how print an array row with pointers - c++

Question

#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main(){
ifstream fin("C:\\Users\\rati\\Desktop\\iris_flower.txt");
float s=0;
int x,n=5,m=150,i,j;float d[5]={0};
float **iris;
float ss=n;
iris=new float *[n];
for(i=0;i<n;i++)
iris[i]=new float [m];
for(i=0;i<n;i++)
for(j=0;j<m;j++)
fin>> iris[i][j];
for(i=0;i<n;i++){
for(j=0;j<m;j++)
cout<<iris[i][j]<<" ";
cout<<endl;
}
for(j=0;j<m;j++){
for(i=0;i<n;i++)
s+=iris[i][j];
d[j]+=s/ss;
cout<<s<<endl;
}
system ("pause");
}
this is my full code. I want to print a row from 2d array with pointer(no loops).I hope you can write a fragment to add that it did what I want

Answer 1

You can modify the array with pointers but if you want to print the array, you have to use loops.
Check out this example:-
int main() {
int n = 3, m = 4, a[n][m], i, j, (* p)[m] = a;
for (i = 0; i < n; i++)
for (j = 0; j < m; j++)
a[i][j] = 1;
p++;
(*p)[2] = 9;
return 0;}
Here
p is a pointer to a 4-element int arrays (i.e. a pointer to pointer to int, where the first dimension is 4 and the second is unknown). When you increment p, it points to the next 4-element int array, i.e. the fifth int altogether. Then p is dereferenced with offset 2, which means that the seventh int changes, so you get
1 1 1 1
1 1 9 1
1 1 1 1
For converting integer array pointed by p to string, try this :-
string int_array_to_string(int *p, int size_of_array){
string returnstring = "";
for (int temp = 0; temp < size_of_array; temp++)
returnstring += itoa((* p)[temp]);
return returnstring;
}
You get the row array from here.

Answer 2

With array of ints it wont be so easy like array of chars.
int n=10, m=10;
int width, height;
char **tab = new char*[n];
for (int x = 0; x < n; x++) {
tab[x] = new char[m];
}
for(int i=0;i<n;i++)
for(int j=0;j<m;j++)
tab[i][j] = rand()%10 + '0';
for (int i=0; i<n; i++) { for(int j=0; j<n; j++) cout << tab[i][j]; cout << endl; }
cout << endl;
cout << tab[5];
ideone
/// edit ///
if u cant use loop and recursion u can do this
const int n=3;
float *k =new float [n];
k[0]=6.123;
k[1]=9.5345;
k[2]=1.32423;
int i=0;
label:
if(i<n){
cout << *(k+i) << " ";
i++;
goto label;
}