C++ - error: 'function' was not declared in this scope - c++

Question

I have the following Problem:
error: 'kleiner' was not declared in this scope
My Professor told me, that my code just works fine for him.
The directories are all included in bulid options (I am using Code::Blocks).
Can someone please tell me what the problem might be?
main.cpp
#include <iostream>
#include "vector.h"
using namespace std;
int main(int argc, char *argv[])
{
Vector v1;
cout << "v1: " << v1 << endl;
Vector v2(8);
cout << "v2: " << v2 << endl;
cout << "Minimum von v2: " << v2.min() << endl;
Vector v3(v2);
cout << "v3: " << v3 << endl;
cout << "Anzahl von v3: " << v3.getAnzahl() << endl;
if ( kleiner( v3[2], v2[5] ) )//<<--<<--<<-- HERE IS THE PROBLEM
cout << v3[2] << " ist kleiner als " << v2[5] << endl;
int arr[5] = { 10, 5, 2, 3, 12 };
Vector v4;
cout << "v4: " << v4 << endl;
v4.setVector( arr, 4 );
cout << "v4 nach set: " << v4 << endl;
cout << "Minimum von v4: " << v4.min() << endl;
cout << "Anzahl von v4: " << v4.getAnzahl() << endl;
return 0;
}
vector.h
#ifndef VECTOR_H
#define VECTOR_H
#include <iostream>
using namespace std;
class Vector
{
int* v;
int anzahl;
public:
Vector(int anzahl = 10);
Vector( const Vector& vec ); // Kopierkonstruktor
~Vector();
friend bool kleiner( const int& a, const int& b );
int min() const;
int getAnzahl() const;
int operator[]( const int i ) const;
void setVector( int* sv, int sanzahl);
friend ostream& operator<< ( ostream& os, const Vector& v );
};
#endif
vector.cpp
#include "vector.h"
Vector::Vector( int a ) : anzahl(a)
{
v = new int[a];
for ( int i = 0; i < a; i++ )
v[i] = i;
}
Vector::Vector( const Vector& vec )
{
anzahl = vec.getAnzahl();
v = new int[anzahl];
for ( int i = 0; i < anzahl; i++ )
v[i] = vec[i];
}
Vector::~Vector()
{
delete[] v;
v = NULL;
}
bool kleiner( const int& a, const int& b )
{
return ( a < b );
}
int Vector::min() const
{
int min = v[0];
for ( int i = 1; i < anzahl; i++ )
{
if ( v[i] < min )
min = v[i];
}
return min;
}
int Vector::getAnzahl() const
{
return anzahl;
}
int Vector::operator[] ( const int i ) const
{
return v[i];
}
void Vector::setVector( int* sv, int sanzahl )
{
delete[] v; // alten Inhalt loeschen
anzahl = sanzahl;
v = new int[anzahl];
for ( int i = 0; i < anzahl; i++ )
v[i] = sv[i];
return;
}
ostream& operator<< ( ostream& os, const Vector& v )
{
for ( int i = 0; i < v.anzahl; i++ )
os << v[i] << ", ";
return os;
}

Answer 1

Declare the function outside of the class as well as specifying as a friend.
Reference; http://en.cppreference.com/w/cpp/language/friend
A name first declared in a friend declaration within class or class template X becomes a member of the innermost enclosing namespace of X, but is not accessible for lookup (except argument-dependent lookup that considers X) unless a matching declaration at the namespace scope is provided - see namespaces for details.
I think you and your Professor have different compilers?

Answer 2

Declare the friend function also outside the class definition in the header. It is not visiable until it will be declared outside the class.