Changing enum values based on HW selection - c++

Question

What is the best way to design a function where the allowed enum value changes based on the HW selected for example. The function might look like this, this won't compile but hopefully you get the idea.
enum class EHWUnit
{
Unit0,
Unit1,
Unit2
};
enum class EHWType
{
Type1,
Type2,
Type3,
Type4
};
SelectHWinput( const EHWUnit aUnit, const EHWType aHWType, const unit8_t aSelect )
{
if( aHWType & 1 == 0)
ArrayIS( 2,4,6,8,10)
else
ArrayIS( 1,3,5,7,9)
element = ArrayIS(aSelect)
WriteToRegister( Address, bits, element);
}
Does anyone know of a way to make it better to select the element based on type? I would prefer to somehow link those even elements to the type at compile time and not select them at run time, using one function is there anyway to make this code more fool proof?

Answer 1

A shot in the dark, as I'm not sure what exactly it is you want to do.
It seems like you want to make some compile-time decisions, which could look something like this:
enum EHWUnit
{
Unit0,
Unit1,
Unit2
};
enum EHWType
{
Type1,
Type2,
Type3,
Type4
};
template <int Select>
struct ArrayIS
{
static constexpr int const array[] = {1, 3, 5, 7, 9};
};
template <int Select>
constexpr int const ArrayIS<Select>::array[];
template <>
struct ArrayIS<0>
{
static constexpr int const array[] = {2, 4, 6, 8, 10};
};
constexpr int const ArrayIS<0>::array[];
template <EHWUnit aUnit, EHWType aHWType, int aSelect>
struct SelectHWinput
{
static constexpr int get()
{
return ArrayIS<static_cast<int>(aHWType) & 1>::array[aSelect];
}
};
int main()
{
// To illustrate that the value is selected at compile-time, a
// static assertion that will always fail:
static_assert(SelectHWinput<Unit0, Type1, 0>::get() < 0, "Works, value selected at compile-time");
}
In the code above, Template Metaprogramming (TMP) is used to select a value of one of the arrays at compile-time. The correct array is chosen by supplying the Select template non-type parameter. Because these arrays are declared constexpr, a constexpr member-function can be used to extract one of its element at compile-time. The static_assert proves that it works.
If you want to construct the arrays more flexibly at compile-time, I suggest looking at this question of mine, where I describe TMP-functors to construct static arrays at compile-time:
g++ (4.7.2) bug or feature, when initializing static arrays at compile-time?
EDIT:
You said you were interested in the Array implementation:
template <typename T, size_t Count, template <typename, T> class Function, T Current, T ... Elements>
struct Array_: public Array_<T, Count - 1, Function, Function<T, Current>::result, Elements ..., Current>
{};
template <typename T, template <typename, T> class Function, T Current, T ... Elements>
struct Array_<T, 0, Function, Current, Elements...>
{
constexpr static std::array<T, sizeof...(Elements)> array = {{Elements ...}};
};
template <typename T, size_t Count, T Start = T(), template <typename, T> class Function = Null>
struct Array: public Array_<T, Count, Function, Start>
{};
Here, the last one is the one you'll use, using a Template Metaprogramming functor that tells the compiler how to generate the next element from the previous one. This is a limitation, but it's the best I could come up with at the time.
Three simple functors that you could use:
template <typename T, T Value>
struct Null
{
enum { result = Value };
};
template <typename T, T Value>
struct Increment
{
enum { result = Value + 1 };
};
template <typename T, T Value>
struct Decrement
{
enum { result = Value - 1 };
};
For example, if you need an array with incremental values from 1 to 100, you would do this:
std::array<int, 100> arr = Array<int, 100, 1, Increment>::array;
This array is then allocated and populated at compile-time.