checkout=2018-10-27&id=bandung-108001534490276290&page=1&room=1&sort=popularity&type=CITY
/search?checkin=2018-12-09&checkout=2018-12-13&id=singapore-108001534490299035&maxPrice=&minPrice=&room=1&type=REGION
/search?page=1&room=1&type=POI&id=indo-1999999051158
/search?checkin=2018-10-22&checkout=2018-10-23&lat=-6.1176043&long=106.7767146&maxPrice=&minPrice=&room=1&type=COORDINATE
/search?page=1&room=1&type=POI&id=taman-mini-indonesia-indah-110001539700828313&checkin=2018-11-14&checkout=2018-11-16&sort=distance
/search?page=1&room=1&type=POI&id=indonesia-1100055689`;
var rgx = /&id=.+?(?=&$)|&id=.+?$/gm;
var res = rgx.exec(str);
while (res != null) {
console.log(res[0]);
res = rgx.exec(str);
}
I am stumped on trying to figure out regular expressions so I thought I would ask the big dogs.
I have a string that can range from 1-4 sets as follows:
1234-abcd, baa74739, maps21342, 6789
Now I have figured out the regular expressions for the 1234-abcd, baa74739, and maps21342. However, I am having trouble figuring out a code to pull the numbers that stand alone. Does anyone have an opinion on a way around this?
Example of the regex I used:
dbout.Range("D7").Formula = "=RegexExtract(DH7," & Chr(34) & "([M][A][P][S]\d+)" & Chr(34) & ")"
dbout.Range("D7").AutoFill Destination:=dbout.Range("D7:D2000")
for digit stand alone replace
dbout.Range("D7").Formula = "=RegexExtract(DH7," & Chr(34) & "([M][A][P][S]\d+)" & Chr(34) & ")"
dbout.Range("D7").AutoFill Destination:=dbout.Range("D7:D2000")
with
dbout.Range("D7").Formula = "=RegexExtract(DH7," & Chr(34) & "(\b\d+\b)" & Chr(34) & ")"
dbout.Range("D7").AutoFill Destination:=dbout.Range("D7:D2000")
OR
dbout.Range("D7").Formula = "=RegexExtract(DH7,""(\b\d+\b)"")"
dbout.Range("D7").AutoFill Destination:=dbout.Range("D7:D2000")
I am trying to remove a string from another string using VBA replace function.
The string from which I am trying to remove looks like below which contains cell address concatenated by ;
"$B$1;$B$21;$B$2;$C$3;$B$20;$B$201"
and the string which I would like to remove is $B$2 by say xxx.
The replace function matches all occurrences of $B$2 in the string and gives me the output as below
$B$1;xxx1;xxx;$C$3;xxx0;xxx01
However I would like to search for $B$2 exactly in the string and expect an output like
$B$1;$B$21;xxx;$C$3;$B$20;$B$201
I one way I could think of doing this is by splitting up the string on ;(separator and looping and looking at each value) but I am looking at more direct solution here. Like using pattern matching techniques or something else.
You can include the following ; in the replace operation, to make sure you only match "complete" references. You just need to take a precaution for also matching the last entry, by adding a dummy semicolon at the end:
s = "$B$1;$B$21;$B$2;$C$3;$B$20;$B$201"
find = "$B$2"
repl = "xxxx"
result = Replace(s & ";", find & ";", repl & ";")
result = Left(result, Len(result)-1) ' Remove the final semicolon
Although this works for your case, in a more general exercise, you would also want to test for the preceding delimiter, and then the last two lines would look like this:
result = Replace(";" & s & ";", ";" & find & ";", ";" & repl & ";")
result = Mid(result, 2, Len(result)-2)
you cold use:
Function myReplace(strng As String, findStr As String, replacementStrng As String)
myReplace = Replace(strng & ";", findStr & ";", replacementStrng & ";")
myReplace = Left(myReplace, Len(myReplace) - 1)
End Function
to be exploited in your "main" sub like follows:
strng = "$B$1;$B$21;$B$2;$C$3;$B$20;$B$201"
MsgBox myReplace(strng, "$B$2", "xxx")