delete in threads gives a segmentation fault - c++

Question

This program counts the occurrence of a word in a line. It runs as expected, but I have 2 concerns:
delete tmp is commented as of now (line 57). If it is uncommented and compiled, my executable gives "segmentation fault". Oddly, it doesn't crash while running in gdb nor with valgrind.
Lines 65 and 66: ideally these threads would need to be joined. But, I am getting correct output even though they are not joined. Is this how it behaves for a shared (volatile) variable?
#include <iostream>
#include <stdio.h>
#include <string.h>
#include <pthread.h>
#include <unistd.h>
#include <fstream>
#include <new>
#define MAX_BUFF 1000
using namespace std;
volatile int tcount=0;
pthread_mutex_t myMux;
typedef struct data
{
string line;
string arg;
}tdata;
void *calcWordCount(void *arg)
{
tdata *tmp = (tdata *)arg;
string line = tmp->line;
string s = tmp->arg;
int startpos = 0;
int finds = 0;
while ((startpos = line.find(s, startpos)) != std::string::npos)
{
++finds;
startpos+=1;
pthread_mutex_lock(&myMux);
tcount++;
pthread_mutex_unlock(&myMux);
}
//cout<<endl<<line<<s<<" "<<finds<<endl;
}
int main(int argc,char *argv[])
{
pthread_t thread_ids[10000];
int cnt=1;
int thread_cnt=0;
void *exit_status;
int targc=argc;
ifstream infile("testfile");
string line;
while(getline(infile,line))
{
while(targc >1)
{
tdata *tmp = new tdata;
tmp->line = line;
tmp->arg = argv[cnt];
pthread_create(&thread_ids[thread_cnt],NULL,calcWordCount,tmp);
thread_cnt++;
cnt++;
targc--;
//delete tmp;
}
cnt=1;
targc=argc;
}
infile.close();
int j;
/*for(j=0;j<thread_cnt;j++)
pthread_join(thread_ids[j],&exit_status);*/
cout<<tcount<<endl;
return 0;
}

Answer 1

You have undefined behaviour as you're calling delete on tmp and another thread is consuming it.
One fix would be to create and pass (by value) a std::shared_ptr rather than the bare pointer into your worker thread. You can use release and reset methods in your main loop. The memory will be released by std::shared_ptr once the worker thread is done with it.